NR 507 FINAL EXAM PREP - CHAMBERLAIN PATHOPHYSIOLOGY (2026/2027) Actual Questions and Answers - Verified
NR 507 Final Exam Prep (2026/2027)
Chamberlain Pathophysiology - Actual Questions and Answers
Advanced Pathophysiology Final Examination - Verified Answers (PDF)
EXAM INSTRUCTIONS: This comprehensive 145-question examination covers all ten competency
domains of the Chamberlain NR 507 Advanced Pathophysiology course, aligned with the 2026/2027
curriculum. Questions test recall of pathophysiologic mechanisms, application of cellular and systemic
concepts to clinical scenarios, and analysis of multisystem disorders. Each question has ONE correct
answer (A, B, C, or D). After each question, the correct answer and a detailed rationale citing cellular
mechanisms, pathophysiologic processes, compensatory responses, and clinical correlations are provided.
Total exam length: 145 questions across 10 sections. Recommended completion time: 3 hours.
SECTION 1: Cellular Biology, Genetics, and Altered Cellular Function
Cellular adaptation, injury, death (necrosis vs. apoptosis), genetic disorders, and inheritance patterns.
Q1: A 68-year-old male with chronic GERD undergoes endoscopy revealing intestinal-type
columnar epithelium replacing the normal squamous epithelium in the distal esophagus. This
cellular adaptation is BEST described as:
A. Hyperplasia
B. Metaplasia (reversible replacement of one differentiated cell type with another) [CORRECT]
C. Dysplasia
D. Anaplasia
Correct Answer: B
Rationale: Metaplasia is the reversible replacement of one adult cell type with another, often an adaptive
substitution of cells sensitive to stress with cells better able to withstand the adverse environment. In Barrett
esophagus, chronic acid exposure causes squamous epithelium to be replaced by intestinal-type columnar
epithelium. Hyperplasia is increased cell number; dysplasia is disordered growth; anaplasia is lack of
differentiation (malignancy). NR 507 emphasizes distinguishing adaptive from pre-malignant changes.
Q2: A patient's heart muscle increases in size due to chronic hypertension. This cellular
adaptation is called:
A. Hyperplasia
B. Hypertrophy (increase in cell size, occurring in cells unable to divide) [CORRECT]
C. Atrophy
D. Metaplasia
Correct Answer: B
Rationale: Hypertrophy is an increase in cell SIZE, occurring in tissues (like cardiac and skeletal muscle)
composed of cells that cannot divide (terminally differentiated). The increased workload from chronic
hypertension forces myocardial cells to enlarge to generate greater contractile force. Hyperplasia is increased
cell NUMBER; atrophy is shrinkage; metaplasia is cell type replacement. NR 507 emphasizes that cardiac
muscle undergoes hypertrophy, not hyperplasia, in response to stress.
Q3: A pathologist examining a tissue specimen notes cell swelling, vacuolation, and nuclear
changes including pyknosis (nuclear condensation). These findings are MOST consistent with:
Chamberlain NR 507 Advanced Pathophysiology - Final Exam Prep Page 1
,NR 507 FINAL EXAM PREP - CHAMBERLAIN PATHOPHYSIOLOGY (2026/2027) Actual Questions and Answers - Verified
A. Apoptosis
B. Reversible cell injury (early ischemic change) [CORRECT]
C. Necrosis (late cell death with inflammation)
D. Metaplasia
Correct Answer: B
Rationale: Cellular swelling (hydropic change) and vacuolation are hallmarks of REVERSIBLE cell injury - early
ischemic/hypoxic changes that can resolve if oxygenation is restored. Pyknosis (chromatin condensation) may
be present early. Necrosis is characterized by cell membrane rupture, inflammation, and progressive nuclear
changes (pyknosis → karyorrhexis → karyolysis) with surrounding inflammation. Apoptosis is programmed,
controlled cell death without inflammation. NR 507 emphasizes the progression from reversible to irreversible
injury.
Q4: Which of the following BEST distinguishes apoptosis from necrosis?
A. Apoptosis involves cell swelling; necrosis involves cell shrinkage.
B. Apoptosis is programmed cell death requiring energy (ATP), with cell shrinkage, chromatin
condensation, and no inflammation; necrosis is uncontrolled cell death with cell swelling, membrane
rupture, and significant inflammation. [CORRECT]
C. Apoptosis always causes inflammation; necrosis never does.
D. Apoptosis occurs only in pathological conditions.
Correct Answer: B
Rationale: Apoptosis is energy-dependent (ATP-required) programmed cell death: cell shrinkage, chromatin
condensation, membrane blebbing, formation of apoptotic bodies, and NO inflammation (cells are quietly
phagocytosed). Necrosis is uncontrolled cell death: cell swelling, membrane rupture, contents spill into
extracellular space, significant inflammation. Apoptosis can be physiologic (development) or pathologic (DNA
damage). NR 507 tests this distinction as a high-yield exam concept.
Q5: A 25-year-old female presents with bilateral breast masses that enlarge during the menstrual
cycle and regress afterward. Biopsy shows increased number of normal-appearing cells. This is an
example of:
A. Hypertrophy
B. Hyperplasia (hormone-induced increase in cell number) [CORRECT]
C. Metaplasia
D. Neoplasia
Correct Answer: B
Rationale: Hyperplasia is an increase in cell NUMBER in response to hormonal stimulation or growth factors.
Hormone-induced breast tissue changes during the menstrual cycle represent physiologic hyperplasia.
Hypertrophy is increased cell size; metaplasia is cell type replacement; neoplasia is uncontrolled new growth
(cancer). NR 507 distinguishes physiologic from pathologic hyperplasia.
Q6: A 75-year-old patient has prolonged bedrest after a hip fracture. The affected leg muscles
decrease in size. This cellular change is called:
A. Atrophy (decrease in cell size due to decreased workload/disuse) [CORRECT]
B. Hypertrophy
C. Metaplasia
D. Aplasia
Correct Answer: A
Chamberlain NR 507 Advanced Pathophysiology - Final Exam Prep Page 2
,NR 507 FINAL EXAM PREP - CHAMBERLAIN PATHOPHYSIOLOGY (2026/2027) Actual Questions and Answers - Verified
Rationale: Atrophy is a decrease in cell SIZE due to decreased workload (disuse), decreased blood supply, loss
of innervation, inadequate nutrition, or loss of hormonal stimulation. Prolonged bedrest causes disuse atrophy of
skeletal muscles. Hypertrophy is enlargement; metaplasia is cell type replacement; aplasia is absence of cell
development. NR 507 emphasizes that atrophy is a reversible adaptive response.
Q7: A Pap smear shows cells with disordered growth, increased nuclear-cytoplasmic ratio, and
pleomorphism, but the changes do not extend through the full thickness of the epithelium. This is
BEST classified as:
A. Metaplasia
B. Dysplasia (disordered, atypical cell growth that may progress to neoplasia) [CORRECT]
C. Anaplasia
D. Hyperplasia
Correct Answer: B
Rationale: Dysplasia is abnormal, disordered cell growth with atypical features (pleomorphism, hyperchromatic
nuclei, increased nuclear-cytoplasmic ratio, increased mitoses) but confined to the epithelial layers. It is a
pre-malignant change that may regress or progress to carcinoma in situ and invasive cancer. Metaplasia is
reversible cell type substitution; anaplasia is lack of differentiation (malignancy); hyperplasia is increased cell
number. NR 507 emphasizes dysplasia as a precursor to cancer.
Q8: A child is born with cystic fibrosis. The genetic basis is MOST accurately described as:
A. Autosomal dominant inheritance
B. Autosomal recessive inheritance with a mutation in the CFTR gene causing defective chloride channels
[CORRECT]
C. X-linked recessive inheritance
D. Mitochondrial inheritance
Correct Answer: B
Rationale: Cystic fibrosis is an autosomal recessive disorder caused by mutations in the CFTR gene
(chromosome 7) encoding a chloride channel. The most common mutation is delta-F508. Defective chloride
transport leads to thick, dehydrated mucus in lungs, pancreas, and other organs. Autosomal recessive
inheritance requires both parents to be carriers (25% chance of affected child). NR 507 tests genetic inheritance
patterns and their clinical implications.
Q9: A 35-year-old male presents with Huntington disease. The inheritance pattern and genetic
mechanism is BEST described as:
A. Autosomal recessive with trinucleotide repeat expansion
B. Autosomal dominant with CAG trinucleotide repeat expansion in the HTT gene, demonstrating
anticipation [CORRECT]
C. X-linked recessive
D. Mitochondrial inheritance
Correct Answer: B
Rationale: Huntington disease is autosomal dominant with CAG trinucleotide repeat expansion in the HTT gene
(chromosome 4). It demonstrates anticipation - symptoms appear earlier and more severely in successive
generations as the repeat expands. Symptoms typically begin in mid-life (30s-50s) with chorea, cognitive
decline, and psychiatric disturbances. Autosomal dominant inheritance means each child of an affected parent
has a 50% risk. NR 507 tests trinucleotide repeat disorders (Huntington, fragile X, myotonic dystrophy).
Chamberlain NR 507 Advanced Pathophysiology - Final Exam Prep Page 3
, NR 507 FINAL EXAM PREP - CHAMBERLAIN PATHOPHYSIOLOGY (2026/2027) Actual Questions and Answers - Verified
Q10: A 24-year-old African American male presents with severe painful episodes, jaundice, and
anemia. Peripheral smear shows sickled red blood cells. The underlying genetic mechanism is:
A. Frameshift mutation causing truncated hemoglobin
B. Point mutation (single nucleotide substitution: glutamic acid → valine at position 6 of beta-globin chain)
- autosomal recessive [CORRECT]
C. Trinucleotide repeat expansion
D. Chromosomal translocation
Correct Answer: B
Rationale: Sickle cell disease results from a single point mutation in the beta-globin gene (HBB) on
chromosome 11, substituting valine for glutamic acid at position 6, producing hemoglobin S (HbS). Under low
oxygen conditions, HbS polymerizes, causing RBCs to sickle. Autosomal recessive inheritance; sickle cell trait
(heterozygous) provides malaria resistance. NR 507 tests point mutations and their clinical consequences.
Q11: A 40-year-old female presents with multiple café-au-lait spots, neurofibromas, and Lisch
nodules. Her father had similar findings. The inheritance pattern is:
A. Autosomal recessive
B. Autosomal dominant (NF1 gene mutation, each child has 50% risk) [CORRECT]
C. X-linked recessive
D. Multifactorial inheritance
Correct Answer: B
Rationale: Neurofibromatosis type 1 (von Recklinghausen disease) is autosomal dominant, caused by
mutations in the NF1 gene (chromosome 17) encoding neurofibromin (a tumor suppressor). Features include
café-au-lait spots, neurofibromas, Lisch nodules (iris hamartomas), and optic gliomas. Each child of an affected
parent has a 50% risk. About 50% of cases are new mutations. NR 507 tests autosomal dominant disorders and
tumor suppressor genes.
Q12: A 28-year-old male presents with severe recurrent infections. Genetic testing reveals a defect
in the BTK gene on the X chromosome, leading to absent B cells and very low immunoglobulin
levels. The inheritance pattern and condition is:
A. Autosomal recessive; severe combined immunodeficiency
B. X-linked recessive; X-linked agammaglobulinemia (Bruton disease) [CORRECT]
C. Autosomal dominant; DiGeorge syndrome
D. Mitochondrial inheritance
Correct Answer: B
Rationale: X-linked agammaglobulinemia (Bruton disease) is X-linked recessive, caused by mutations in the
BTK gene on the X chromosome. B cells fail to mature, leading to absent immunoglobulins and recurrent
bacterial infections. Males are affected; females are carriers. Symptoms begin after 6 months of age as maternal
antibodies wane. NR 507 tests X-linked recessive inheritance patterns and immunodeficiency mechanisms.
Q13: A patient with Type 2 diabetes, cardiovascular disease, and family history of early-onset MI in
multiple relatives represents which type of inheritance?
A. Single-gene (Mendelian) inheritance
B. Multifactorial inheritance (multiple genes + environmental factors) [CORRECT]
C. Mitochondrial inheritance
D. X-linked dominant
Correct Answer: B
Chamberlain NR 507 Advanced Pathophysiology - Final Exam Prep Page 4
NR 507 Final Exam Prep (2026/2027)
Chamberlain Pathophysiology - Actual Questions and Answers
Advanced Pathophysiology Final Examination - Verified Answers (PDF)
EXAM INSTRUCTIONS: This comprehensive 145-question examination covers all ten competency
domains of the Chamberlain NR 507 Advanced Pathophysiology course, aligned with the 2026/2027
curriculum. Questions test recall of pathophysiologic mechanisms, application of cellular and systemic
concepts to clinical scenarios, and analysis of multisystem disorders. Each question has ONE correct
answer (A, B, C, or D). After each question, the correct answer and a detailed rationale citing cellular
mechanisms, pathophysiologic processes, compensatory responses, and clinical correlations are provided.
Total exam length: 145 questions across 10 sections. Recommended completion time: 3 hours.
SECTION 1: Cellular Biology, Genetics, and Altered Cellular Function
Cellular adaptation, injury, death (necrosis vs. apoptosis), genetic disorders, and inheritance patterns.
Q1: A 68-year-old male with chronic GERD undergoes endoscopy revealing intestinal-type
columnar epithelium replacing the normal squamous epithelium in the distal esophagus. This
cellular adaptation is BEST described as:
A. Hyperplasia
B. Metaplasia (reversible replacement of one differentiated cell type with another) [CORRECT]
C. Dysplasia
D. Anaplasia
Correct Answer: B
Rationale: Metaplasia is the reversible replacement of one adult cell type with another, often an adaptive
substitution of cells sensitive to stress with cells better able to withstand the adverse environment. In Barrett
esophagus, chronic acid exposure causes squamous epithelium to be replaced by intestinal-type columnar
epithelium. Hyperplasia is increased cell number; dysplasia is disordered growth; anaplasia is lack of
differentiation (malignancy). NR 507 emphasizes distinguishing adaptive from pre-malignant changes.
Q2: A patient's heart muscle increases in size due to chronic hypertension. This cellular
adaptation is called:
A. Hyperplasia
B. Hypertrophy (increase in cell size, occurring in cells unable to divide) [CORRECT]
C. Atrophy
D. Metaplasia
Correct Answer: B
Rationale: Hypertrophy is an increase in cell SIZE, occurring in tissues (like cardiac and skeletal muscle)
composed of cells that cannot divide (terminally differentiated). The increased workload from chronic
hypertension forces myocardial cells to enlarge to generate greater contractile force. Hyperplasia is increased
cell NUMBER; atrophy is shrinkage; metaplasia is cell type replacement. NR 507 emphasizes that cardiac
muscle undergoes hypertrophy, not hyperplasia, in response to stress.
Q3: A pathologist examining a tissue specimen notes cell swelling, vacuolation, and nuclear
changes including pyknosis (nuclear condensation). These findings are MOST consistent with:
Chamberlain NR 507 Advanced Pathophysiology - Final Exam Prep Page 1
,NR 507 FINAL EXAM PREP - CHAMBERLAIN PATHOPHYSIOLOGY (2026/2027) Actual Questions and Answers - Verified
A. Apoptosis
B. Reversible cell injury (early ischemic change) [CORRECT]
C. Necrosis (late cell death with inflammation)
D. Metaplasia
Correct Answer: B
Rationale: Cellular swelling (hydropic change) and vacuolation are hallmarks of REVERSIBLE cell injury - early
ischemic/hypoxic changes that can resolve if oxygenation is restored. Pyknosis (chromatin condensation) may
be present early. Necrosis is characterized by cell membrane rupture, inflammation, and progressive nuclear
changes (pyknosis → karyorrhexis → karyolysis) with surrounding inflammation. Apoptosis is programmed,
controlled cell death without inflammation. NR 507 emphasizes the progression from reversible to irreversible
injury.
Q4: Which of the following BEST distinguishes apoptosis from necrosis?
A. Apoptosis involves cell swelling; necrosis involves cell shrinkage.
B. Apoptosis is programmed cell death requiring energy (ATP), with cell shrinkage, chromatin
condensation, and no inflammation; necrosis is uncontrolled cell death with cell swelling, membrane
rupture, and significant inflammation. [CORRECT]
C. Apoptosis always causes inflammation; necrosis never does.
D. Apoptosis occurs only in pathological conditions.
Correct Answer: B
Rationale: Apoptosis is energy-dependent (ATP-required) programmed cell death: cell shrinkage, chromatin
condensation, membrane blebbing, formation of apoptotic bodies, and NO inflammation (cells are quietly
phagocytosed). Necrosis is uncontrolled cell death: cell swelling, membrane rupture, contents spill into
extracellular space, significant inflammation. Apoptosis can be physiologic (development) or pathologic (DNA
damage). NR 507 tests this distinction as a high-yield exam concept.
Q5: A 25-year-old female presents with bilateral breast masses that enlarge during the menstrual
cycle and regress afterward. Biopsy shows increased number of normal-appearing cells. This is an
example of:
A. Hypertrophy
B. Hyperplasia (hormone-induced increase in cell number) [CORRECT]
C. Metaplasia
D. Neoplasia
Correct Answer: B
Rationale: Hyperplasia is an increase in cell NUMBER in response to hormonal stimulation or growth factors.
Hormone-induced breast tissue changes during the menstrual cycle represent physiologic hyperplasia.
Hypertrophy is increased cell size; metaplasia is cell type replacement; neoplasia is uncontrolled new growth
(cancer). NR 507 distinguishes physiologic from pathologic hyperplasia.
Q6: A 75-year-old patient has prolonged bedrest after a hip fracture. The affected leg muscles
decrease in size. This cellular change is called:
A. Atrophy (decrease in cell size due to decreased workload/disuse) [CORRECT]
B. Hypertrophy
C. Metaplasia
D. Aplasia
Correct Answer: A
Chamberlain NR 507 Advanced Pathophysiology - Final Exam Prep Page 2
,NR 507 FINAL EXAM PREP - CHAMBERLAIN PATHOPHYSIOLOGY (2026/2027) Actual Questions and Answers - Verified
Rationale: Atrophy is a decrease in cell SIZE due to decreased workload (disuse), decreased blood supply, loss
of innervation, inadequate nutrition, or loss of hormonal stimulation. Prolonged bedrest causes disuse atrophy of
skeletal muscles. Hypertrophy is enlargement; metaplasia is cell type replacement; aplasia is absence of cell
development. NR 507 emphasizes that atrophy is a reversible adaptive response.
Q7: A Pap smear shows cells with disordered growth, increased nuclear-cytoplasmic ratio, and
pleomorphism, but the changes do not extend through the full thickness of the epithelium. This is
BEST classified as:
A. Metaplasia
B. Dysplasia (disordered, atypical cell growth that may progress to neoplasia) [CORRECT]
C. Anaplasia
D. Hyperplasia
Correct Answer: B
Rationale: Dysplasia is abnormal, disordered cell growth with atypical features (pleomorphism, hyperchromatic
nuclei, increased nuclear-cytoplasmic ratio, increased mitoses) but confined to the epithelial layers. It is a
pre-malignant change that may regress or progress to carcinoma in situ and invasive cancer. Metaplasia is
reversible cell type substitution; anaplasia is lack of differentiation (malignancy); hyperplasia is increased cell
number. NR 507 emphasizes dysplasia as a precursor to cancer.
Q8: A child is born with cystic fibrosis. The genetic basis is MOST accurately described as:
A. Autosomal dominant inheritance
B. Autosomal recessive inheritance with a mutation in the CFTR gene causing defective chloride channels
[CORRECT]
C. X-linked recessive inheritance
D. Mitochondrial inheritance
Correct Answer: B
Rationale: Cystic fibrosis is an autosomal recessive disorder caused by mutations in the CFTR gene
(chromosome 7) encoding a chloride channel. The most common mutation is delta-F508. Defective chloride
transport leads to thick, dehydrated mucus in lungs, pancreas, and other organs. Autosomal recessive
inheritance requires both parents to be carriers (25% chance of affected child). NR 507 tests genetic inheritance
patterns and their clinical implications.
Q9: A 35-year-old male presents with Huntington disease. The inheritance pattern and genetic
mechanism is BEST described as:
A. Autosomal recessive with trinucleotide repeat expansion
B. Autosomal dominant with CAG trinucleotide repeat expansion in the HTT gene, demonstrating
anticipation [CORRECT]
C. X-linked recessive
D. Mitochondrial inheritance
Correct Answer: B
Rationale: Huntington disease is autosomal dominant with CAG trinucleotide repeat expansion in the HTT gene
(chromosome 4). It demonstrates anticipation - symptoms appear earlier and more severely in successive
generations as the repeat expands. Symptoms typically begin in mid-life (30s-50s) with chorea, cognitive
decline, and psychiatric disturbances. Autosomal dominant inheritance means each child of an affected parent
has a 50% risk. NR 507 tests trinucleotide repeat disorders (Huntington, fragile X, myotonic dystrophy).
Chamberlain NR 507 Advanced Pathophysiology - Final Exam Prep Page 3
, NR 507 FINAL EXAM PREP - CHAMBERLAIN PATHOPHYSIOLOGY (2026/2027) Actual Questions and Answers - Verified
Q10: A 24-year-old African American male presents with severe painful episodes, jaundice, and
anemia. Peripheral smear shows sickled red blood cells. The underlying genetic mechanism is:
A. Frameshift mutation causing truncated hemoglobin
B. Point mutation (single nucleotide substitution: glutamic acid → valine at position 6 of beta-globin chain)
- autosomal recessive [CORRECT]
C. Trinucleotide repeat expansion
D. Chromosomal translocation
Correct Answer: B
Rationale: Sickle cell disease results from a single point mutation in the beta-globin gene (HBB) on
chromosome 11, substituting valine for glutamic acid at position 6, producing hemoglobin S (HbS). Under low
oxygen conditions, HbS polymerizes, causing RBCs to sickle. Autosomal recessive inheritance; sickle cell trait
(heterozygous) provides malaria resistance. NR 507 tests point mutations and their clinical consequences.
Q11: A 40-year-old female presents with multiple café-au-lait spots, neurofibromas, and Lisch
nodules. Her father had similar findings. The inheritance pattern is:
A. Autosomal recessive
B. Autosomal dominant (NF1 gene mutation, each child has 50% risk) [CORRECT]
C. X-linked recessive
D. Multifactorial inheritance
Correct Answer: B
Rationale: Neurofibromatosis type 1 (von Recklinghausen disease) is autosomal dominant, caused by
mutations in the NF1 gene (chromosome 17) encoding neurofibromin (a tumor suppressor). Features include
café-au-lait spots, neurofibromas, Lisch nodules (iris hamartomas), and optic gliomas. Each child of an affected
parent has a 50% risk. About 50% of cases are new mutations. NR 507 tests autosomal dominant disorders and
tumor suppressor genes.
Q12: A 28-year-old male presents with severe recurrent infections. Genetic testing reveals a defect
in the BTK gene on the X chromosome, leading to absent B cells and very low immunoglobulin
levels. The inheritance pattern and condition is:
A. Autosomal recessive; severe combined immunodeficiency
B. X-linked recessive; X-linked agammaglobulinemia (Bruton disease) [CORRECT]
C. Autosomal dominant; DiGeorge syndrome
D. Mitochondrial inheritance
Correct Answer: B
Rationale: X-linked agammaglobulinemia (Bruton disease) is X-linked recessive, caused by mutations in the
BTK gene on the X chromosome. B cells fail to mature, leading to absent immunoglobulins and recurrent
bacterial infections. Males are affected; females are carriers. Symptoms begin after 6 months of age as maternal
antibodies wane. NR 507 tests X-linked recessive inheritance patterns and immunodeficiency mechanisms.
Q13: A patient with Type 2 diabetes, cardiovascular disease, and family history of early-onset MI in
multiple relatives represents which type of inheritance?
A. Single-gene (Mendelian) inheritance
B. Multifactorial inheritance (multiple genes + environmental factors) [CORRECT]
C. Mitochondrial inheritance
D. X-linked dominant
Correct Answer: B
Chamberlain NR 507 Advanced Pathophysiology - Final Exam Prep Page 4
