NR 507 Advanced Pathophysiology Final Exam Page 1
Final Exam: NR 507 / NR507 (Latest 2026/2027 Update)
Advanced Pathophysiology Guide
Questions and Answers | Grade A | 100% Correct (Verified Solutions)
Chamberlain University | Comprehensive 150-Question Exam Review
Section 1: Cellular Adaptation, Injury, and Neoplasia (Q1-25)
Q1: A 68-year-old patient with a 15-year history of hypertension presents with dyspnea on exertion. Echocardiography
reveals left ventricular wall thickening with a mass-to-volume ratio significantly above normal. Which cellular adaptation
best explains this finding?
A. Hyperplasia
B. Hypertrophy [CORRECT]
C. Metaplasia
D. Atrophy
Correct Answer: B
Rationale: Hypertrophy is an increase in individual cell size due to increased workload, commonly seen in myocardial cells exposed to chronic pressure
overload from hypertension. Hyperplasia involves an increase in cell number, not size. Metaplasia is a reversible replacement of one cell type with
another. Atrophy is a decrease in cell size due to reduced workload, blood supply, or innervation.
Q2: A 55-year-old woman with chronic GERD undergoes endoscopy, and biopsy reveals columnar epithelium replacing the
normal stratified squamous epithelium in the distal esophagus. Which cellular adaptation is demonstrated?
A. Dysplasia
B. Hyperplasia
C. Metaplasia [CORRECT]
D. Anaplasia
Correct Answer: C
Rationale: Barrett esophagus is the classic example of metaplasia, where chronic acid exposure causes reversible replacement of stratified squamous
epithelium with intestinal-type columnar epithelium. Dysplasia refers to abnormal cell growth with nuclear atypia and is considered a pre-neoplastic
change. Hyperplasia is an increase in cell number. Anaplasia refers to undifferentiated tumor cells.
Q3: A 72-year-old male with a history of cerebral artery occlusion presents with weakness in his right upper extremity.
Muscle biopsy reveals a reduction in the size of individual muscle fibers. Which process is responsible?
A. Hypertrophy
B. Metaplasia
C. Atrophy due to denervation [CORRECT]
D. Hyperplasia due to hormonal stimulation
Correct Answer: C
Rationale: Disuse atrophy occurs when cells experience decreased workload, loss of innervation, diminished blood supply, or inadequate nutrition. In
this case, the cerebral artery occlusion led to upper motor neuron injury and subsequent denervation atrophy of the affected muscles. Hypertrophy
increases cell size, not decreases it. Metaplasia changes cell type. Hyperplasia increases cell number.
Q4: A 45-year-old woman presents with menorrhagia. Endometrial biopsy reveals an increase in the number of
endometrial glands with crowded, irregular architecture but no cytologic atypia. Which cellular adaptation is most likely?
A. Hyperplasia [CORRECT]
B. Hypertrophy
C. Metaplasia
D. Dysplasia
,NR 507 Advanced Pathophysiology Final Exam Page 2
Correct Answer: A
Rationale: Endometrial hyperplasia is caused by unopposed estrogen stimulation, leading to an increase in the number of endometrial glands and
stroma. The key distinction from dysplasia is the absence of cellular atypia. Hypertrophy involves increased cell size, not number. Metaplasia involves a
change in cell type, not an increase in gland number. Dysplasia would show nuclear atypia.
Q5: A cervical biopsy from a 32-year-old woman reveals disorganized epithelial cells with nuclear hyperchromasia,
pleomorphism, and abnormal mitotic figures. The basement membrane is intact. Which of the following best describes this
finding?
A. Metaplasia
B. Dysplasia [CORRECT]
C. Anaplasia
D. Hyperplasia
Correct Answer: B
Rationale: Dysplasia is characterized by abnormal cell growth with disorganized architecture, nuclear atypia (hyperchromasia, pleomorphism), and
abnormal mitoses, but the basement membrane remains intact, distinguishing it from invasive carcinoma. Metaplasia is a change in cell type without
atypia. Anaplasia refers to undifferentiated malignant cells. Hyperplasia increases cell number without atypia.
Q6: A 60-year-old patient with a myocardial infarction exhibits pale, firm myocardial tissue with coagulative necrosis on
histology. Which of the following best explains why the myocardium undergoes coagulative necrosis rather than
liquefactive necrosis?
A. The heart has a rich blood supply that prevents liquefaction
B. Myocardial cells have high lysosomal enzyme activity
C. Myocardial cells are rich in protein but low in hydrolytic enzymes [CORRECT]
D. The infarct is caused by ischemia rather than infection
Correct Answer: C
Rationale: Coagulative necrosis occurs in tissues with low lysosomal enzyme content and high protein, such as the heart, kidneys, and spleen. The
denatured structural proteins maintain the tissue architecture even after cell death. Liquefactive necrosis occurs in the brain due to high lysosomal
enzyme content and lipid-rich tissue. The mechanism of injury (ischemia vs infection) is not the primary determinant of necrosis type.
Q7: A 35-year-old patient presents with fever, malaise, and a swollen, tender right great toe. Aspiration reveals cloudy
synovial fluid with numerous neutrophils but no organisms on Gram stain. Which type of necrosis is most likely present in
this joint?
A. Coagulative necrosis
B. Liquefactive necrosis [CORRECT]
C. Caseous necrosis
D. Fat necrosis
Correct Answer: B
Rationale: Liquefactive necrosis is characterized by enzymatic degradation of dead cells into a liquid, viscous mass. It typically occurs in the brain and
in abscesses or suppurative infections where neutrophils release hydrolytic enzymes. The clinical scenario of acute inflammatory arthritis with
neutrophil-predominant fluid is consistent with liquefactive necrosis within the joint. Coagulative necrosis preserves tissue architecture. Caseous necrosis
is seen in tuberculosis. Fat necrosis involves adipose tissue with saponification.
Q8: A nurse practitioner is teaching a graduate class about cellular injury. Which of the following is the FIRST
biochemical change that occurs in a cell subjected to ischemic injury?
A. Influx of calcium into the cytoplasm
B. Decreased ATP production [CORRECT]
C. Activation of caspase enzymes
D. Rupture of the plasma membrane
Correct Answer: B
Rationale: Decreased ATP production is the earliest biochemical change in ischemic injury because oxygen deprivation halts oxidative phosphorylation.
This leads to failure of the sodium-potassium pump, causing sodium accumulation in the cell and subsequent cellular swelling. Calcium influx occurs
later as ATP-dependent calcium pumps fail. Caspase activation is part of apoptosis, not the initial ischemic injury. Membrane rupture is a late event in
,NR 507 Advanced Pathophysiology Final Exam Page 3
necrosis.
Q9: A 4-year-old child of Ashkenazi Jewish descent presents with developmental regression, cherry-red macula, and
hyperreflexia. Genetic testing confirms hexosaminidase A deficiency. Which cellular process is most impaired in this
condition?
A. Necrosis
B. Apoptosis
C. Autophagy
D. Programmed cell death with defective enzyme degradation [CORRECT]
Correct Answer: D
Rationale: Tay-Sachs disease is caused by a deficiency of hexosaminidase A, leading to accumulation of GM2 ganglioside in neurons. The disease
represents a defect in the lysosomal degradation pathway, where programmed cell death (apoptosis) mechanisms are impaired because the accumulated
substrate cannot be cleared. The cherry-red macula is a classic finding. While apoptosis is a form of programmed cell death, the defect here is
specifically in lysosomal enzyme function, not the apoptosis signaling cascade itself.
Q10: A 50-year-old patient with a long-standing history of smoking presents with a chronic cough and weight loss.
Bronchoscopy reveals a central lung mass. Biopsy shows small cells with scant cytoplasm, granular chromatin, and absent
nucleoli. Which of the following terms best describes the degree of cellular differentiation in this tumor?
A. Well-differentiated
B. Moderately differentiated
C. Anaplastic [CORRECT]
D. Dysplastic
Correct Answer: C
Rationale: Small cell lung carcinoma is a classic example of an anaplastic (poorly differentiated) tumor. Anaplastic cells have little resemblance to their
tissue of origin, with scant cytoplasm, hyperchromatic nuclei, and absent nucleoli. Well-differentiated tumors closely resemble the parent tissue.
Moderately differentiated tumors show intermediate features. Dysplasia is a pre-malignant change, not a tumor classification.
Q11: A 62-year-old woman with breast cancer is started on tamoxifen. The nurse practitioner explains that tamoxifen acts
as an antagonist in breast tissue but may have agonist effects in the endometrium. This dual action is an example of which
pharmacologic concept?
A. Down-regulation of estrogen receptors
B. Selective estrogen receptor modulation [CORRECT]
C. Competitive inhibition of aromatase
D. Irreversible receptor binding
Correct Answer: B
Rationale: Selective estrogen receptor modulators (SERMs) like tamoxifen have tissue-specific effects, acting as antagonists in breast tissue (blocking
estrogen-driven proliferation) but as agonists in other tissues such as the endometrium (increasing risk of endometrial hyperplasia and carcinoma). This
is not down-regulation, competitive inhibition of aromatase (which is the mechanism of anastrozole), or irreversible binding.
Q12: A pathologist examines a tissue specimen and notes cells with shrinkage, chromatin condensation (pyknosis), nuclear
fragmentation (karyorrhexis), and formation of cytoplasmic blebs without an inflammatory response. Which of the
following processes is occurring?
A. Coagulative necrosis
B. Liquefactive necrosis
C. Apoptosis [CORRECT]
D. Caseous necrosis
Correct Answer: C
Rationale: Apoptosis is programmed cell death characterized by cell shrinkage, chromatin condensation, nuclear fragmentation, and formation of
apoptotic bodies, all without eliciting an inflammatory response. This distinguishes it from necrosis, which involves cell swelling, membrane rupture, and
inflammation. Coagulative and liquefactive necrosis are forms of cell death that trigger inflammation. Caseous necrosis is a specific pattern seen in
tuberculosis.
, NR 507 Advanced Pathophysiology Final Exam Page 4
Q13: A 28-year-old patient with a diagnosed BRCA1 mutation asks about her risk of ovarian cancer. The nurse
practitioner explains that BRCA1 is classified as which type of gene?
A. Proto-oncogene
B. Tumor suppressor gene [CORRECT]
C. Oncogene
D. Telomerase gene
Correct Answer: B
Rationale: BRCA1 is a tumor suppressor gene that plays a critical role in DNA repair through homologous recombination. Mutations in BRCA1 lead to
defective DNA repair, accumulation of genetic damage, and increased risk of breast and ovarian cancers. Proto-oncogenes are normal genes that
promote cell growth; when mutated, they become oncogenes. Oncogenes promote uncontrolled proliferation. Telomerase genes maintain telomere length
and are often reactivated in cancer cells.
Q14: A 48-year-old male presents with a painless neck mass. Biopsy reveals a tumor with papillary architecture and nuclear
features including grooves, overlapping, and pseudoinclusions. Fine psammoma bodies are present. Which of the following
is the most likely diagnosis?
A. Follicular thyroid carcinoma
B. Medullary thyroid carcinoma
C. Papillary thyroid carcinoma [CORRECT]
D. Anaplastic thyroid carcinoma
Correct Answer: C
Rationale: Papillary thyroid carcinoma is the most common thyroid malignancy and is characterized by papillary architecture, nuclear grooves,
overlapping nuclei, nuclear pseudoinclusions, and psammoma bodies (calcified concretions). Follicular carcinoma shows follicular architecture without
these nuclear features. Medullary carcinoma arises from parafollicular C cells and is associated with amyloid stroma. Anaplastic carcinoma is highly
undifferentiated with a very poor prognosis.
Q15: A research study demonstrates that a particular chemotherapeutic agent triggers cytochrome c release from
mitochondria, activation of caspase-9, and subsequent DNA fragmentation. Which cellular process is being induced?
A. Necrosis
B. The intrinsic pathway of apoptosis [CORRECT]
C. The extrinsic pathway of apoptosis
D. Autophagic cell death
Correct Answer: B
Rationale: The intrinsic (mitochondrial) pathway of apoptosis is triggered by intracellular stress signals such as DNA damage, leading to mitochondrial
outer membrane permeabilization and cytochrome c release. Cytochrome c forms the apoptosome with Apaf-1 and caspase-9, activating the caspase
cascade. The extrinsic pathway is initiated by death receptor binding (e.g., FasL, TNF) and activates caspase-8. Necrosis does not involve caspase
activation. Autophagic cell death involves lysosomal degradation.
Q16: A 65-year-old patient with a diagnosed malignant tumor has elevated levels of oncofetal antigens detected in the
blood. Which of the following is an example of an oncofetal antigen used as a tumor marker?
A. BRCA1 protein
B. Carcinoembryonic antigen (CEA) [CORRECT]
C. Epidermal growth factor receptor
D. p53 protein
Correct Answer: B
Rationale: Carcinoembryonic antigen (CEA) is an oncofetal antigen normally expressed during fetal development that is re-expressed in certain
malignancies, particularly colorectal cancer. It is used as a tumor marker for monitoring disease progression and treatment response. BRCA1 is a tumor
suppressor protein, not an oncofetal antigen. EGFR is a receptor tyrosine kinase that can be overexpressed or mutated in cancers. p53 is a tumor
suppressor protein mutated in many cancers.
Q17: A 70-year-old patient with prostate cancer has bone metastases. The nurse practitioner explains that the tumor cells
produce which substance that promotes bone resorption in osteolytic metastases?
A. Osteoprotegerin
Final Exam: NR 507 / NR507 (Latest 2026/2027 Update)
Advanced Pathophysiology Guide
Questions and Answers | Grade A | 100% Correct (Verified Solutions)
Chamberlain University | Comprehensive 150-Question Exam Review
Section 1: Cellular Adaptation, Injury, and Neoplasia (Q1-25)
Q1: A 68-year-old patient with a 15-year history of hypertension presents with dyspnea on exertion. Echocardiography
reveals left ventricular wall thickening with a mass-to-volume ratio significantly above normal. Which cellular adaptation
best explains this finding?
A. Hyperplasia
B. Hypertrophy [CORRECT]
C. Metaplasia
D. Atrophy
Correct Answer: B
Rationale: Hypertrophy is an increase in individual cell size due to increased workload, commonly seen in myocardial cells exposed to chronic pressure
overload from hypertension. Hyperplasia involves an increase in cell number, not size. Metaplasia is a reversible replacement of one cell type with
another. Atrophy is a decrease in cell size due to reduced workload, blood supply, or innervation.
Q2: A 55-year-old woman with chronic GERD undergoes endoscopy, and biopsy reveals columnar epithelium replacing the
normal stratified squamous epithelium in the distal esophagus. Which cellular adaptation is demonstrated?
A. Dysplasia
B. Hyperplasia
C. Metaplasia [CORRECT]
D. Anaplasia
Correct Answer: C
Rationale: Barrett esophagus is the classic example of metaplasia, where chronic acid exposure causes reversible replacement of stratified squamous
epithelium with intestinal-type columnar epithelium. Dysplasia refers to abnormal cell growth with nuclear atypia and is considered a pre-neoplastic
change. Hyperplasia is an increase in cell number. Anaplasia refers to undifferentiated tumor cells.
Q3: A 72-year-old male with a history of cerebral artery occlusion presents with weakness in his right upper extremity.
Muscle biopsy reveals a reduction in the size of individual muscle fibers. Which process is responsible?
A. Hypertrophy
B. Metaplasia
C. Atrophy due to denervation [CORRECT]
D. Hyperplasia due to hormonal stimulation
Correct Answer: C
Rationale: Disuse atrophy occurs when cells experience decreased workload, loss of innervation, diminished blood supply, or inadequate nutrition. In
this case, the cerebral artery occlusion led to upper motor neuron injury and subsequent denervation atrophy of the affected muscles. Hypertrophy
increases cell size, not decreases it. Metaplasia changes cell type. Hyperplasia increases cell number.
Q4: A 45-year-old woman presents with menorrhagia. Endometrial biopsy reveals an increase in the number of
endometrial glands with crowded, irregular architecture but no cytologic atypia. Which cellular adaptation is most likely?
A. Hyperplasia [CORRECT]
B. Hypertrophy
C. Metaplasia
D. Dysplasia
,NR 507 Advanced Pathophysiology Final Exam Page 2
Correct Answer: A
Rationale: Endometrial hyperplasia is caused by unopposed estrogen stimulation, leading to an increase in the number of endometrial glands and
stroma. The key distinction from dysplasia is the absence of cellular atypia. Hypertrophy involves increased cell size, not number. Metaplasia involves a
change in cell type, not an increase in gland number. Dysplasia would show nuclear atypia.
Q5: A cervical biopsy from a 32-year-old woman reveals disorganized epithelial cells with nuclear hyperchromasia,
pleomorphism, and abnormal mitotic figures. The basement membrane is intact. Which of the following best describes this
finding?
A. Metaplasia
B. Dysplasia [CORRECT]
C. Anaplasia
D. Hyperplasia
Correct Answer: B
Rationale: Dysplasia is characterized by abnormal cell growth with disorganized architecture, nuclear atypia (hyperchromasia, pleomorphism), and
abnormal mitoses, but the basement membrane remains intact, distinguishing it from invasive carcinoma. Metaplasia is a change in cell type without
atypia. Anaplasia refers to undifferentiated malignant cells. Hyperplasia increases cell number without atypia.
Q6: A 60-year-old patient with a myocardial infarction exhibits pale, firm myocardial tissue with coagulative necrosis on
histology. Which of the following best explains why the myocardium undergoes coagulative necrosis rather than
liquefactive necrosis?
A. The heart has a rich blood supply that prevents liquefaction
B. Myocardial cells have high lysosomal enzyme activity
C. Myocardial cells are rich in protein but low in hydrolytic enzymes [CORRECT]
D. The infarct is caused by ischemia rather than infection
Correct Answer: C
Rationale: Coagulative necrosis occurs in tissues with low lysosomal enzyme content and high protein, such as the heart, kidneys, and spleen. The
denatured structural proteins maintain the tissue architecture even after cell death. Liquefactive necrosis occurs in the brain due to high lysosomal
enzyme content and lipid-rich tissue. The mechanism of injury (ischemia vs infection) is not the primary determinant of necrosis type.
Q7: A 35-year-old patient presents with fever, malaise, and a swollen, tender right great toe. Aspiration reveals cloudy
synovial fluid with numerous neutrophils but no organisms on Gram stain. Which type of necrosis is most likely present in
this joint?
A. Coagulative necrosis
B. Liquefactive necrosis [CORRECT]
C. Caseous necrosis
D. Fat necrosis
Correct Answer: B
Rationale: Liquefactive necrosis is characterized by enzymatic degradation of dead cells into a liquid, viscous mass. It typically occurs in the brain and
in abscesses or suppurative infections where neutrophils release hydrolytic enzymes. The clinical scenario of acute inflammatory arthritis with
neutrophil-predominant fluid is consistent with liquefactive necrosis within the joint. Coagulative necrosis preserves tissue architecture. Caseous necrosis
is seen in tuberculosis. Fat necrosis involves adipose tissue with saponification.
Q8: A nurse practitioner is teaching a graduate class about cellular injury. Which of the following is the FIRST
biochemical change that occurs in a cell subjected to ischemic injury?
A. Influx of calcium into the cytoplasm
B. Decreased ATP production [CORRECT]
C. Activation of caspase enzymes
D. Rupture of the plasma membrane
Correct Answer: B
Rationale: Decreased ATP production is the earliest biochemical change in ischemic injury because oxygen deprivation halts oxidative phosphorylation.
This leads to failure of the sodium-potassium pump, causing sodium accumulation in the cell and subsequent cellular swelling. Calcium influx occurs
later as ATP-dependent calcium pumps fail. Caspase activation is part of apoptosis, not the initial ischemic injury. Membrane rupture is a late event in
,NR 507 Advanced Pathophysiology Final Exam Page 3
necrosis.
Q9: A 4-year-old child of Ashkenazi Jewish descent presents with developmental regression, cherry-red macula, and
hyperreflexia. Genetic testing confirms hexosaminidase A deficiency. Which cellular process is most impaired in this
condition?
A. Necrosis
B. Apoptosis
C. Autophagy
D. Programmed cell death with defective enzyme degradation [CORRECT]
Correct Answer: D
Rationale: Tay-Sachs disease is caused by a deficiency of hexosaminidase A, leading to accumulation of GM2 ganglioside in neurons. The disease
represents a defect in the lysosomal degradation pathway, where programmed cell death (apoptosis) mechanisms are impaired because the accumulated
substrate cannot be cleared. The cherry-red macula is a classic finding. While apoptosis is a form of programmed cell death, the defect here is
specifically in lysosomal enzyme function, not the apoptosis signaling cascade itself.
Q10: A 50-year-old patient with a long-standing history of smoking presents with a chronic cough and weight loss.
Bronchoscopy reveals a central lung mass. Biopsy shows small cells with scant cytoplasm, granular chromatin, and absent
nucleoli. Which of the following terms best describes the degree of cellular differentiation in this tumor?
A. Well-differentiated
B. Moderately differentiated
C. Anaplastic [CORRECT]
D. Dysplastic
Correct Answer: C
Rationale: Small cell lung carcinoma is a classic example of an anaplastic (poorly differentiated) tumor. Anaplastic cells have little resemblance to their
tissue of origin, with scant cytoplasm, hyperchromatic nuclei, and absent nucleoli. Well-differentiated tumors closely resemble the parent tissue.
Moderately differentiated tumors show intermediate features. Dysplasia is a pre-malignant change, not a tumor classification.
Q11: A 62-year-old woman with breast cancer is started on tamoxifen. The nurse practitioner explains that tamoxifen acts
as an antagonist in breast tissue but may have agonist effects in the endometrium. This dual action is an example of which
pharmacologic concept?
A. Down-regulation of estrogen receptors
B. Selective estrogen receptor modulation [CORRECT]
C. Competitive inhibition of aromatase
D. Irreversible receptor binding
Correct Answer: B
Rationale: Selective estrogen receptor modulators (SERMs) like tamoxifen have tissue-specific effects, acting as antagonists in breast tissue (blocking
estrogen-driven proliferation) but as agonists in other tissues such as the endometrium (increasing risk of endometrial hyperplasia and carcinoma). This
is not down-regulation, competitive inhibition of aromatase (which is the mechanism of anastrozole), or irreversible binding.
Q12: A pathologist examines a tissue specimen and notes cells with shrinkage, chromatin condensation (pyknosis), nuclear
fragmentation (karyorrhexis), and formation of cytoplasmic blebs without an inflammatory response. Which of the
following processes is occurring?
A. Coagulative necrosis
B. Liquefactive necrosis
C. Apoptosis [CORRECT]
D. Caseous necrosis
Correct Answer: C
Rationale: Apoptosis is programmed cell death characterized by cell shrinkage, chromatin condensation, nuclear fragmentation, and formation of
apoptotic bodies, all without eliciting an inflammatory response. This distinguishes it from necrosis, which involves cell swelling, membrane rupture, and
inflammation. Coagulative and liquefactive necrosis are forms of cell death that trigger inflammation. Caseous necrosis is a specific pattern seen in
tuberculosis.
, NR 507 Advanced Pathophysiology Final Exam Page 4
Q13: A 28-year-old patient with a diagnosed BRCA1 mutation asks about her risk of ovarian cancer. The nurse
practitioner explains that BRCA1 is classified as which type of gene?
A. Proto-oncogene
B. Tumor suppressor gene [CORRECT]
C. Oncogene
D. Telomerase gene
Correct Answer: B
Rationale: BRCA1 is a tumor suppressor gene that plays a critical role in DNA repair through homologous recombination. Mutations in BRCA1 lead to
defective DNA repair, accumulation of genetic damage, and increased risk of breast and ovarian cancers. Proto-oncogenes are normal genes that
promote cell growth; when mutated, they become oncogenes. Oncogenes promote uncontrolled proliferation. Telomerase genes maintain telomere length
and are often reactivated in cancer cells.
Q14: A 48-year-old male presents with a painless neck mass. Biopsy reveals a tumor with papillary architecture and nuclear
features including grooves, overlapping, and pseudoinclusions. Fine psammoma bodies are present. Which of the following
is the most likely diagnosis?
A. Follicular thyroid carcinoma
B. Medullary thyroid carcinoma
C. Papillary thyroid carcinoma [CORRECT]
D. Anaplastic thyroid carcinoma
Correct Answer: C
Rationale: Papillary thyroid carcinoma is the most common thyroid malignancy and is characterized by papillary architecture, nuclear grooves,
overlapping nuclei, nuclear pseudoinclusions, and psammoma bodies (calcified concretions). Follicular carcinoma shows follicular architecture without
these nuclear features. Medullary carcinoma arises from parafollicular C cells and is associated with amyloid stroma. Anaplastic carcinoma is highly
undifferentiated with a very poor prognosis.
Q15: A research study demonstrates that a particular chemotherapeutic agent triggers cytochrome c release from
mitochondria, activation of caspase-9, and subsequent DNA fragmentation. Which cellular process is being induced?
A. Necrosis
B. The intrinsic pathway of apoptosis [CORRECT]
C. The extrinsic pathway of apoptosis
D. Autophagic cell death
Correct Answer: B
Rationale: The intrinsic (mitochondrial) pathway of apoptosis is triggered by intracellular stress signals such as DNA damage, leading to mitochondrial
outer membrane permeabilization and cytochrome c release. Cytochrome c forms the apoptosome with Apaf-1 and caspase-9, activating the caspase
cascade. The extrinsic pathway is initiated by death receptor binding (e.g., FasL, TNF) and activates caspase-8. Necrosis does not involve caspase
activation. Autophagic cell death involves lysosomal degradation.
Q16: A 65-year-old patient with a diagnosed malignant tumor has elevated levels of oncofetal antigens detected in the
blood. Which of the following is an example of an oncofetal antigen used as a tumor marker?
A. BRCA1 protein
B. Carcinoembryonic antigen (CEA) [CORRECT]
C. Epidermal growth factor receptor
D. p53 protein
Correct Answer: B
Rationale: Carcinoembryonic antigen (CEA) is an oncofetal antigen normally expressed during fetal development that is re-expressed in certain
malignancies, particularly colorectal cancer. It is used as a tumor marker for monitoring disease progression and treatment response. BRCA1 is a tumor
suppressor protein, not an oncofetal antigen. EGFR is a receptor tyrosine kinase that can be overexpressed or mutated in cancers. p53 is a tumor
suppressor protein mutated in many cancers.
Q17: A 70-year-old patient with prostate cancer has bone metastases. The nurse practitioner explains that the tumor cells
produce which substance that promotes bone resorption in osteolytic metastases?
A. Osteoprotegerin
