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Anatomy and Physiology 101 Lab 2 Microscope, Cellular Structure, The Cell Cycle Labs 4, 5, and 7 in manual Textbook Figures 3.3, 3.7, and 3.37 Table 3.3 and 3.5
Anatomy and Physiology 101 Lab 2 
Microscope, Cellular Structure, The Cell Cycle Labs 4, 5, and 7 in manual 
Textbook Figures 3.3, 3.7, and 3.37 
Table 3.3 and 3.5 
 
Lab Exercise 4 - Care and Use of the Compound Microscope 
The microscope is an essential tool for the study of structures too small to see with the naked eye. 
 
Objectives- In this lab you will learn the parts of a microscope, the function of each part, how to calculate total magnification, and how to place a slide in position and...
- Exam (elaborations)
- • 13 pages •
Anatomy and Physiology 101 Lab 2 
Microscope, Cellular Structure, The Cell Cycle Labs 4, 5, and 7 in manual 
Textbook Figures 3.3, 3.7, and 3.37 
Table 3.3 and 3.5 
 
Lab Exercise 4 - Care and Use of the Compound Microscope 
The microscope is an essential tool for the study of structures too small to see with the naked eye. 
 
Objectives- In this lab you will learn the parts of a microscope, the function of each part, how to calculate total magnification, and how to place a slide in position and...
MATH 110 Module 4 Exam.| PORTGE LEARNING
MATH 110 Module 4 Exam.| PORTGE LEARNING 
Module 4 Exam 
Exam Page 1 
A factory has eight safety systems. During an emergency, the probability of any one of the safety systems failing is .08. What is the probability that six or more safety systems will fail during an emergency? 
 
f(x) = ( (n!) / (x!(n-x)!) ) x ( (p^x) x ((1-p)^n-x)) ) n = 8 
x = 6, 7, 8 (number of failures) 
p = 0.08 
 
 
6	failures: 
n = 8 
x = 6 
p = 0.8 
n-x = 8-6 = 2 
( (8!) / (6!(2)!) ) x ( (0.08^6) x ((1-0.08)^2)) ) = 6.2...
- Exam (elaborations)
- • 10 pages •
MATH 110 Module 4 Exam.| PORTGE LEARNING 
Module 4 Exam 
Exam Page 1 
A factory has eight safety systems. During an emergency, the probability of any one of the safety systems failing is .08. What is the probability that six or more safety systems will fail during an emergency? 
 
f(x) = ( (n!) / (x!(n-x)!) ) x ( (p^x) x ((1-p)^n-x)) ) n = 8 
x = 6, 7, 8 (number of failures) 
p = 0.08 
 
 
6	failures: 
n = 8 
x = 6 
p = 0.8 
n-x = 8-6 = 2 
( (8!) / (6!(2)!) ) x ( (0.08^6) x ((1-0.08)^2)) ) = 6.2...
MATH 110 – Module 1 (Book Exam) Limespring.com Questions 1-18
MATH 110 – Module 1 (Book Exam) L Questions 1-18
- Exam (elaborations)
- • 7 pages •
MATH 110 – Module 1 (Book Exam) L Questions 1-18
Sophia College Algebra Final Milestone
Sophia College Algebra milestone final 
 
 
 
 
 
 
 
 
 
 
 
Score 22/25 
 
 
 
 
You passed this Milestone 
22 questions were answered correctly. 3MqueIstLionEs wSereTanOsweNredEincorrectly. 
Which of the following graphs represents the quadratic inequality	?
- Exam (elaborations)
- • 31 pages •
Sophia College Algebra milestone final 
 
 
 
 
 
 
 
 
 
 
 
Score 22/25 
 
 
 
 
You passed this Milestone 
22 questions were answered correctly. 3MqueIstLionEs wSereTanOsweNredEincorrectly. 
Which of the following graphs represents the quadratic inequality	?
SOPHIA COLLEGE ALGEBRA MILESTONE 5 – ALL ANSWERS !!!
SOPHIA COLLEGE ALGEBRA MILESTONE 5 – ALL ANSWERS !!! 
 
 
You passed this Milestone 
21 questions were answered correctly. 1 question was answered incorrectly. 
1 
 
Consider the function . 
What are the domain and range of this function? 
• 
 
 
 
• 
 correct 
 
• 
 
 
• 
 
 
RATIONALE 
 
 	A Square root function has the domain restriction that the radicand (the value underneath the radical) cannot be negative. To find the specific domain, construct an inequality showing that th...
- Exam (elaborations)
- • 47 pages •
SOPHIA COLLEGE ALGEBRA MILESTONE 5 – ALL ANSWERS !!! 
 
 
You passed this Milestone 
21 questions were answered correctly. 1 question was answered incorrectly. 
1 
 
Consider the function . 
What are the domain and range of this function? 
• 
 
 
 
• 
 correct 
 
• 
 
 
• 
 
 
RATIONALE 
 
 	A Square root function has the domain restriction that the radicand (the value underneath the radical) cannot be negative. To find the specific domain, construct an inequality showing that th...
College Algebra Unit 4 - Milestone 4 with answers and rationale
College Algebra Unit 4 - Milestone 4 with answers and rationale 
 
18 questions were answered correctly. 2 questions were answered incorrectly. 1 
 
Angela is an electrical engineer who is testing the voltage of a circuit given a certain current and resistance. She uses the following formula to calculate voltage: 
 
The circuit she tests has a current of amps and a resistance of ohms. 
What is the voltage of the circuit? 
• 
 
 
• 
 
 
• 
 
 
• 
 
 
RATIONALE 
 
The voltage of t...
- Exam (elaborations)
- • 53 pages •
College Algebra Unit 4 - Milestone 4 with answers and rationale 
 
18 questions were answered correctly. 2 questions were answered incorrectly. 1 
 
Angela is an electrical engineer who is testing the voltage of a circuit given a certain current and resistance. She uses the following formula to calculate voltage: 
 
The circuit she tests has a current of amps and a resistance of ohms. 
What is the voltage of the circuit? 
• 
 
 
• 
 
 
• 
 
 
• 
 
 
RATIONALE 
 
The voltage of t...
Sophia College Algebra Unit 5 Challenge 3
Sophia College Algebra Unit 5 Challenge 3 
 
 
 
 
 
This study source was downloaded by from CourseH on 04-20-2022 03:22:07 GMT -05:00 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
This study source was downloaded by from CourseH on 04-20-2022 03:22:07 GMT -05:00
- Exam (elaborations)
- • 9 pages •
Sophia College Algebra Unit 5 Challenge 3 
 
 
 
 
 
This study source was downloaded by from CourseH on 04-20-2022 03:22:07 GMT -05:00 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
This study source was downloaded by from CourseH on 04-20-2022 03:22:07 GMT -05:00
MATH 110 Module 1 Exam.| PORTGE LEARNING
MATH 110 Module 1 Exam.| PORTAGE LEARNING 
Module 1 Exam 
 
 
 
 
2. Explain statistical inference.
- Exam (elaborations)
- • 4 pages •
MATH 110 Module 1 Exam.| PORTAGE LEARNING 
Module 1 Exam 
 
 
 
 
2. Explain statistical inference.
MATH 110 COMBINATION OF EXAM ANSWERS
MATH 110 COMBINATION OF EXAM ANSWERS. 
 
Exam 1 
Exam Page 1 
Define each of the following: 
 
a)	Element. 
 
An element is described as "the individual and unique entry in a data set about which data has been collected, analyzed and presented in a same manner to differentiate" (Module 1). 
 
 
b)	Variable. 
 
A variable is defined as a "particular measurable attribute that the researcher believes is needed to describe the element in their study" (Module 1). 
 
 
c)	Data. 
 
Data (or the plu...
- Exam (elaborations)
- • 37 pages •
MATH 110 COMBINATION OF EXAM ANSWERS. 
 
Exam 1 
Exam Page 1 
Define each of the following: 
 
a)	Element. 
 
An element is described as "the individual and unique entry in a data set about which data has been collected, analyzed and presented in a same manner to differentiate" (Module 1). 
 
 
b)	Variable. 
 
A variable is defined as a "particular measurable attribute that the researcher believes is needed to describe the element in their study" (Module 1). 
 
 
c)	Data. 
 
Data (or the plu...
MATH 110 MODULE 3 EXAM
Module 3 Exam 
Exam Page 1 
Suppose A and B are two events with probabilities: 
 
P(Ac )=.40,P(B)=.45,P(A∪B)=.60. 
 
 
Find the following: 
a)	P(A∩B). 
 
p(anb) = p(a) + p(b) - p(aub) p(a) = 1 - p(a^c) 
p(a^c) = 0.40 
1 - 0.40 = 0.60 
p(a) = 0.60 
 
 
0.60 + 0.45 - 0.60 = 0.45 
 
 
P(AnB) = 0.45 
 
b)	P(A). 
 
p(a) = 1 - p(a^c) p(a^c) = 0.40 
 
1 - 0.40 = 0.60 
 
 
P(A) = 0.60 
 
c)	P(Bc). 
 
p(b) = 1 - p(b^c) 
rearranged to find p(b^c) = 1 - p(b) 
 
 
1 - 0.45 = 0.55 
 
 
 
 
 
 
 
 
 
 ...
- Exam (elaborations)
- • 10 pages •
Module 3 Exam 
Exam Page 1 
Suppose A and B are two events with probabilities: 
 
P(Ac )=.40,P(B)=.45,P(A∪B)=.60. 
 
 
Find the following: 
a)	P(A∩B). 
 
p(anb) = p(a) + p(b) - p(aub) p(a) = 1 - p(a^c) 
p(a^c) = 0.40 
1 - 0.40 = 0.60 
p(a) = 0.60 
 
 
0.60 + 0.45 - 0.60 = 0.45 
 
 
P(AnB) = 0.45 
 
b)	P(A). 
 
p(a) = 1 - p(a^c) p(a^c) = 0.40 
 
1 - 0.40 = 0.60 
 
 
P(A) = 0.60 
 
c)	P(Bc). 
 
p(b) = 1 - p(b^c) 
rearranged to find p(b^c) = 1 - p(b) 
 
 
1 - 0.45 = 0.55 
 
 
 
 
 
 
 
 
 
 ...