Los angeles chem 14bl Study guides, Class notes & Summaries

A−¿ ¿ ¿ ¿ (base/acid) HA=acid OH- =base A - =conjugate base H2O=conjugate acid Initial pH: Soltn. Acetic acid made by dissolving 5.00x10-3 mol acetic acid (HA) in 100.00mL water. Then titrated with strong base (NaOH) conc. 0.250M (Ka = 1.8x10-5) HA + H2O  H3O + + AKa = (x )(x) 0.05−x ASSUME X<<0.005  1.8x10-5 = (x)(x ) 0.05 solve I 0.05M ~ 0 0 x = 3.0x10-4 CHECK ASSUMPTION (3.0 x10−4 ) 0 .005 ∗100 = 6% (doesn’t work, plug into quadratic, watch ...