Cos 3701 Study guides, Class notes & Summaries

COS3701 EXAM PACK 2024
Exam (elaborations) • 338 pages • 2023

questions with well outlined answers for exam preparations. compiled from past years

(0)
$3.00
+ learn more

COS3701 EXAM PACK 2023
Exam (elaborations) • 339 pages • 2023

Recent exam questions and answers and summarized notes for exam preparation.

(0)
$2.50
+ learn more

COS 3701 Feedback on EXAM PREPARATION PHASE IV (Use The Pumping Lemma)

COS 3701 Feedback on EXAM PREPARATION PHASE IV (Use The Pumping Lemma)
Exam (elaborations) • 7 pages • 2021

Feedback on EXAM PREPARATION PHASE IV (Use The Pumping Lemma) Question 1: Show that the language {anb n c nd n for n = 1 2 3 . ..} = { abcd aabbccdd . . . } is non-context-free. Feedback Question 1: In order to answer this question we use the pumping lemma with length. See study guide. In this question the alphabet is ∑= {a; b; c; d}. • The first step is to assume that the language L = {a nb nc nd n | n = 1, 2, 3…} actually is context-free. This means that there exis...

(0)
$3.49
+ learn more

Preview 2 out of 7 pages

Add to cart

Exam (elaborations)

(0)

Last document update: ago

Feedback on EXAM PREPARATION PHASE IV (Use The Pumping Lemma) Question 1: Show that the language {anb n c nd n for n = 1 2 3 . ..} = { abcd aabbccdd . . . } is non-context-free. Feedback Question 1: In order to answer this question we use the pumping lemma with length. See study guide. In this question the alphabet is ∑= {a; b; c; d}. • The first step is to assume that the language L = {a nb nc nd n | n = 1, 2, 3…} actually is context-free. This means that there exis...

$3.49

Add to cart

Show more info