Chem 103 module Study guides, Class notes & Summaries

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CHEM 103 MODULE 1 TO 6 EXAM LATEST 2022-2023 QUESTIONS & CORRECT ANSWERS PORTAGE LEARNING|COMPLETE AGRADE
  • CHEM 103 MODULE 1 TO 6 EXAM LATEST 2022-2023 QUESTIONS & CORRECT ANSWERS PORTAGE LEARNING|COMPLETE AGRADE

  • Exam (elaborations) • 35 pages • 2023
  • CHEM 103 MODULE 1 TO 6 EXAM LATEST 2022-2023 QUESTIONS & CORRECT ANSWERS PORTAGE LEARNING|COMPLETE AGRADE
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning)
  • CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning)

  • Exam (elaborations) • 35 pages • 2023
  • CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning) Show the calculation of the mass of a 18.6 ml sample of freon with density of 1.49 g/ml 2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5 ml. 1. M = D x V = 1.49 x 18.6 = 27.7 g 2. D = M / V = 26.3 / 30.5 = 0.862 g/ml Question 5 Click this link to access the Periodic Table. This may be helpful throughout the exam. 1. 3.0600 contains ? significant figures. 2. 0.0151 contains ? significant figu...
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning)
  • CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning)

  • Exam (elaborations) • 35 pages • 2023
  • Available in package deal
  • CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning) Using the following information, do the conversions shown below, showing all work: 1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts 1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints kilo (= 1000) milli (= 1/1000) centi (= 1/100) deci (= 1/10) 1. 24.6 grams = ? kg 2. 6.3 ft = ? inches 1. 24.6 grams x 1 kg / 1000 g = 0.0246 kg 2. 6.3 ft x 12 in / 1 ft = 75.6 inches please always use the correct units in your ...
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Portage Learning / CHEM 103 / Module 1 to 6 Exam answers  2023|2024 UPDATED A+ RATED
  • Portage Learning / CHEM 103 / Module 1 to 6 Exam answers 2023|2024 UPDATED A+ RATED

  • Exam (elaborations) • 58 pages • 2023
  • Click this link to access the Periodic Table. This may be helpful throughout the exam. 1. Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0. Question 2 Click this link to access the Periodic Table. This may be helpful throughout the exam. ...
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CHEM 103 Module 5 Problem Set (100 out of 100) Questions and Verified Elaborations | Portage Learning
  • CHEM 103 Module 5 Problem Set (100 out of 100) Questions and Verified Elaborations | Portage Learning

  • Exam (elaborations) • 7 pages • 2024
  • CHEM 103 Module 5 Problem Set (100 out of 100) Questions and Verified Elaborations | Portage Learning
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 CHEM 103 module 4 exam question and answers
  • CHEM 103 module 4 exam question and answers

  • Other • 8 pages • 2023
  • Write the subshell electron configuration (i.e.1s2 2s2 , etc.) for the Ni28 atom. Your Answer: Ni28 = 1s2 , 2s2 , 2p6 , 3s2 , 3p6 ,4s2 , 3d8 ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↓ ↑ ↑ 1s 2s 2p 3s 3p 4s 3d Ni28 = 28 electrons = 1s2 2s2 2p6 3s2 3p6 4s2 3d8 Question 2 Not yet graded / 10 pts Click this link to access the Periodic Table.This may be helpful throughout the exam. Write the subshell electron configur...
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CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning WITH COMPLETE SOLUTION UPDATED 2023|2024 RATED A+
  • CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning WITH COMPLETE SOLUTION UPDATED 2023|2024 RATED A+

  • Exam (elaborations) • 19 pages • 2023
  • Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. Al (SO ) 2. C H NOBr 2 4 3 7 5 1. Al (SO ) Al = 2 x 26.98 = 53.96 S = 3 x 32.07 = 96.21 O = 12 x 16.00 = 192 2 4 3 M2: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 3/18 Total Molecular Weight for Al (SO ) = 342.17 2. C H NOBr C = 7 x 12.01 = 84.07 H = 5 x 1.008 = 5.04 N = 1 x 14.01 = 14.01 O = 1 x 16....
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PORTAGE LEARNING CHEM 103 MODULE 3 EXAM 2022
  • PORTAGE LEARNING CHEM 103 MODULE 3 EXAM 2022

  • Exam (elaborations) • 6 pages • 2023
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  • PORTAGE LEARNING CHEM 103 MODULE 3 EXAM 2022 A reaction between HCl and NaOH is being studied in a styrofoam coffee cup with NO lid and the heat given off is measured by means of a thermometer immersed in the reaction mixture. Enter the correct thermochemistry term to describe the item listed. 1. The type of thermochemical process 2. The amount of heat released in the reaction of HCl with NaOH 1. Heat given off = Exothermic process 2. The amount of heat released = Heat of reaction
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Exam CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A|
  • Exam CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A|

  • Exam (elaborations) • 34 pages • 2023
  • Available in package deal
  • Exam CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A| Exam CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A| ...
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