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Oxford PAT Questions and Answers with 100% VERIFIED
Solutions UPDATED!!!
n1/n2 = - ANSWER sinR/sinI
F (Hookes Law) = - ANSWER -kx
P(A|B)= - ANSWER P(AnB) / P(B)
Max Velocity = - ANSWER -wa
Chain Rule - ANSWER Dy/Dx= Dy/du x du/dx
Product rule - ANSWER Dy/dx = Udv/dx x Vdu/dx
Differential of Sin(x) - ANSWER cosx
Differential of cos(x) - ANSWER -sinx
Differential of ln(x) - ANSWER 1/x
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Coulomb's Law - ANSWER The relationship among electrical
force, charges, and distance: The electrical force between two
charges varies directly as the product of the charges and
inversely as the square of the distance between them.
integral of lnx - ANSWER xlnx-x+C
F (electrostatic) = - ANSWER 1/ 4piE0 x q1q2/d^2
E (electric field strength) = - ANSWER Force / Charge
F (gravitational) = - ANSWER Gmeme/d^2
Area of sector= - ANSWER 0.5r^2angle
T2= - ANSWER Constant x R3
w (oscillations) = - ANSWER 2 pi f
Oxford PAT Questions and Answers with 100% VERIFIED
Solutions UPDATED!!!
n1/n2 = - ANSWER sinR/sinI
F (Hookes Law) = - ANSWER -kx
P(A|B)= - ANSWER P(AnB) / P(B)
Max Velocity = - ANSWER -wa
Chain Rule - ANSWER Dy/Dx= Dy/du x du/dx
Product rule - ANSWER Dy/dx = Udv/dx x Vdu/dx
Differential of Sin(x) - ANSWER cosx
Differential of cos(x) - ANSWER -sinx
Differential of ln(x) - ANSWER 1/x
, 2|Page
Coulomb's Law - ANSWER The relationship among electrical
force, charges, and distance: The electrical force between two
charges varies directly as the product of the charges and
inversely as the square of the distance between them.
integral of lnx - ANSWER xlnx-x+C
F (electrostatic) = - ANSWER 1/ 4piE0 x q1q2/d^2
E (electric field strength) = - ANSWER Force / Charge
F (gravitational) = - ANSWER Gmeme/d^2
Area of sector= - ANSWER 0.5r^2angle
T2= - ANSWER Constant x R3
w (oscillations) = - ANSWER 2 pi f
