Industrial Automated Systems (1st Edition, 2010) – Solutions to Lab Manual – Bartelt

,Solutions
to Lab Manual to accompany
Industrial Automated Systems:
Instrumentation and Motion Control
Terry Bartelt




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, Experiment
1
Operational Amplifiers
Experiment Questions
1. analog
2. linear
3. greater
4. 6, –
5. – 5V


INPUTS
VOUT
V1 V2 (V)
+4 +1 −5
+2 +3 +5 VIN (V) VOUT (V) VIN (V) VOUT (V)
+1 0 −5 +0.21 −1.2 +0.30 −0.75
+4 +4 0 −0.40 +2.2 −0.15 +0.38
0 +1 +5 0.3 0.6 −2.00 −5.00
+3 +2 −5 +0.32 −1.6 +0.40 −1.00

Figure 1-2 b Figure 1-3 b Figure 1-3 c




Input Voltage Output Voltage
V1 V2 V3 Measured Calculated
+1 +1 +1 −3 −3
+1 −1 −1 +1 +1
+2 −1 −1 0 0
−3 −1 +3 +1 +1
+1 +2 −1 −2 −2

Figure 1-4 b




1

, Experiment
2
Schmitt Trigger
Procedure Question Answer
1. No. Because the 7476 J-K flip-flop is negative-edge triggered, and reacts only to
positive-to-negative–going signals that change abruptly. The rectified sine wave
does not change fast enough.

Step 5
Point 1
.9
Vth – = _____VDC
1.7
Vth + = _____VDC

Table 2-1
Step 7


Is the Flip-Flop
Waveform At Point 1 At Point 2
Toggling (Yes, No)



Circuit (a) NO


Circuit (b) YES


Table 2-2

Experiment Questions
1. - Convert electronic signals to square waves.
- Perform NAND gate and Inverter logic functions.
2. D
3. edge
4. Low, High
5. hysteresis
6. Because when sine waves are counted, they must be converted to square waves
before being applied to a flip-flop.

2

, Experiment
3
Magnitude Comparator
Procedure Question Answer
1. If the high-order bits are equal, then the output state is determined by comparing
the low-order bits.
Step 2A
Input B Input A Outputs
B3 B2 B1 B0 A3 A2 A1 A0 A<B A=B A>B
0 0 0 0 0 0 0 0 0 1 0
0 1 0 0 0 0 0 1 1 0 0
1 0 0 1 1 0 0 0 1 0 0
0 0 1 1 0 1 0 0 0 0 1
0 0 0 1 1 0 0 1 0 0 1

Table 3-2
Step 3B
Input B Input A Expansion Inputs Outputs
B3 B2 B1 B0 A3 A2 A1 A0 IA<B IA=B IA>B A<B A=B A>B
0 0 0 0 1 1 1 1 1 0 0 0 0 1
0 0 0 1 0 0 0 1 0 0 1 0 0 1
0 1 1 0 0 1 1 0 0 1 0 0 1 0
1 1 1 0 1 1 0 1 0 0 1 1 0 0
0 1 0 1 1 1 1 0 0 1 0 0 0 1

Table 3-4

Experiment Questions
1. 1111
2. Yes. By connecting a Low to the MSB of inputs A and B, and applying the three
binary bits to the remaining inputs.
3. IA > B = 0
IA = B = 0
IA < B = 1
4. 4
5. When A is greater than B, or B is greater than A, the circuit would operate nor-
mally. When A is equal to B, however, output A<B would incorrectly go High—
instead of output A=B.

3

, Experiment
4
SCR Phase Control Circuit
Step 3 169 volts, yes
Step 4 15 volts, yes


Experiment Questions
1. D
2. B
3. 169−15 = 154
4. A
5. B
No Power Half Power Full Power
6. B to Load to Load to Load


Input




TP1




TP2




TP3




TP4




TP5




Across Figure 4-1
Lightbulb




4

, Experiment
5
Photoresistor
Step 1 Dark resistance = 40KΩ
Step 3 Ambient light voltage = −8V
Dark voltage = +7V
Design Question
Switch the position of R1 with that of the photoresistor.


Experiment Questions
1. A
2. B
3. B
4. B
5. A




5

, Experiment
6
Optocoupler
Step 1 1 Meg ohm
Step 2 150 ohms
Step 4


LED
On/Off
Condition Ov




Optoisolator
(Transistor)
Output Ov



Step 5 B
Step 6 25KHz
Step 7 IC = 3.5mA
If = 16mA
CTR 22%


Experiment Questions
1. True
2. A
3. A
4. 25%
5. C




6

, Experiment
7
Digital-to-Analog Converter
Procedure Question Answers
1. A
2. A
3. 16 (24)
4. 1
5. Eight different voltage levels. When an open is at the LSB input, a binary 1 is
always applied to the LSB digital input lead of the D/A converter. This causes the
D/A converter to produce the following counts:
Desired Count Count with Pin 12 Open
0 1
1 1
2 3
3 3
4 5
5 5
6 7
7 7
8 9
9 9
10 11
11 11
12 13
13 13
14 15
15 15




7

, 8 Experiment 7 Digital-to-Analog Converter

6. 32
The number of outputs is determined by multiplying 2 by the power of the num-
ber of inputs applied to the digital input of the D/A converter (25).


Experiment Questions
1. 256
2. 1
3. - Change VREF applied to pin 14.
- Change the resistor value connected to pin 14.
- Change the RF resistor connected to pin 4.