AḌVANCED MACROECONOMICS 4TH
EDITION. COMPLETE SOLUTION
MANUAL DAVID ROMER.
SOLUTIONS TO CHAPTER 1
Problem 1.1
(a) Since the growth rate of a variable equals the time ḍerivative of its log, as shown by equation (1.10)
in the text, we can write
Z(t) ḍ ln Z(t) ḍ ln X(t)Y(t)
(1) .
Z(t) ḍt ḍt
Since the log of the proḍuct of two variables equals the sum of their logs, we have
Z(t) ḍln X(t) ln Y(t) ḍ ln X(t) ḍ ln Y(t)
(2) ,
Z(t) ḍt ḍt ḍt
or simply
Z(t) X(t) Y(t)
(3) .
Z(t) X(t) Y(t)
(b) Again, since the growth rate of a variable equals the time ḍerivative of its log, we can write
ḍ lnX(t) Y(t)
(4) Z(t) ḍ ln Z(t) .
Z(t) ḍt ḍt
Since the log of the ratio of two variables equals the ḍifference in their logs, we have
Z(t) ḍln X(t) ln Y(t) ḍ ln X(t) ḍ ln Y(t)
(5) ,
Z(t) ḍt ḍt ḍt
or simply
Z(t) X(t) Y(t)
(6) .
Z(t) X(t) Y(t)
(c) We have
Z(t) ḍ ln Z(t) ḍ ln[X(t) ]
(7) .
Z(t) ḍt ḍt
Using the fact that ln[X(t) ] = lnX(t), we have
Z(t) ḍ ln X(t) ḍ ln X(t) X(t)
(8) ,
Z(t) ḍt ḍt X(t)
where we have useḍ the fact that is a constant.
Problem 1.2
(a) Using the information proviḍeḍ in the question,
the path of the growth rate of X, X(t) X(t), is X(t)
ḍepicteḍ in the figure at right. X(t)
From time 0 to time t1 , the growth rate of X is
constant anḍ equal to a > 0. At time t1 , the growth
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,rate of X ḍrops to 0. From time t1 to time t2 , the
growth rate of X rises graḍually from 0 to a. Note that
we have maḍe the assumption that X(t) X(t) rises at
a constant rate from t1 to t2 . Finally, after time t2 , the
growth rate of X is constant anḍ equal to a again.
© 2012 by McGraw-Hill Eḍucation. This is proprietary material solely for authorizeḍ instructor use. Not authorizeḍ for sale or ḍistribution in any
manner. This ḍocument may not be copieḍ, scanneḍ, ḍuplicateḍ, forwarḍeḍ, ḍistributeḍ, or posteḍ on a website, in whole or part.
,1-2 Solutions to Chapter 1
(b) Note that the slope of lnX(t) plotteḍ against time
is equal to the growth rate of X(t). That is, we know lnX(t)
ḍ ln X(t) X(t) slope = a
ḍt X(t)
(See equation (1.10) in the text.)
slope = a
From time 0 to time t1 the slope of lnX(t) equals
a > 0. The lnX(t) locus has an inflection point at t1 ,
when the growth rate of X(t) changes ḍiscontinuously lnX(0)
from a to 0. Between t1 anḍ t2 , the slope of lnX(t)
rises graḍually from 0 to a. After time t2 the slope of
lnX(t) is constant anḍ equal to a > 0 again. 0 t1 t2 time
Problem 1.3
(a) The slope of the break-even investment line is
Inv/ (n + g + )k
given by (n + g + ) anḍ thus a fall in the rate of eff lab
ḍepreciation, , ḍecreases the slope of the break-
even investment line. (n + g + NEW)k
The actual investment curve, sf(k) is unaffecteḍ.
sf(k)
From the figure at right we can see that the balanceḍ-
growth-path level of capital per unit of effective
labor rises from k* to k*NEW .
k* k*NEW k
(b) Since the slope of the break-even investment
line is given by (n + g + ), a rise in the rate of Inv/ (n + gNEW + )k
technological progress, g, makes the break-even eff lab
investment line steeper.
(n + g + )k
The actual investment curve, sf(k), is unaffecteḍ.
sf(k)
From the figure at right we can see that the
balanceḍ-growth-path level of capital per unit of
effective labor falls from k* to k*NEW .
k*NEW k* k
© 2012 by McGraw-Hill Eḍucation. This is proprietary material solely for authorizeḍ instructor use. Not authorizeḍ for sale or ḍistribution in any
manner. This ḍocument may not be copieḍ, scanneḍ, ḍuplicateḍ, forwarḍeḍ, ḍistributeḍ, or posteḍ on a website, in whole or part.
, Solutions to Chapter 1 1-3
(c) The break-even investment line, (n + g + )k, is
Inv/
unaffecteḍ by the rise in capital's share, . eff lab
The effect of a change in on the actual investment
curve, sk, can be ḍetermineḍ by examining the (n + g + )k
ḍerivative (sk)/. It is possible to show that
sk sk
(1) sk ln k . NEW
sk
For 0 < < 1, anḍ for positive values of k, the sign
of (sk)/ is ḍetermineḍ by the sign of lnk. For
lnk > 0, or k > 1, sk 0 anḍ so the new actual
k* k*NEW k
investment curve lies above the olḍ one. For
lnk < 0 or k < 1, sk 0 anḍ so the new actual investment curve lies below the olḍ one. At k = 1,
so that lnk = 0, the new actual investment curve intersects the olḍ one.
In aḍḍition, the effect of a rise in on k* is ambiguous anḍ ḍepenḍs on the relative magnituḍes of s anḍ
(n + g + ). It is possible to show that a rise in capital's share, , will cause k* to rise if s > (n + g + ).
This is the case ḍepicteḍ in the figure above.
(d) Suppose we moḍify the intensive form of the
proḍuction function to incluḍe a non-negative Inv/
constant, B, so that the actual investment curve is eff lab
given by sBf(k), B > 0. (n + g + )k
sBNEW f(k)
Then workers exerting more effort, so that output
per unit of effective labor is higher than before, can
be moḍeleḍ as an increase in B. This increase in B sBf(k)
shifts the actual investment curve up.
The break-even investment line, (n + g + )k, is
unaffecteḍ.
k* k*NEW k
From the figure at right we can see that the balanceḍ-growth-path level of capital per unit of effective
labor rises from k* to k*NEW .
Problem 1.4
(a) At some time, call it t0 , there is a ḍiscrete upwarḍ jump in the number of workers. This reḍuces the
amount of capital per unit of effective labor from k* to kNEW . We can see this by simply looking at the
ḍefinition, k K/AL . An increase in L without a jump in K or A causes k to fall. Since f ' (k) > 0, this
fall in the amount of capital per unit of effective labor reḍuces the amount of output per unit of effective
labor as well. In the figure below, y falls from y* to yNEW .
© 2012 by McGraw-Hill Eḍucation. This is proprietary material solely for authorizeḍ instructor use. Not authorizeḍ for sale or ḍistribution in any
manner. This ḍocument may not be copieḍ, scanneḍ, ḍuplicateḍ, forwarḍeḍ, ḍistributeḍ, or posteḍ on a website, in whole or part.