• Wrong document? Swap it for free
  • Written by students who passed
  • Immediately available after payment
  • Read online or as PDF
Sell
Where do you study
Your language
Document preview thumbnail
Preview 2 out of 5 pages
Exam (elaborations)

Manhattan College MATH 103: sequences

Document preview thumbnail
Preview 2 out of 5 pages

Manhattan College MATH 103: sequences

Content preview

Sequences




In simple words sequence is a list of numbers written in definite order: a1 , a2 , … , an . a1 is first ​ ​ ​ ​




term, a2 is second term, and, in general, an is n-th term. We deal with infinite sequences, so each
​ ​




term an will have a successor an+1 .
​ ​




Notice that for every positive integer n there is a corresponding number an and so a sequence ​




can be defined as a function whose domain is the set of positive integers. But we usually write an ​




instead of the function notation f(n) for the value of the function at the number n.

∞
The sequence {a1 , a2 , … , an } is also denoted by {an } or {an }n=1 .
​ ​ ​ ​ ​ ​




If sequence is given by formula an ​ = f (n) then we calculate an by calculating f (n). For example,
​




1 1
if an ​ = n+1
then ​ a3 = ​




3+1
​ = 14 . ​




Example 1. Some sequences can be defined by giving a formula for the n-th term. In the
following examples we give three descriptions of the sequence: one by using the preceding
notation, another by using the defining formula, and a third by writing out the terms of the
sequence. Notice that n doesn't have to start at 1.
∞
a. { n2n+1 } , an = n2n+1 , { 12 , 25 , 10
3 4
n=1
​ ​ , 17 , … , n2n+1 , …}
​ ​ ​ ​ ​ ​




n n n
b. {(−1) 2n }, an = (−1) 2n , {−2, 4, −8, 16, … , (−1) 2n , …}
​




∞
1 1 1 1 1 1
c. { n−2 } , an = , n > 2, {1, , , 2
, … , …}
n−2 2 3 n−2
​ ​ ​ ​ ​ ​ ​




n=3 ​ ​ ​ ​




πn ∞
d. {sin ( 4 )}n=0 ,
​ ​ an = sin ( πn
4 ), n ≥ 0, {0,
​ ​
1
2
​




​
, 1, 12 , 0, … , sin ( πn
​




​
4 ​ ), … }

Note, that there are sequences that don't have a simple defining equation.



Example 2.

a. Sequence {pn } where pn is population of USA as of January 1 in the year n.
​ ​




b. If an is n-th decimal digit of number π then {an }
​ ​ = {1, 4, 1, 5, 9, 2, 6, 5, …}.
This study source was downloaded by 100000898062787 from CourseHero.com on 09-29-2025 04:47:44 GMT -05:00


https://www.coursehero.com/file/250856122/sequencespdf/

, c. The Fibonacci sequence {f n } is defined recursively as f 1
= 1, f 2 = 1,f n = f n−1 + f n−2 , n ≥ 3.
​ ​ ​ ​ ​ ​




In other words, n-th member is sum of two previous. So, {f n } = ​




{1, 1, 2, 3, 5, 8, 13, 21, 34, 55, …}.
n n 1 n 1
Now, consider the sequence an ​ = n+1
​. Since n+1 ​ =1− n+1
then
​ 1− n+1
​ = n+1
. We see
​




that this difference can be made as small as we like by taking n sufficiently large. We indicate it
n
by writing limn→∞ n+1 ​ ​ = 1.



Definition. A sequence {an } has the limit L and we write limn→∞ an ​ ​ ​
= L or an → L as L →​




∞ if we can make the terms an as close to L as we like by taking n sufficiently large. If ​




limn→∞ an exists, we say the sequence converges (or is convergent). Otherwise, we say the
​ ​




sequence diverges (or is divergent).


Notice that the following definition of the limit of a sequence is very similar to the definition of a
limit of a function at infinity.


If you compare Definition with definition of a limit of a function at infinity you will see that the only
difference between limx→∞ f (x) ​
= L and limn→∞ an = L is that n is required to be an integer.
​ ​




Thus, we have the following theorem.



Theorem 1. If limx→∞ f (x) ​
= L and f (n) = an when n is an integer, then limn→∞ an = L.
​ ​ ​




In particular, since limx→∞ x1r ​ ​
= 0 when r > 0, we have that limn→∞ ​
1
nr
​
= 0 when r > 0.

If an becomes large as n grows we use notation limn→∞ an
​
= ∞. In this case sequence {an } is ​ ​ ​




divergent, but in a special way. We say that {an } diverges to ∞. ​




The Limits Laws also hold for the limits of sequences and their proof are similar.



Limit Laws for Convergent Sequences

1. If {an } and {bn } are convergent sequences and c is arbitrary constant then;
​ ​




2. limn→∞ (an + bn ) = limn→∞ an + limn→∞ bn
​ ​ ​ ​ ​ ​ ​




3. limn→∞ (an − bn ) = limn→∞ an − limn→∞ bn
​ ​ ​ ​ ​ ​ ​




4. limn→∞ c = c ​




5. limn→∞ can = c limn→∞ an
​ ​ ​ ​




This study source was downloaded by 100000898062787 from CourseHero.com on 09-29-2025 04:47:44 GMT -05:00


https://www.coursehero.com/file/250856122/sequencespdf/

Document information

Uploaded on
September 29, 2025
Number of pages
5
Written in
2025/2026
Type
Exam (elaborations)
Contains
Questions & answers
$12.99

Wrong document? Swap it for free Within 14 days of purchase and before downloading, you can choose a different document. You can simply spend the amount again.
Written by students who passed
Immediately available after payment
Read online or as PDF

Seller avatar
Reputation scores are based on the amount of documents a seller has sold for a fee and the reviews they have received for those documents. There are three levels: Bronze, Silver and Gold. The better the reputation, the more your can rely on the quality of the sellers work.
PaulMarks
3.7
(227)
Sold
1406
Followers
1093
Items
4928
Last sold
11 hours ago



Why students choose Stuvia

Created by fellow students, verified by reviews

Quality you can trust: written by students who passed their tests and reviewed by others who've used these notes.

Didn't get what you expected? Choose another document

No worries! You can instantly pick a different document that better fits what you're looking for.

Pay as you like, start learning right away

No subscription, no commitments. Pay the way you're used to via credit card and download your PDF document instantly.

Student with book image

“Bought, downloaded, and aced it. It really can be that simple.”

Alisha Student

Working on your references?

Create accurate citations in APA, MLA and Harvard with our free citation generator.

Working on your references?

Frequently asked questions