Polymer Science and
Technology
Third Edition
Joel R. Fried
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ISBN-10: 0-13-384559-1
ISBN-13: 978-0-13-384559-4
This text is associated with Fried/Polymer Science and Technology, Third Edition (9780137039555)
Copyright 2014, Pearson Education, Inc. Do not redistribute.
, SOLUTIONS TO PROBLEMS IN POLYMER SCIENCE AND TECHNOLOGY,
3RD EDITION
TABLE OF CONTENTS
Chapter 1 1
Chapter 2 5
Chapter 3 14
Chapter 4 24
Chapter 5 28
Chapter 7 36
Chapter 11 40
Chapter 12 51
Chapter 13 52
CHAPTER 1
1-1 A polymer sample combines five different molecular-weight fractions, each of equal weight. The
molecular weights of these fractions increase from 20,000 to 100,000 in increments of 20,000.
Calculate M n , M w , and M z . Based upon these results, comment on whether this sample has a
broad or narrow molecular-weight distribution compared to typical commercial polymer samples.
Solution
Fraction # Mi (×10-3) Wi Ni = Wi/Mi (×105)
1 20 1 5.0
2 40 1 2.5
3 60 1 1.67
4 80 1 1.25
5 100 1 1.0
Σ 300 5 11.42
5
5
M n = ∑Wi N = = 43,783
i =1 1.142 × 10−4
5
∑W M i i
300,000
Mw = i =1
5
= = 60,000
5
∑Wi =1
i
5
∑W M i i
2
4 × 108 + 16 × 108 + 36 × 108 + 64 × 108 + 100 × 108
Mz = i =1
= = 73,333
5
3 × 105
∑W M
i =1
i i
M z 60,000
= = 1.37 (narrow distribution)
M n 43,783
1-2 A 50-gm polymer sample was fractionated into six samples of different weights given in the table
below. The viscosity-average molecular weight, M v , of each was determined and is included in the table.
Estimate the number-average and weight-average molecular weights of the original sample. For these
calculations, assume that the molecular-weight distribution of each fraction is extremely narrow and can
1
This text is associated with Fried/Polymer Science and Technology, Third Edition (9780137039555)
Copyright 2014, Pearson Education, Inc. Do not redistribute.
, be considered to be monodisperse. Would you classify the molecular weight distribution of the original
sample as narrow or broad?
Fraction Weight Mv
(gm)
1 1.0 1,500
2 5.0 35,000
3 21.0 75,000
4 15.0 150,000
5 6.5 400,000
6 1.5 850,000
Solution
Let M i ≈ M v
Fraction Wi Mi Ni = Wi/Mi WiMi
(×106)
1 1.0 1,500 667 1500
2 5.0 35,000 143 175.000
3 21.0 75,000 280 627,500
4 15.0 150,000 100. 2,250,000
5 6.5 400,000 16.3 2,600,000
6 1.5 850,000 1.76 1,275,000
Σ 50.0 1208 7,929,000
6
50.0
M n = ∑Wi N = = 41,322
i =1 1.21 × 10−3
6
∑W M i i
7,930,000
Mw = i =1
6
= = 158,600
50.0
∑Wi =1
i
M w 158, 600
= = 3.84 (broad distribution)
Mn 41,322
1-3 The Schultz–Zimm [11] molecular-weight-distribution function can be written as
a b +1
W (M ) = M b exp ( − aM )
Γ ( b + 1)
where a and b are adjustable parameters (b is a positive real number) and Γ is the gamma function (see
Appendix E) which is used to normalize the weight fraction.
(a) Using this relationship, obtain expressions for M n and M w in terms of a and b and an expression for
M max , the molecular weight at the peak of the W(M) curve, in terms of M n .
Solution
∞
Mn =
∫ 0
WdM
∞
∫ (W
0
M ) dM
let t = aM
2
This text is associated with Fried/Polymer Science and Technology, Third Edition (9780137039555)
Copyright 2014, Pearson Education, Inc. Do not redistribute.