Bio 182 Genetics Module 2 Final Exam
T/F Dominance results from biochemical processes involving enzymes associated with
the gene. - Correct Answer-True
T/F If a heterozygote (Aa) makes some enzymes, but not enough to catalyze as many
reactions as a homozygote (AA) can, all genotypes would have the same phenotype
(AA=Aa=aa)? - Correct Answer-False
Unit of heritable information on chromosome and consisting of a sequence of DNA. -
Correct Answer-Gene
A heritable feature, such as flower color. - Correct Answer-Character
A variant of a character, such as purple or white flowers. - Correct Answer-Trait
T/F Each trait carries two copies of a gene, one inherited from the mother and the other
from the father. - Correct Answer-True
Probability - Correct Answer-Describes our certainty about an outcome or event
Independent Events - Correct Answer-The outcome of one event does not affect the
outcome of the second event
Joint Probability - Correct Answer-The probability of two events occurring together
P(A and B) = P(A) · P(B) - Correct Answer-Joint Probability Calculation
P(A OR B) = P(A) + P(B) - P(A AND B) - Correct Answer-Probability that either event
occurs
-Each parent in the monohybrid cross contributed one of two alleles to each offspring
-Every combination of alleles was equally likely - Correct Answer-Mendels postulated
the following rules of inheritance
Different phenotypes for a single trait - Correct Answer-Monohybrid cross
T/F A probability of 0.98 means that an event occurs rarely. - Correct Answer-False
T/F When a parent is heterozygous, the probability of passing the dominant allele to its
offspring is 25%. - Correct Answer-False
T/F When both parents are heterozygous (Aa), the probability of an offspring being
homozygous recessive (aa) equals 0.25. - Correct Answer-True
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T/F A Punnett square enables one to determine the frequency of observed genotypes
without using a mathematical formula to calculate the joint probability. - Correct Answer-
True
T/F When both parents are heterozygous (Aa), the probability of an offspring being
heterozygous (Aa) equals 0.75. - Correct Answer-False
Why do experiments? - Correct Answer-1. Replicate Observations
2. Control Conditions
3. Randomize Subjects
T/F If two heterozygotes mate to produce two offspring, the chance that both offspring
are homozygous equals 50%. - Correct Answer-False
The probability of the observed deviation or a greater deviation, when the model is
correct - Correct Answer-P Value
A statistical test used to determine the probability of obtaining observed proportions by
chance, under a specific hypothesis. - Correct Answer-Chi-square test
T/F Given a P value less than 0.01, our model of genetics probably fails to explain the
observed phenotypes. - Correct Answer-True
T/F A statistical test estimates the probability of obtaining a certain deviation from
predictions based on sampling error. - Correct Answer-True
T/F We cannot use Mendel's model alone to explain variation in continuous traits, such
as height. - Correct Answer-True
T/F Mendel's model applies only to discrete traits, which have only two or three
phenotypes (e.g., round or wrinkled peas; or red, pink, and white flowers). - Correct
Answer-True
T/F Fisher's revised model of inheritance started the field of quantitative genetics, which
focuses on continuous traits. - Correct Answer-True
The resulting theory of evolution grew during a period from 1920-1940 is known as -
Correct Answer-Modern Synthesis
T/F A genotype with many alleles that contribute to height will be taller than a genotype
with many alleles that detract from the height. - Correct Answer-True
T/F A trait with a heritability of 25% can evolve more rapidly than a trait with a heritability
of 50%. - Correct Answer-False
Bio 182