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WGU D335 – Introduction to Python (OA) Practice Exam 2026

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Ace your WGU D335 Introduction to Python Objective Assessment (OA) with this comprehensive practice exam, featuring 100% verified questions and answers aligned with the official WGU exam blueprint. This resource is designed to help you master Python fundamentals, debug code, and solve programming challenges with confidence—guaranteeing an A+ performance on your first attempt! Why This Practice Exam Works: 100% Exam Accuracy – Questions mirror the actual OA format and difficulty Detailed Explanations – Every answer includes code breakdowns and logic A+ Pass Guarantee – Used by 1,000+ successful students Covers All Tested Topics – From basics to problem-solving

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Institution
WGU D335
Course
WGU D335

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WGU D335 – INTRODUCTION TO PYTHON (OA)
PRACTICE EXAM 100% CORRECT QUESTIONS
A+ PASS GUARANTEED


Create a solution that accepts three integer inputs representing the number of
times an employee travels to a job site. Output the total distance traveled to two
decimal places given the following miles per employee commute to the job site.
Output the total distance traveled to two decimal places given the following miles
per employee commute to the job site:


Employee A: 15.62
miles Employee B:
41.85 miles
Employee C: 32.67
miles
The solution output should be in the
format Distance: total_miles_traveled
commute = { 'Employee A': 15.62,
'Employee B': 41.85,
'Employee C': 32.67
}
travels = {
'Employee A': int(input()),
'Employee B':
int(input()), 'Employee
C': int(input())

,}
t_d_t = sum(commute[employee]*travels[employee] for employee in travels)
print(f'Distance: {t_d_t:.2f} miles') << correct answer >>Create a Python solution
to the following task. Ensure that the solution produces output in exactly the same
format shown in the sample(s) below, including capitalization and whitespace.
Task:
Create a solution that accepts an integer input representing any number of ounces.
Output the converted total number of tons, pounds, and remaining ounces based
on the input ounces value. There are 16 ounces in a pound and 2,000 pounds in a
ton.

, The solution output should be in the format


Tons: value_1 Pounds: value_2 Ounces:
value_3 opp = 16 top = 2000
ounces = int(input())
tons = ounces // (opp *
top) ro = ounces %
(opp * top) pounds =
ro // opp
ro %= opp
print(f'Tons:
{tons}')
print(f'Pounds: {pounds}')
print(f'Ounces: {ro}') << correct answer >>Create a solution that accepts an integer
input representing the index value for any any of the five elements in the following
list:
various_data_types = [516, 112.49, True, "meow", ("Western", "Governors",
"University"), {"apple": 1, "pear": 5}]


Using the built-in function type() and getting its name by using the .name
attribute, output data type (e.g., int", "float", "bool", "str") based on the input
index value of the list element.


The solution output should be in the format
Element index_value: data_type I_V =
int(input()) if -1 <= I_V <
len(various_data_types):

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Uploaded on
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