QUIZ EXAM QUESTIONS AND
ANSWERS 100% SOLVED
You place an object in front of a mirror and observe that the image is real. Which of the
following arrangements could produce this image? - ANSWER-A converging lens, but
only if the object is placed at do > f.
An object with a height of 1.0 cm is at some position from a converging mirror. The
image is real and has a height of 0.33 cm. The statement that best compares the object
and image positions is the - ANSWER-image is closer the mirror than the object.
An object is at a position of 15 cm from a diverging lens with a virtual focal point of 8
cm. The location of the image is - ANSWER--5.2 cm.
The focal length of a lens depends on the - ANSWER-All of the above statements are
correct.
A ray diagram showing the principle rays traveling from the tip of an arrow through a
converging lens is below. An additional ray is also incident on the lens. Which of the
rays shows the correct refraction for this ray? - ANSWER-B
A light ray is incident on a plane mirror with an angle of 50°. The reflected angle of the
light ray is - ANSWER-equal to 50°.
An object is at a position 6.0 cm from a converging lens with a focal length of 3.0 cm.
Compared to the object height, the height of the image is - ANSWER-same size.
An object is at a position 1.0 cm from a converging mirror with a focal point of 2.0 cm.
The image will be located at a position of - ANSWER--2.0 cm.
An arrow is in front of a mirror as shown below. The resulting image can best be
described as - ANSWER-virtual and upright.
A student solves for the image height produced by a curved mirror and obtains a
negative value. This means the - ANSWER-image is inverted.
A light ray traveling through a material with an index of refraction of 1.2 is incident on a
material that has an index of refraction of 1.4. Compared to the incident angle, the
refracted angle of the light ray is - ANSWER-smaller than the incident angle.