Final Exam Practice Test.
1. For the given significance test, explain the meaning of Concluding
that the
a Type I error. smog-level has
decreased
A metropolitan city is trying to bring its smog level into when it has
actually not.
federal guidelines and currently has 12%
pollutants per 10,000 volume of air. The city
comes up with a new policy where city
employees are encouraged to use city
transportation to and from work. An
independent agency, hired by the city, runs a
test on the air in order to determine if the new
policy has had the desired effect.
Explain the meaning of a Type I error.
2. Determine the margin of error. Using the z-
It has been determined with 95% confidence tables (or t-
that the proportion of Americans who eat tables),
turkey on Thanksgiv- ing is between 0.78 and determine
0.82. the critical
Determine the margin of error associated value for
with this confidence interval. the two-
tailed z-test
3. Determine the point estimate. with α=0.02
A random sample of 800 people found that 408
cele- brate Valentine's Day. 5. State your
Find a point estimate (p-hat) for p, the conclusion
population pro- portion of people who celebrate to the
hypothesis
Valentine's Day. test.
Is achieving
4. Determine the critical value.
a basic skill
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30
, Final Exam Practice Test.
level in a subject indepen- dent to the location not .80 or .78 or .05
of the school? A random sample
.51 ?
not ±1.645
There is not a suflcient
sample evidence to
sug- gest that skill level
in a
2/
30
, Final Exam Practice Test.
of students categorized by the location of subject is dependent
school and the number achieving basic skills in on location.
three subjects is shown in the table.
Conduct a chi-square test of independence at
the 1% significance level to test whether the
two variables are independent and state your
conclusion.
Hint: the test statistic is: χ2=0.30
6. Conduct the appropriate hypothesis test and compute No, because
the p-value =
the p-value.Sunshine Air has determined that their 268
no-show rate for passengers booked on a flight involved a
is 6%. The Airline has recently increased the distracted
cost of its travel insurance and and suspects driver using
the no-show rate for pas- sengers will some kind
decrease. of elec-
A random sample of 380 reservations resulted in tronic
18 no-shows. device.
At the 0.10 significance level, is there strong
enough sample evidence to suggest that the
no-show rate in less than 6%?
7. Determine type and strength of the
association.
Data shown on the following scatter-plot
indicate a correlation of 0.96 between the
average flow rate and pressure.
Describe the association.
8. Construct the requested confidence interval.
A survey of 400 non-fatal accidents revealed that
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30
1. For the given significance test, explain the meaning of Concluding
that the
a Type I error. smog-level has
decreased
A metropolitan city is trying to bring its smog level into when it has
actually not.
federal guidelines and currently has 12%
pollutants per 10,000 volume of air. The city
comes up with a new policy where city
employees are encouraged to use city
transportation to and from work. An
independent agency, hired by the city, runs a
test on the air in order to determine if the new
policy has had the desired effect.
Explain the meaning of a Type I error.
2. Determine the margin of error. Using the z-
It has been determined with 95% confidence tables (or t-
that the proportion of Americans who eat tables),
turkey on Thanksgiv- ing is between 0.78 and determine
0.82. the critical
Determine the margin of error associated value for
with this confidence interval. the two-
tailed z-test
3. Determine the point estimate. with α=0.02
A random sample of 800 people found that 408
cele- brate Valentine's Day. 5. State your
Find a point estimate (p-hat) for p, the conclusion
population pro- portion of people who celebrate to the
hypothesis
Valentine's Day. test.
Is achieving
4. Determine the critical value.
a basic skill
1/
30
, Final Exam Practice Test.
level in a subject indepen- dent to the location not .80 or .78 or .05
of the school? A random sample
.51 ?
not ±1.645
There is not a suflcient
sample evidence to
sug- gest that skill level
in a
2/
30
, Final Exam Practice Test.
of students categorized by the location of subject is dependent
school and the number achieving basic skills in on location.
three subjects is shown in the table.
Conduct a chi-square test of independence at
the 1% significance level to test whether the
two variables are independent and state your
conclusion.
Hint: the test statistic is: χ2=0.30
6. Conduct the appropriate hypothesis test and compute No, because
the p-value =
the p-value.Sunshine Air has determined that their 268
no-show rate for passengers booked on a flight involved a
is 6%. The Airline has recently increased the distracted
cost of its travel insurance and and suspects driver using
the no-show rate for pas- sengers will some kind
decrease. of elec-
A random sample of 380 reservations resulted in tronic
18 no-shows. device.
At the 0.10 significance level, is there strong
enough sample evidence to suggest that the
no-show rate in less than 6%?
7. Determine type and strength of the
association.
Data shown on the following scatter-plot
indicate a correlation of 0.96 between the
average flow rate and pressure.
Describe the association.
8. Construct the requested confidence interval.
A survey of 400 non-fatal accidents revealed that
3/
30
