Entrance Exam Semmelweis Questions And Answers | Updated Solutions | 100% Correct Answers

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Entrance Exam Semmelweis

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Terms in this set (124)


Subtract 1 from exponent of highest n-value orbital
Electron configuration for (ex. remove from 4s before 3d)
cations
Ag+ = [Kr]5s^1 4d^9

Add 1 to closest orbital
Electron configuration for
anions
Cl- = [Ne]3s^2 3p^6

Atomic orbitals s, p, d, f

Primary - AA chain (linked by peptide bonds)
Primary vs secondary
structures of proteins Secondary - stabilized by non-covalent bonds (alpha
helices & beta sheets)

Most bonds in organic covalent
compounds are

1. polar
2. capable of adhesion and cohesion
3. high heat capacity (so it's hard to raise its temp)
Properties of water 4. great solvent
5. high heat of vaporization (allows humans to cool off
via sweat)
6. water is less dense as a solid than a liquid

Intermolecular forces of hydrogen bonding
water

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1. solvent (product being dissolved)
Solution components
2. solute (medium for dissolving solvent)

Molarity the number of moles of solute per liter of solution

SOLUBLE
1. alkali metals (group 1) & NH4+ cations
2. NO3- or CH3COO- anions
3. Cl, Br, I (except when bonded to Ag+, Pb2+ or Hg2+)
4. sulfate ions (except when with Ca2+, Sr2+, Ba2+,
Pb2+)
Solubility rules

INSOLUBLE
1. Metal oxides (except CaO, SrO, BaO)
2. Hydroxides (except when with Ca2+, Sr2+, Ba2+)
3. Carbonates, phosphates, sulfides, and sulfites
(unless bound to alkali metal or NH4+)

Ksp = [A]^a[B]^b


**only products because we don't include solids in the
equilibrium expression


for NaCl
Solubility product - Ksp = x^2


for PbCl2
- Ksp = 4x^3


for Cr(OH)3
- Ksp = 27x^4

Large Ksp means strong electrolyte (more soluble)




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So I brought no clean clothes


1. H2SO4
2. HI
Strong acids 3. HBr
4. HNO3
5. HCl
6. HClO4
7. HClO3

1. NaOH
2. LiOH
3. KOH
4. CsOH
5. RbOH
Strong bases 6. Ba(OH)2
7. Ca(OH)2
8. Sr(OH)2


Bases can certainly look pleasing (K), really something
strong (Na)

pressure applied (or volume reduced) --> equilibrium
proceeds in direction with fewer moles
Le Chatlier's principle:
pressure
pressure removed (or volume increased) -->
equilibrium proceeds in direction with more moles

increasing temperature
- toward products (if endothermic)
- toward reactants (if exothermic)
Le Chatlier's principle:
temperature
decreasing temperature
- toward products (if exothermic)
- toward reactants (if endothermic)




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