GMS 6401 Mock Exam questions with
complete solutions
The glomerular capillary is surrounded by an epithelial structure which forms the beginning of
the tubule. - correct answer ✔✔The kidney consists of specialized vascular and tubular
structures (the nephron) which collaborate in the production of urine:
GFR = 100ml/min - correct answer ✔✔A diagnostic renal clearance experiment is conducted
and the following steady state (= equilibrium) measurements are obtained on a 34 year old
male subject, weighing 60 kg (assume that the renal plasma flow (RPF) is the same as the
effective renal plasma flow (ERPF):
Urine inulin = 200 mg/100ml
Plasma inulin = 4 mg/100ml
Urine flow (V) = 2ml/min
Urine PAH = 1200 mg/100ml
Plasma PAH = 6 mg/100ml
Less than the clearance of inulin - correct answer ✔✔Any substance which is freely filtered at
the glomerulus, is reabsorbed and is not secreted, will have a renal clearance that is: Choose
one best answer.
Loss of nephrin from the epithelial slit pore diaphragm - correct answer ✔✔An increased
protein excretion (proteinuria) can indicate glomerular damage. Which of the following changes
are likely to cause proteinuria? Choose 1 best answer:
A low glomerular capillary water permeability - correct answer ✔✔Maintenance of a high
glomerular filtration rate (GFR) is required for optimal kidney function. Which of the following
options would be most likely to associate with a below optimal GFR in man?
complete solutions
The glomerular capillary is surrounded by an epithelial structure which forms the beginning of
the tubule. - correct answer ✔✔The kidney consists of specialized vascular and tubular
structures (the nephron) which collaborate in the production of urine:
GFR = 100ml/min - correct answer ✔✔A diagnostic renal clearance experiment is conducted
and the following steady state (= equilibrium) measurements are obtained on a 34 year old
male subject, weighing 60 kg (assume that the renal plasma flow (RPF) is the same as the
effective renal plasma flow (ERPF):
Urine inulin = 200 mg/100ml
Plasma inulin = 4 mg/100ml
Urine flow (V) = 2ml/min
Urine PAH = 1200 mg/100ml
Plasma PAH = 6 mg/100ml
Less than the clearance of inulin - correct answer ✔✔Any substance which is freely filtered at
the glomerulus, is reabsorbed and is not secreted, will have a renal clearance that is: Choose
one best answer.
Loss of nephrin from the epithelial slit pore diaphragm - correct answer ✔✔An increased
protein excretion (proteinuria) can indicate glomerular damage. Which of the following changes
are likely to cause proteinuria? Choose 1 best answer:
A low glomerular capillary water permeability - correct answer ✔✔Maintenance of a high
glomerular filtration rate (GFR) is required for optimal kidney function. Which of the following
options would be most likely to associate with a below optimal GFR in man?
