PORTAGE LEARNING CHEMISTRY 103 FINAL
EXAM STUDY GUIDE
MODULES
1-6
MODULE 1
– EXAM
Question 1 – Section 1.1
pts
Complete the two problems below:
1. Convert 1005.3 to exponential form and explain your answer.
2. Convert 4.87 x 10-6 to ordinary
form and explain your answer. Your
Answer:
1.) Convert 1005.3 to exponential form and explain your answer:
All number values must be between 1-10. Because this value is greater than 1, the exponent remains
positive.
In order for this to happen, we have to move the decimal three places to the LEFT thus, the exponential
form of 1005.3 is: 1.0053 X 103
2.) Convert 4.87 x 10-6 to ordinary form and explain your answer.
All number values must be between 1-10. Because this value has a
negative exponent, the final answer will be less than 1. In order for this
to happen, we have to move the decimal six places to the LEFT thus:
0.00000487
,Question 2
pts
Complete the two problems below:
Using the following information, do the conversions shown below, showing all work:
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts
1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints
kilo (= 1000) milli (= 1/1000) centi (= 1/100) deci (= 1/10)
1. 3.6 pounds = ? oz
2. 2680 ml =
? liters Your
Answer:
1.) 3.6 pounds = 57.6 oz
1lb = 16oz
3.6(16) / 1 =57.6 oz
2.) 2680 ml = 2.68 liters
New/Old
Liters/Millilit
ers
,1L = 1,000mL
2,680/1,000
=2.68
Question 3
pts
Do the conversions shown below, showing all work:
1. 78oC = ? oK
2. 248oF = ? oC
3. 427oK = ? oF
Your Answer:
Kelvin is the
larger
Fahrenheit is
the middle
Celcius is the
smaller
1.) 78oC = 351 oK
Add:
273+78 = 351K
2.) 248oF = 120 oC
, Subtract 32 then divide by 1.8
248-32= 216
Now divide 216/1.8
=120
3.) 427oK = 309.2 oF
Kelvin to Fahrenheit needs to convert K
to C then continue equation. 427-273 =
154oC
Celsius to Fahrenheit needs to
multiply first then add 32 154 x
1.8 = 277.2
add 32
= 309.2
Question 4
pts
EXAM STUDY GUIDE
MODULES
1-6
MODULE 1
– EXAM
Question 1 – Section 1.1
pts
Complete the two problems below:
1. Convert 1005.3 to exponential form and explain your answer.
2. Convert 4.87 x 10-6 to ordinary
form and explain your answer. Your
Answer:
1.) Convert 1005.3 to exponential form and explain your answer:
All number values must be between 1-10. Because this value is greater than 1, the exponent remains
positive.
In order for this to happen, we have to move the decimal three places to the LEFT thus, the exponential
form of 1005.3 is: 1.0053 X 103
2.) Convert 4.87 x 10-6 to ordinary form and explain your answer.
All number values must be between 1-10. Because this value has a
negative exponent, the final answer will be less than 1. In order for this
to happen, we have to move the decimal six places to the LEFT thus:
0.00000487
,Question 2
pts
Complete the two problems below:
Using the following information, do the conversions shown below, showing all work:
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts
1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints
kilo (= 1000) milli (= 1/1000) centi (= 1/100) deci (= 1/10)
1. 3.6 pounds = ? oz
2. 2680 ml =
? liters Your
Answer:
1.) 3.6 pounds = 57.6 oz
1lb = 16oz
3.6(16) / 1 =57.6 oz
2.) 2680 ml = 2.68 liters
New/Old
Liters/Millilit
ers
,1L = 1,000mL
2,680/1,000
=2.68
Question 3
pts
Do the conversions shown below, showing all work:
1. 78oC = ? oK
2. 248oF = ? oC
3. 427oK = ? oF
Your Answer:
Kelvin is the
larger
Fahrenheit is
the middle
Celcius is the
smaller
1.) 78oC = 351 oK
Add:
273+78 = 351K
2.) 248oF = 120 oC
, Subtract 32 then divide by 1.8
248-32= 216
Now divide 216/1.8
=120
3.) 427oK = 309.2 oF
Kelvin to Fahrenheit needs to convert K
to C then continue equation. 427-273 =
154oC
Celsius to Fahrenheit needs to
multiply first then add 32 154 x
1.8 = 277.2
add 32
= 309.2
Question 4
pts
