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CHEM 103 M5: EXAM- REQUIRES RESPONDUS LOCKDOWN BROWSER PORTAGE LEARNING

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CHEM 103 M5: EXAM- REQUIRES RESPONDUS LOCKDOWN BROWSER PORTAGE LEARNING ● Due No due date ● Points 100 ● Questions 10 ● Time Limit 120 Minutes ● Requires Respondus LockDown Browser Attempt History Attempt Time Score KEPT Attempt 2 5 minutes 77 out of 100 LATEST Attempt 2 5 minutes 77 out of 100 Attempt 1 24 minutes 57 out of 100 Score for this quiz: 77 out of 100 Submitted Sep 17 at 10:07am This attempt took 5 minutes. UnansweredQuestion 1 10 / 10 pts Click this link to access the Periodic Table. This may be helpful throughout the exam. Show the determination of the charge on the ion formed by the K19 atom. Your Answer: K19 (metal = lose electrons) 1s2 2s2 2p6 3s2 3p6 4s1 lose 1e → K+1 Question 2 10 / 10 pts Click this link to access the Periodic Table. This may be helpful throughout the exam. H = 2.1

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CHEM 103 M5: EXAM- REQUIRES RESPONDUS LOCKDOWN
BROWSER PORTAGE LEARNING




● Due No due date
● Points 100
● Questions 10
● Time Limit 120 Minutes
● Requires Respondus LockDown Browser

Attempt History
Attempt Time Score

KEPT Attempt 2 5 minutes 77 out of 100

LATEST Attempt 2 5 minutes 77 out of 100

Attempt 1 24 minutes 57 out of 100
Score for this quiz: 77 out of 100
Submitted Sep 17 at 10:07am
This attempt took 5 minutes.

UnansweredQuestion 1
pts

Click this link to access the Periodic Table. This may be helpful throughout the exam.



Show the determination of the charge on the ion formed by the K19 atom.

Your Answer:

K19 (metal = lose electrons) 1s2 2s2 2p6 3s2 3p6 4s1 lose 1e → K+1


Question 2
pts

Click this link to access the Periodic Table. This may be helpful throughout the exam.



H = 2.1
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, Li = 1.0 Be = 1.5 B = 2.0 C = 2.5 N = 3.0 O= 3.5 F = 4.0

Na = 1.0 Mg = 1.2 Al = 1.5 Si = 1.8 P = 2.1 S = 2.5 Cl =
3.0

K = 0.8 Ca = 1.0 Ga = 1.6 Ge = 1.8 As = 2.0 Se = 2.4 Br =
2.8



Using the electronegativities from the table above, show the determination of the polarity of
each different type of bond in the following molecule




Your Answer:

H-O bond 3.5-2.1 = 1.4 so bond is polar range = 1.6-0.5 for polar

Br-O bond 2.8-2.1 =0.7 so bond is polar range = 1.6-0.5 for polar

H-O bond electronegativity difference = 3.5 - 2.1 = 1.4 1.6 - 0.5 bond is Polar

Br-O bond electronegativity difference = 3.5 - 2.8 = 0.7 1.6 - 0.5 bond is Polar


Question 3
pts

Click this link to access the Periodic Table. This may be helpful throughout the exam.



On a piece of scratch paper, draw the Lewis structure for the CO3-2 ion. Then choose the
correct Lewis structure for CO3-2 from the options listed below.




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