Nicet Level 1 - Water Based Layout exam
with complete solutions
Toggle ahangers ashall abe apermitted aonly afor athe asupport aof apipe a__________
ainches aor asmaller ain asize aunder aceilings aof ahollow atile aor ametal alath aand
aplaster. a- acorrect aanswers a-1 a2/2 ain. a(ref. aNFPA a13 a2016 aSec. a9.2.1.1.2.
While aconducting aa aflow atest, athe achosen ahydrant ashould abe a______ a- acorrect
aanswers a-As aclose ato athe aproperty awhere athe asprinkler asystem ais abeing
ainstalled. a(Ref, aNFPA a13 aSec. aA.24.2.2. aor aNFPA a291)
What aformula ais aused ato adetermine athe adischarge acoefficiant arelating apressure
aand aflow arate? a- acorrect aanswers a-K a= aQ a/ a(Square aroot aof aP)
, What abest adescribes aa atree asystem? a- acorrect aanswers a-Cross amains aand athe
abranch alines aare anot atied atogether, aproviding aonly aone apath aof awater aflow.
Factors athat adefine aOccupancy aGroup aHazard a2 ainclude: a- acorrect aanswers a-
Quantity aand acombustibility aof acontents aare amoderate ato ahigh.
Stockpiles aof acontents awith amoderate arates aof aheat arelease ado anot aexceed a12 aft
aand astockpiles awith ahigh aheat arelease ado anot aexceed a8 aft
(Ref aNFPA a13 aSec. a5.3.2)
Which aof athe afollowing astandards acontain areqs. apertaining ato athe ainstallation aof
aunderground apiping? a- acorrect aanswers a-NFPA a13 a& a24 a(Both ain aChapter a10)
Which aof athe afollowing ashould ayou ainspect aon aan aextension acord abefore aeach
ause? a- acorrect aanswers a-The agrounding aprong a& athe ainsulation afor anicks, acuts,
aor adamage
________ aindicates aa amandatory areq. aaccording ato aNFPA adefinitions. a- acorrect
aanswers a-Shall.
(Ref. aNFPA a13 a2016, aSec. a3.2.4.)
100 aGPM ais aflowing athrough a100' aof a1 a1/4 ain. aSch. a40 apipe. aHow amany afeet
aof a1 a1/2 ain. apipe awill aproduce athe asame afriction aloss? a- acorrect aanswers a-
Assume athis ais aSchedule a40 apipe, aC a= a120. aUse athe aHazen-Williams aformula
ato acalculate athe afriction aloss afor athe a1 a¼ ain. apipe aand athe a1 a½ ain. apipe.
For a1 a¼ ain. apipe a(ID a= a1.38):
P afriction aloss a= a4.52 ax aQ a1.85
c a1.85 ax ad a4.87
P afriction aloss a= a4.52 ax a100 a1.85
120 a1.85 ax a1.38 a4.87
P afriction aloss a= a0.672 apsi/ft
For a1 a½ ain. apipe a(ID a= a1.61):
with complete solutions
Toggle ahangers ashall abe apermitted aonly afor athe asupport aof apipe a__________
ainches aor asmaller ain asize aunder aceilings aof ahollow atile aor ametal alath aand
aplaster. a- acorrect aanswers a-1 a2/2 ain. a(ref. aNFPA a13 a2016 aSec. a9.2.1.1.2.
While aconducting aa aflow atest, athe achosen ahydrant ashould abe a______ a- acorrect
aanswers a-As aclose ato athe aproperty awhere athe asprinkler asystem ais abeing
ainstalled. a(Ref, aNFPA a13 aSec. aA.24.2.2. aor aNFPA a291)
What aformula ais aused ato adetermine athe adischarge acoefficiant arelating apressure
aand aflow arate? a- acorrect aanswers a-K a= aQ a/ a(Square aroot aof aP)
, What abest adescribes aa atree asystem? a- acorrect aanswers a-Cross amains aand athe
abranch alines aare anot atied atogether, aproviding aonly aone apath aof awater aflow.
Factors athat adefine aOccupancy aGroup aHazard a2 ainclude: a- acorrect aanswers a-
Quantity aand acombustibility aof acontents aare amoderate ato ahigh.
Stockpiles aof acontents awith amoderate arates aof aheat arelease ado anot aexceed a12 aft
aand astockpiles awith ahigh aheat arelease ado anot aexceed a8 aft
(Ref aNFPA a13 aSec. a5.3.2)
Which aof athe afollowing astandards acontain areqs. apertaining ato athe ainstallation aof
aunderground apiping? a- acorrect aanswers a-NFPA a13 a& a24 a(Both ain aChapter a10)
Which aof athe afollowing ashould ayou ainspect aon aan aextension acord abefore aeach
ause? a- acorrect aanswers a-The agrounding aprong a& athe ainsulation afor anicks, acuts,
aor adamage
________ aindicates aa amandatory areq. aaccording ato aNFPA adefinitions. a- acorrect
aanswers a-Shall.
(Ref. aNFPA a13 a2016, aSec. a3.2.4.)
100 aGPM ais aflowing athrough a100' aof a1 a1/4 ain. aSch. a40 apipe. aHow amany afeet
aof a1 a1/2 ain. apipe awill aproduce athe asame afriction aloss? a- acorrect aanswers a-
Assume athis ais aSchedule a40 apipe, aC a= a120. aUse athe aHazen-Williams aformula
ato acalculate athe afriction aloss afor athe a1 a¼ ain. apipe aand athe a1 a½ ain. apipe.
For a1 a¼ ain. apipe a(ID a= a1.38):
P afriction aloss a= a4.52 ax aQ a1.85
c a1.85 ax ad a4.87
P afriction aloss a= a4.52 ax a100 a1.85
120 a1.85 ax a1.38 a4.87
P afriction aloss a= a0.672 apsi/ft
For a1 a½ ain. apipe a(ID a= a1.61):
