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CHEM 219 Module 1 problem set Exam Questions With Solved Solution Rated A+

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Classify the bonding between the given pairs of atoms as ionic, covalent, or polar covalent. Use the table of electronegativities shown below to help with the classification. a. Br and Br b. K and Cl c. P and Cl d. C and O e. Na and Br - ACCURATE ANSWER-a. Br-Br: Electronegativity difference () = 0 = COVALENT (or pure covalent) b. K-Cl: () = 2.2 = IONIC c. P-Cl: ()= 0.9 = POLAR COVALENT d. C-O: ()= 1.0 = POLAR COVALENT e. Na-Br: () = 1.8 = POLAR COVALENT Define the term constitutional isomer. - ACCURATE ANSWER-Two (or more) different chemical compounds with the same molecular formula but different connectivity between the atoms in their structural formulae. On a piece of scratch paper, write out the Lewis Dot Diagram for each of the indicated elements and determine the following for each: a) The number of Lone Pairs the atom possesses in its valence shell.b) The number of Unpaired Electrons the atom possesses in its valence shell.c) The number of bonds the atom will form. Oxygen Carbon Hydrogen Nitrogen - ACCURATE ANSWER-Oxygen - a) 2 b) 2 c) 2 Carbon - a) 0 b) 4 c) 4 Hydrogen- a) 0 b) 1 c) 1 Nitrogen - a) 1 b) 3 c) 3 Explain (using specific evidence) what makes the following two compounds constitutional isomers of one another: - ACCURATE ANSWER-Both compounds have a MF of C3H6O - same MF. Compound "a" has a 3-carbon chain with a C=O in the middle. No H atom connected to C of C=O. Compound "b" has a 3-carbon chain with a C=O at the end. There is an H attached to the C of the C=O.

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Institution
CHEM 219 Module 1 Problem Set
Course
CHEM 219 Module 1 problem set

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CHEM 219 Module 1 problem set Exam
Questions With Solved Solution Rated
A+

Classify the bonding between the given pairs of atoms as ionic, covalent, or polar
covalent. Use the table of electronegativities shown below to help with the classification.



a. Br and Br

b. K and Cl

c. P and Cl

d. C and O

e. Na and Br - ACCURATE ANSWER-a. Br-Br: Electronegativity difference () = 0 =
COVALENT (or pure covalent)

b. K-Cl: () = 2.2 = IONIC

c. P-Cl: ()= 0.9 = POLAR COVALENT

d. C-O: ()= 1.0 = POLAR COVALENT

e. Na-Br: () = 1.8 = POLAR COVALENT



Define the term constitutional isomer. - ACCURATE ANSWER-Two (or more) different
chemical compounds with the same molecular formula but different connectivity
between the atoms in their structural formulae.

On a piece of scratch paper, write out the Lewis Dot Diagram for each of the indicated
elements and determine the following for each:

a) The number of Lone Pairs the atom possesses in its valence shell.b) The number of
Unpaired Electrons the atom possesses in its valence shell.c) The number of bonds the
atom will form.

, Oxygen

Carbon

Hydrogen

Nitrogen - ACCURATE ANSWER-Oxygen - a) 2 b) 2 c) 2

Carbon - a) 0 b) 4 c) 4

Hydrogen- a) 0 b) 1 c) 1

Nitrogen - a) 1 b) 3 c) 3




Explain (using specific evidence) what makes the following two compounds
constitutional isomers of one another: - ACCURATE ANSWER-Both compounds have a
MF of C3H6O - same MF.

Compound "a" has a 3-carbon chain with a C=O in the middle. No H atom connected to
C of C=O.

Compound "b" has a 3-carbon chain with a C=O at the end. There is an H attached to
the C of the C=O.



What is the relationship between the compounds shown? Are they the same compound,
constitutional isomers, or two different compounds that are not related to one another?
Explain. - ACCURATE ANSWER-Different compounds that are not related. They have
different MF - (a) C3H8O, (b) C3H6O.



Identify each of the following carbon skeletons as linear (continuous), branched, or
cyclic. - ACCURATE ANSWER-a) Branched

b) Linear (continuous)

c) Cyclic

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CHEM 219 Module 1 problem set
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CHEM 219 Module 1 problem set

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