Written by students who passed Immediately available after payment Read online or as PDF Wrong document? Swap it for free 4.6 TrustPilot
logo-home
Document preview thumbnail
Preview 2 out of 12 pages
Exam (elaborations)

CSE 2221 Midterm 2 Exam Guide 2025. | Exam Revision Questions And Correct Answers | Graded A+ | 2025 Update |

Document preview thumbnail
Preview 2 out of 12 pages

CSE 2221 Midterm 2 Exam Guide 2025. | Exam Revision Questions And Correct Answers | Graded A+ | 2025 Update |

Content preview

CSE 2221 Midterm 2 Exam Guide 2025. | Exam Revision Questions And
Correct Answers | Graded A+ | 2025 Update |




XMLTree Method .label() - ANSWER- Returns the name of the root of the tree in the form of
a string


XMLTree Method .hasTag() - ANSWER- Returns true if the XMLTree is a tag node and not a
text node


XMLMethod .hasAttribute(String name) - ANSWER- Returns true if the XMLTree has an
attribute with the label of name


XMLTree Method .attributeValue(String name) - ANSWER- Returns the string value of the
attribute whose label is name


XMLTree Method .numberOfChildren() - ANSWER- Returns the number of direct children of
the XMLTree


XMLTree .child(int k) - ANSWER- Returns the XMLTree that is the kth child of the XMLTree
used


XMLTree toString() - ANSWER- Returns the XMLTree in the form of a string



NaturalNumber n = new NaturalNumber2() - ANSWER- n=0



NaturalNumber n = new NaturalNumber2(int k) - ANSWER- n=k



NaturalNumber n = new NaturalNumber2(NaturalNumber m) - ANSWER- n=m

, NaturalNumber n = new NaturalNumber2("32") - ANSWER- n = 32



n.add(NaturalNumber k); - ANSWER- n=n+k



n.subtract(NaturalNumber k); - ANSWER- n=n-k



n.multiply(NaturalNumber k); - ANSWER- n=n*k



NaturalNumber r = n.divide(NaturalNumber k); - ANSWER- n = n/k
k=k
r=n%k


n.power(NaturalNumber k); - ANSWER- n=n^k



n.root(k) - ANSWER- n = n ^ (1 / k). If n is say 24 and k = 2, n will be 4 after the method call
because n always rounds down if it's not a perfect square, cube, etc.


n.copyFrom(k) - ANSWER- n=k
k=k


int comp = n.compareTo(k); - ANSWER- comp = positive integer if n > k or negative integer
if n < k or 0 if n = k


n.multiplyBy10(k); - ANSWER- n = (#n * 10) + k



int r = n.divideBy10(); - ANSWER- r = n % 10;
n = n / 10

Document information

Uploaded on
June 1, 2025
Number of pages
12
Written in
2024/2025
Type
Exam (elaborations)
Contains
Questions & answers
$12.99

Wrong document? Swap it for free Within 14 days of purchase and before downloading, you can choose a different document. You can simply spend the amount again.
Written by students who passed
Immediately available after payment
Read online or as PDF

Seller avatar
Reputation scores are based on the amount of documents a seller has sold for a fee and the reviews they have received for those documents. There are three levels: Bronze, Silver and Gold. The better the reputation, the more your can rely on the quality of the sellers work.
LECTpharis
4.8
(8)
Sold
41
Followers
1
Items
6040
Last sold
2 months ago




Why students choose Stuvia

Created by fellow students, verified by reviews

Quality you can trust: written by students who passed their tests and reviewed by others who've used these notes.

Didn't get what you expected? Choose another document

No worries! You can instantly pick a different document that better fits what you're looking for.

Pay as you like, start learning right away

No subscription, no commitments. Pay the way you're used to via credit card and download your PDF document instantly.

Student with book image

“Bought, downloaded, and aced it. It really can be that simple.”

Alisha Student

Working on your references?

Create accurate citations in APA, MLA and Harvard with our free citation generator.

Working on your references?

Frequently asked questions