ZOL3702
ASSIGNMENT 1 2025
UNIQUE NO. 218877
DUE DATE: 25 MAY 2025
, QUESTION 1: Occam’s Razor
Occam’s Razor is a principle that helps us choose between different explanations or
theories. It says that the simplest explanation—the one with the fewest assumptions—is
usually the best. So, instead of complicating things with too many details, we should go
with the answer that makes the most sense in the easiest way.
QUESTION 2: Graph and Calculations
We are told that animal numbers increase with food availability in a straight line. The
equation is:
y = 0.5x + 10
Where:
x = food availability
y = number of animals
2.1 Graph of the relationship:
See the attached graph image below to visualise how the number of animals rises as
more food becomes available.
📎 Download here: Q2.1_Food_vs_Animals.png
2.2 Predictions based on the equation:
a) Food = 5 units
y = 0.5(5) + 10 = 2.5 + 10 = 12.5 animals
b) Food = 20 units
y = 0.5(20) + 10 = 10 + 10 = 20 animals
ASSIGNMENT 1 2025
UNIQUE NO. 218877
DUE DATE: 25 MAY 2025
, QUESTION 1: Occam’s Razor
Occam’s Razor is a principle that helps us choose between different explanations or
theories. It says that the simplest explanation—the one with the fewest assumptions—is
usually the best. So, instead of complicating things with too many details, we should go
with the answer that makes the most sense in the easiest way.
QUESTION 2: Graph and Calculations
We are told that animal numbers increase with food availability in a straight line. The
equation is:
y = 0.5x + 10
Where:
x = food availability
y = number of animals
2.1 Graph of the relationship:
See the attached graph image below to visualise how the number of animals rises as
more food becomes available.
📎 Download here: Q2.1_Food_vs_Animals.png
2.2 Predictions based on the equation:
a) Food = 5 units
y = 0.5(5) + 10 = 2.5 + 10 = 12.5 animals
b) Food = 20 units
y = 0.5(20) + 10 = 10 + 10 = 20 animals
