Oxford Cambridge and RSA
INSTRUCTIONS
• Do not send this Equation Sheet for marking. Keep it in the centre or recycle it.
INFORMATION
• This Equation Sheet is for the June 2024 examination series only.
• This Equation Sheet has 4 pages.
OCR is an exempt Charity
Turn over
,© OCR 2024
Key: HT = Higher Tier only
Equations in physics
P1 Matter
mass
density = ρ=m
volume V
change in thermal energy = mass × specific heat capacity × change in temperature ΔE = mc Δθ
thermal energy for a change in state = mass × specific latent heat E = ml
for a given mass of gas at a constant temperature: pressure ×
p V = constant
volume = constant
HT pressure due to a column of liquid = height of column × density of liquid × gravitational field strength p = hρg
J249 01/02/03/04
2
P2 Forces
distance travelled = speed × time s = vt
change in velocity v–u
acceleration = a=
time t
(final velocity)2 – (initial velocity)2 = 2 × acceleration × distance v2 – u 2 = 2 as
1 1
kinetic energy = × mass × (speed)2 E = m v2
2 2
force = mass × acceleration F = ma
HT momentum = mass × velocity p = mv
work done = force × distance (along the line of action of the force) W = Fs
work done W
P=
power = time t
,© OCR 2024
P2 Forces
force exerted by a spring = spring constant × extension F = kx
1 1
energy transferred in stretching = × spring constant × (extension)2 E = k x2
2 2
gravitational force = mass × gravitational field strength W = mg
gravitational potential energy = mass × gravitational field strength × height E = mgh
force normal to a surface F
p=
pressure = A
area of that surface
moment of a force = force × distance (normal to direction of the force) M = Fd
P3 Electricity
J249 01/02/03/04
charge flow = current × time Q = It
3
potential difference = current × resistance V = IR
energy transferred = charge × potential difference E = QV
power = potential difference × current P = VI
power = (current)2 × resistance P = I2 R
energy transferred = power × time E = Pt
P4 Magnetism and magnetic fields
HT force on a conductor (at right angles to a magnetic field) carrying a current: force =
F = BIl
magnetic flux density × current × length
HT potential difference across primary coil number of turns in primary coil Vp Np
= =
potential difference across secondary coil number of turns in secondary coil V N
s s
Turn over
, © OCR 2024
P5 Waves in matter
wave speed = frequency × wavelength v = fλ
P7 Energy
useful output energy transfer
efficiency =
input energy transfer
P8 Global challenges
potential difference across primary coil × current in primary coil = potential difference across secondary coil × current in secondary coil Vp Ip = Vs Is
J249 01/02/03/04
4
Oxford Cambridge and RSA
Copyright Information
OCR is committed to seeking permission to reproduce all third-party content that it uses in its assessment materials. OCR has attempted to identify and contact all copyright holders whose work is used in this paper. To avoid the issue of disclosure of answer-related information to candidates, all
copyright acknowledgements are reproduced in the OCR Copyright Acknowledgements Booklet. This is produced for each series of examinations and is freely available to download from our public website (www.ocr.org.uk) after the live examination series.
If OCR has unwittingly failed to correctly acknowledge or clear any third-party content in this assessment material, OCR will be happy to correct its mistake at the earliest possible opportunity. For queries or
further information please contact The OCR Copyright Team, The Triangle Building, Shaftesbury Road, Cambridge CB2 8EA.
OCR is part of Cambridge University Press & Assessment, which is itself a department of the University of Cambridge.
INSTRUCTIONS
• Do not send this Equation Sheet for marking. Keep it in the centre or recycle it.
INFORMATION
• This Equation Sheet is for the June 2024 examination series only.
• This Equation Sheet has 4 pages.
OCR is an exempt Charity
Turn over
,© OCR 2024
Key: HT = Higher Tier only
Equations in physics
P1 Matter
mass
density = ρ=m
volume V
change in thermal energy = mass × specific heat capacity × change in temperature ΔE = mc Δθ
thermal energy for a change in state = mass × specific latent heat E = ml
for a given mass of gas at a constant temperature: pressure ×
p V = constant
volume = constant
HT pressure due to a column of liquid = height of column × density of liquid × gravitational field strength p = hρg
J249 01/02/03/04
2
P2 Forces
distance travelled = speed × time s = vt
change in velocity v–u
acceleration = a=
time t
(final velocity)2 – (initial velocity)2 = 2 × acceleration × distance v2 – u 2 = 2 as
1 1
kinetic energy = × mass × (speed)2 E = m v2
2 2
force = mass × acceleration F = ma
HT momentum = mass × velocity p = mv
work done = force × distance (along the line of action of the force) W = Fs
work done W
P=
power = time t
,© OCR 2024
P2 Forces
force exerted by a spring = spring constant × extension F = kx
1 1
energy transferred in stretching = × spring constant × (extension)2 E = k x2
2 2
gravitational force = mass × gravitational field strength W = mg
gravitational potential energy = mass × gravitational field strength × height E = mgh
force normal to a surface F
p=
pressure = A
area of that surface
moment of a force = force × distance (normal to direction of the force) M = Fd
P3 Electricity
J249 01/02/03/04
charge flow = current × time Q = It
3
potential difference = current × resistance V = IR
energy transferred = charge × potential difference E = QV
power = potential difference × current P = VI
power = (current)2 × resistance P = I2 R
energy transferred = power × time E = Pt
P4 Magnetism and magnetic fields
HT force on a conductor (at right angles to a magnetic field) carrying a current: force =
F = BIl
magnetic flux density × current × length
HT potential difference across primary coil number of turns in primary coil Vp Np
= =
potential difference across secondary coil number of turns in secondary coil V N
s s
Turn over
, © OCR 2024
P5 Waves in matter
wave speed = frequency × wavelength v = fλ
P7 Energy
useful output energy transfer
efficiency =
input energy transfer
P8 Global challenges
potential difference across primary coil × current in primary coil = potential difference across secondary coil × current in secondary coil Vp Ip = Vs Is
J249 01/02/03/04
4
Oxford Cambridge and RSA
Copyright Information
OCR is committed to seeking permission to reproduce all third-party content that it uses in its assessment materials. OCR has attempted to identify and contact all copyright holders whose work is used in this paper. To avoid the issue of disclosure of answer-related information to candidates, all
copyright acknowledgements are reproduced in the OCR Copyright Acknowledgements Booklet. This is produced for each series of examinations and is freely available to download from our public website (www.ocr.org.uk) after the live examination series.
If OCR has unwittingly failed to correctly acknowledge or clear any third-party content in this assessment material, OCR will be happy to correct its mistake at the earliest possible opportunity. For queries or
further information please contact The OCR Copyright Team, The Triangle Building, Shaftesbury Road, Cambridge CB2 8EA.
OCR is part of Cambridge University Press & Assessment, which is itself a department of the University of Cambridge.
