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Basic Math Ability Exam ACTUAL EXAM QUESTIONS AND CORRECT DETAILED ANSWERS (VERIFIED ANSWERS) |ALREADY GRADED A+

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Basic Math Ability Exam ACTUAL EXAM QUESTIONS AND CORRECT DETAILED ANSWERS (VERIFIED ANSWERS) |ALREADY GRADED A+ When asked to round a place, only look at the digit next to the place. - CORRECT ANSWER Rounding {3,4,5} {5,12,13} {8,15,17} {7,24,25} - CORRECT ANSWER Pythagorean Triplet If the sides given are larger, divide down by the greatest common factor. Do the computations in the smaller triangle and then scale back up. - CORRECT ANSWER Right angled Triangle Similar figures have the same shape but different sizes. The angles in similar figures are always equal. We can prove two triangles are similar if they simply share two angles. Sides in similar figures are proportional. The scale factor k, is the factor by which all lengths in the smaller figure were multiplied to arrive at the lengths in the larger figure. If all the lengths are multiplied by k, then the area is multiplied by k squared, the scale factor squared. - CORRECT ANSWER Similar Triangles Angles= 45-45-90; sides= 1-1-√(2) - CORRECT ANSWER Isosceles Right Triangle We get this by diving an equilateral triangle in half. Has sides 1-√(3)-2. - CORRECT ANSWER 30-60-90 triangle The average of a group of consecutive integers is equal to the average of the smallest and largest numbers. - CORRECT ANSWER Average(Arithmetic Mean) Tips A=RT For problems with multiple workers or machines, create rates for each one and then add the rates. - CORRECT ANSWER Work Problems

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Basic Math Ability Exam ACTUAL EXAM QUESTIONS AND
CORRECT DETAILED ANSWERS (VERIFIED ANSWERS)
|ALREADY GRADED A+




When asked to round a place, only look at the digit next to the place. - CORRECT
ANSWER Rounding
{3,4,5}
{5,12,13}
{8,15,17}
{7,24,25} - CORRECT ANSWER Pythagorean Triplet
If the sides given are larger, divide down by the greatest common factor. Do the
computations in the smaller triangle and then scale back up. - CORRECT
ANSWER Right angled Triangle
Similar figures have the same shape but different sizes.
The angles in similar figures are always equal.
We can prove two triangles are similar if they simply share two angles.
Sides in similar figures are proportional.
The scale factor k, is the factor by which all lengths in the smaller figure were multiplied
to arrive at the lengths in the larger figure.
If all the lengths are multiplied by k, then the area is multiplied by k squared, the scale
factor squared. - CORRECT ANSWER Similar Triangles

Angles= 45-45-90; sides= 1-1-√(2) - CORRECT ANSWER Isosceles Right
Triangle

We get this by diving an equilateral triangle in half.
Has sides 1-√(3)-2. - CORRECT ANSWER 30-60-90 triangle

The average of a group of consecutive integers is equal to the average of the smallest
and largest numbers. - CORRECT ANSWER Average(Arithmetic Mean) Tips

A=RT
For problems with multiple workers or machines, create rates for each one and then add
the rates. - CORRECT ANSWER Work Problems

, All even numbers(last digit is even) - CORRECT ANSWER Divisibility rule for 2

If the sum of the digits is divisible by 3 then the number is divisible by 3 - CORRECT
ANSWER Divisibility for 3
If last two digits are divisible by 4 then the whole number is divisible by 4. -
CORRECT ANSWER divisibility for 4

Last digit is 5 or 0 - CORRECT ANSWER Divisibility by 5

No. should be divisible by 2 and 3 - CORRECT ANSWER Divisibility by 6

If the sum of the digits is divisible by 9 then the number is divisible by 9 - CORRECT
ANSWER Divisibility by 9
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59

1 is not a prime number
2 is the only even prime number
to check if a no. <100 is prime check whether it is divisible by 2 3 5 and 7. -
CORRECT ANSWER Prime numbers

D= RT - CORRECT ANSWER Motion Problems
20% : 0.2: 1/5
25%: 0.25: 1/4
50%: 0.5: 1/2
60%: 0.6: 3/5
75%:0.75:3/4 - CORRECT ANSWER Percentage:decimal:fraction

nCr= (first r values of n!)/r! - CORRECT ANSWER Easy nCr formula
n!=n(n-1)!
nCr=nCn-r
nC1= n - CORRECT ANSWER Factorials
If there are n items with b identical items then the total no. of arrangements is,
N=n!/b!
or if there are b identical items,different group of c identical items,d identical items then,

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