Percent Composition - correct answer -%E = (mass of E / mass of sample) X
| | | | | | | | | | | | | |
100%
|
Avogadro's number - correct answer -6.022 X 10²³ particles or 1 mole
| | | | | | | | | | |
Molar Mass (MM) - correct answer -The average mass of an atom of any
| | | | | | | | | | | | |
substances as the mass of 1 mole.
| | | | | | |
ex. Carbon is 12.01 g/mol
| | | |
ex. Oxygen is 16.00 g/mol
| | | |
CO₂ is 44.01 g/mol
| | |
Mass in grams X molar mass - correct answer -equals moles
| | | | | | | | | |
Moles X molar mass - correct answer -equals mass in grams
| | | | | | | | | |
1 mole - correct answer -6.022 X 10²³
| | | | | | |
Empirical formula - correct answer -Expresses the simplest ratio of atoms in a
| | | | | | | | | | | |
compound and written with the smallest whole-number subscripts. ex. C₅H₁₀ →
| | | | | | | | | | |
CH²
|
, Molecular formula - correct answer -Expresses the actual number of atoms in a
| | | | | | | | | | | |
compound and can have the same subscripts as the empirical formula or some
| | | | | | | | | | | | |
multiple of them.
| | |
Finding Empirical - correct answer -1. Assume any size sample is 100 grams so %
| | | | | | | | | | | | | |
value =mass value.
| | |
2. Convert grams to moles for each element using its molar mass as a
| | | | | | | | | | | | |
conversion factor.
| |
3. Without changing the relative amounts, change moles to whole numbers. Do
| | | | | | | | | | |
this by dividing all by the same smallest value. If all do not convert to whole
| | | | | | | | | | | | | | | |
numbers, multiply to get whole numbers
| | | | | |
Percent Mass Solute (solution concentration formula) - correct answer -(mass
| | | | | | | | |
of solute / total mass of solution) X 100
| | | | | | | | |
Concentration - correct answer -Ratio of solute to solvent | | | | | | | |
Molarity (M) - correct answer -Molarity = (moles of solute / liters of solution)
| | | | | | | | | | | | |
Another way to express the concentration of a solution
| | | | | | | |
Dilution - correct answer -M (initial) V (initial) = M (final) V (final)
| | | | | | | | | | | |
chemical reaction - correct answer -it is chemical change and occurs when one
| | | | | | | | | | | |
or more substances is
| | | |
converted into one or more new substances.
| | | | | |
| | | | | | | | | | | | | |
100%
|
Avogadro's number - correct answer -6.022 X 10²³ particles or 1 mole
| | | | | | | | | | |
Molar Mass (MM) - correct answer -The average mass of an atom of any
| | | | | | | | | | | | |
substances as the mass of 1 mole.
| | | | | | |
ex. Carbon is 12.01 g/mol
| | | |
ex. Oxygen is 16.00 g/mol
| | | |
CO₂ is 44.01 g/mol
| | |
Mass in grams X molar mass - correct answer -equals moles
| | | | | | | | | |
Moles X molar mass - correct answer -equals mass in grams
| | | | | | | | | |
1 mole - correct answer -6.022 X 10²³
| | | | | | |
Empirical formula - correct answer -Expresses the simplest ratio of atoms in a
| | | | | | | | | | | |
compound and written with the smallest whole-number subscripts. ex. C₅H₁₀ →
| | | | | | | | | | |
CH²
|
, Molecular formula - correct answer -Expresses the actual number of atoms in a
| | | | | | | | | | | |
compound and can have the same subscripts as the empirical formula or some
| | | | | | | | | | | | |
multiple of them.
| | |
Finding Empirical - correct answer -1. Assume any size sample is 100 grams so %
| | | | | | | | | | | | | |
value =mass value.
| | |
2. Convert grams to moles for each element using its molar mass as a
| | | | | | | | | | | | |
conversion factor.
| |
3. Without changing the relative amounts, change moles to whole numbers. Do
| | | | | | | | | | |
this by dividing all by the same smallest value. If all do not convert to whole
| | | | | | | | | | | | | | | |
numbers, multiply to get whole numbers
| | | | | |
Percent Mass Solute (solution concentration formula) - correct answer -(mass
| | | | | | | | |
of solute / total mass of solution) X 100
| | | | | | | | |
Concentration - correct answer -Ratio of solute to solvent | | | | | | | |
Molarity (M) - correct answer -Molarity = (moles of solute / liters of solution)
| | | | | | | | | | | | |
Another way to express the concentration of a solution
| | | | | | | |
Dilution - correct answer -M (initial) V (initial) = M (final) V (final)
| | | | | | | | | | | |
chemical reaction - correct answer -it is chemical change and occurs when one
| | | | | | | | | | | |
or more substances is
| | | |
converted into one or more new substances.
| | | | | |
