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Nicet Level 1 - Water Based Layout Practice Questions and Answers LATEST UPDATE GRADED A+ | ASSURED SUCCESS

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28/12/2024, 19:54 Nicet Level 1 - Water Based Layout Practice Questions and Answers 2025-2026 LATEST UPDATE GRADED A+ | ASSURED SUC…




Nicet Level 1 - Water Based Layout Practice
Questions and Answers 2025-2026 LATEST
UPDATE GRADED A+ | ASSURED SUCCESS


Practice questions for this set


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Terms in this set (64)

Toggle hangers shall be 1 2/2 in. (ref. NFPA 13 2016 Sec. 9.2.1.1.2.
permitted only for the
support of pipe __________
inches or smaller in size
under ceilings of hollow
tile or metal lath and
plaster.

While conducting a flow As close to the property where the sprinkler system is
test, the chosen hydrant being installed. (Ref, NFPA 13 Sec. A.24.2.2. or NFPA
should be ______ 291)




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,28/12/2024, 19:54 Nicet Level 1 - Water Based Layout Practice Questions and Answers 2025-2026 LATEST UPDATE GRADED A+ | ASSURED SUC…

What formula is used to K = Q / (Square root of P)
determine the discharge
coefficiant relating
pressure and flow rate?

What best describes a tree Cross mains and the branch lines are not tied
system? together, providing only one path of water flow.

Quantity and combustibility of contents are moderate
to high.

Factors that define
Stockpiles of contents with moderate rates of heat
Occupancy Group Hazard
release do not exceed 12 ft and stockpiles with high
2 include:
heat release do not exceed 8 ft


(Ref NFPA 13 Sec. 5.3.2)

Which of the following NFPA 13 & 24 (Both in Chapter 10)
standards contain reqs.
pertaining to the
installation of
underground piping?

Which of the following The grounding prong & the insulation for nicks, cuts,
should you inspect on an or damage
extension cord before
each use?

________ indicates a Shall.
mandatory req. according
to NFPA definitions. (Ref. NFPA 13 2016, Sec. 3.2.4.)




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, 28/12/2024, 19:54 Nicet Level 1 - Water Based Layout Practice Questions and Answers 2025-2026 LATEST UPDATE GRADED A+ | ASSURED SUC…

Assume this is Schedule 40 pipe, C = 120. Use the
Hazen-Williams formula to calculate the friction loss
for the 1 ¼ in. pipe and the 1 ½ in. pipe.


For 1 ¼ in. pipe (ID = 1.38):



P friction loss = 4.52 x Q 1.85


c 1.85 x d 4.87



P friction loss = 4.52 x 100 1.85


120 1.85 x 1.38 4.87


P friction loss = 0.672 psi/ft



For 1 ½ in. pipe (ID = 1.61):



100 GPM is flowing
P friction loss = 4.52 x Q 1.85
through 100' of 1 1/4 in.
Sch. 40 pipe. How many
c 1.85 x d 4.87
feet of 1 1/2 in. pipe will
produce the same friction
P friction loss = 4.52 x 100 1.85
loss?

120 1.85 x 1.61 4.87



P friction loss = 0.317 psi/ft



Step #2: Determine the total friction loss for 100 gpm
flowing through 100 ft. of 1 ¼ in. Schedule 40 black
steel pipe: 100 ft. x 0.672 psi/ft = 67.2 psi

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