Solutions Manual B
to accompany
B
STATISTICS FOR ENGINEERS
B B
BAND SCIENTISTS
B
Fourth Edition
B
by
William Navidi B
, Table of Contents
B B
Chapter 1 ................................................................................................................... 1
B
Chapter 2 ................................................................................................................. 13
B
Chapter 3 ................................................................................................................. 54
B
Chapter 4 ................................................................................................................. 74
B
Chapter 5 ............................................................................................................... 116
B
Chapter 6 ............................................................................................................... 135
B
Chapter 7 ............................................................................................................... 171
B
Chapter 8 ............................................................................................................... 191
B
Chapter 9 ............................................................................................................... 210
B
Chapter 10 ............................................................................................................. 230
B
,SECTION B1.1 1
Chapter 1 B
Section 1.1 B
1. (a) BThe Bpopulation Bconsists Bof Ball Bthe Btimes Bthe Bprocess Bcould Bbe Brun. BIt Bis Bconceptual.
(b) The Bpopulation Bconsist Bof Ball Bthe Bregistered Bvoters Bin Bthe Bstate. BIt Bis Btangible.
(c) The Bpopulation Bconsist Bof Ball Bpeople Bwith Bhigh Bcholesterol Blevels. BIt Bis Btangible.
(d) The Bpopulation Bconsist Bof Ball Bconcrete Bspecimens Bthat Bcould Bbe Bmade Bfrom Bthe Bnew Bformulation. B It Bis Bconceptual.
(e) The Bpopulation Bconsist Bof Ball Bbolts Bmanufactured Bthat Bday. BIt Bis Btangible.
3. B(a) BFalse
(b) BTrue
5. (a) BNo. B What Bis Bimportant Bis Bthe Bpopulation Bproportion Bof Bdefectives; Bthe Bsample Bproportion Bis Bonly
Ban Bapprox- Bimation. B The Bpopulation Bproportion Bfor Bthe Bnew Bprocess Bmay Bin Bfact Bbe Bgreater Bor
Bless Bthan Bthat Bof Bthe Bold Bprocess.
(b) No. B The Bpopulation Bproportion Bfor Bthe Bnew Bprocess Bmay Bbe B0.12 Bor Bmore, Beven Bthough Bthe
Bsample Bproportion Bwas Bonly B0.11.
(c) Finding B2 Bdefective Bcircuits Bin Bthe Bsample.
7. A Bgood Bknowledge Bof Bthe Bprocess Bthat Bgenerated Bthe Bdata.
9. B(a) BA Bcontrolled Bexperiment
(b) BIt Bis Bwell-justified, Bbecause Bit Bis Bbased Bon Ba Bcontrolled Bexperiment Brather Bthan Ban Bobservational Bstudy.
, 2 CHAPTER
B4
Section 1.2 B
1. False
3. No. BIn Bthe Bsample B1, B2, B4 Bthe Bmean Bis B7/3, Bwhich Bdoes Bnot Bappear Bat Ball.
5. The Bsample Bsize Bcan Bbe Bany Bodd Bnumber.
7. Yes. BIf Ball Bthe Bnumbers Bin Bthe Blist Bare Bthe Bsame, Bthe Bstandard Bdeviation Bwill Bequal B0.
9. The Bmean Band Bstandard Bdeviation Bboth Bincrease Bby B5%.
11. The Btotal Bheight Bof Bthe B20 Bmen Bis B20 B× B178 B= B3560. B The Btotal Bheight Bof Bthe B30 Bwomen Bis B30 B× B164 B= B4920.
The Btotal Bheight Bof Ball B50 Bpeople Bis B3560 B+ B4920 B= B8480. BThere Bare B20 B+ B30 B= B50 Bpeople Bin Btotal.
B Therefore Bthe Bmean Bheight Bfor Bboth Bgroups Bput Btogether Bis B8480/50 B= B169.6 Bcm.
13. B(a) BAll Bwould Bbe Bdivided Bby B2.54.
(b) BNot Bexactly Bthe Bsame, Bbecause Bthe Bmeasurements Bwould Bbe Ba Blittle Bdifferent Bthe Bsecond Btime.
15. (a) BThe Bsample Bsize Bis Bn B= B16. BThe Btertiles Bhave Bcutpoints B(1/3)(17) B= B5.67 Band B(2/3)(17) B= B11.33. BThe
Bfirst Btertile Bis Btherefore Bthe Baverage Bof Bthe Bsample Bvalues Bin Bpositions B5 Band B6, Bwhich Bis B(44 B+ B46)/2 B=
B45. B The Bsecond Btertile Bis Bthe Baverage Bof Bthe Bsample Bvalues Bin Bpositions B11 Band B12, Bwhich Bis B(76
B+ B79)/2 B= B77.5.
(b) The Bsample Bsize Bis Bn B= B16. BThe Bquintiles Bhave Bcutpoints B(i/5)(17) Bfor Bi B= B1, B2, B3, B4. B The Bquintiles
Bare Btherefore Bthe Baverages Bof Bthe Bsample Bvalues Bin Bpositions B3 Band B4, Bin Bpositions B6 Band B7, Bin
Bpositions B10 Band B11, Band Bin Bpositions B13 Band B14. B The Bquintiles Bare Btherefore B(23 B+ B41)/2 B= B32,
B(46 B+B49)/2 B= B47.5, B(74 B+B76)/2 B= B75, Band
(82 B+B89)/2 B= B85.5.
to accompany
B
STATISTICS FOR ENGINEERS
B B
BAND SCIENTISTS
B
Fourth Edition
B
by
William Navidi B
, Table of Contents
B B
Chapter 1 ................................................................................................................... 1
B
Chapter 2 ................................................................................................................. 13
B
Chapter 3 ................................................................................................................. 54
B
Chapter 4 ................................................................................................................. 74
B
Chapter 5 ............................................................................................................... 116
B
Chapter 6 ............................................................................................................... 135
B
Chapter 7 ............................................................................................................... 171
B
Chapter 8 ............................................................................................................... 191
B
Chapter 9 ............................................................................................................... 210
B
Chapter 10 ............................................................................................................. 230
B
,SECTION B1.1 1
Chapter 1 B
Section 1.1 B
1. (a) BThe Bpopulation Bconsists Bof Ball Bthe Btimes Bthe Bprocess Bcould Bbe Brun. BIt Bis Bconceptual.
(b) The Bpopulation Bconsist Bof Ball Bthe Bregistered Bvoters Bin Bthe Bstate. BIt Bis Btangible.
(c) The Bpopulation Bconsist Bof Ball Bpeople Bwith Bhigh Bcholesterol Blevels. BIt Bis Btangible.
(d) The Bpopulation Bconsist Bof Ball Bconcrete Bspecimens Bthat Bcould Bbe Bmade Bfrom Bthe Bnew Bformulation. B It Bis Bconceptual.
(e) The Bpopulation Bconsist Bof Ball Bbolts Bmanufactured Bthat Bday. BIt Bis Btangible.
3. B(a) BFalse
(b) BTrue
5. (a) BNo. B What Bis Bimportant Bis Bthe Bpopulation Bproportion Bof Bdefectives; Bthe Bsample Bproportion Bis Bonly
Ban Bapprox- Bimation. B The Bpopulation Bproportion Bfor Bthe Bnew Bprocess Bmay Bin Bfact Bbe Bgreater Bor
Bless Bthan Bthat Bof Bthe Bold Bprocess.
(b) No. B The Bpopulation Bproportion Bfor Bthe Bnew Bprocess Bmay Bbe B0.12 Bor Bmore, Beven Bthough Bthe
Bsample Bproportion Bwas Bonly B0.11.
(c) Finding B2 Bdefective Bcircuits Bin Bthe Bsample.
7. A Bgood Bknowledge Bof Bthe Bprocess Bthat Bgenerated Bthe Bdata.
9. B(a) BA Bcontrolled Bexperiment
(b) BIt Bis Bwell-justified, Bbecause Bit Bis Bbased Bon Ba Bcontrolled Bexperiment Brather Bthan Ban Bobservational Bstudy.
, 2 CHAPTER
B4
Section 1.2 B
1. False
3. No. BIn Bthe Bsample B1, B2, B4 Bthe Bmean Bis B7/3, Bwhich Bdoes Bnot Bappear Bat Ball.
5. The Bsample Bsize Bcan Bbe Bany Bodd Bnumber.
7. Yes. BIf Ball Bthe Bnumbers Bin Bthe Blist Bare Bthe Bsame, Bthe Bstandard Bdeviation Bwill Bequal B0.
9. The Bmean Band Bstandard Bdeviation Bboth Bincrease Bby B5%.
11. The Btotal Bheight Bof Bthe B20 Bmen Bis B20 B× B178 B= B3560. B The Btotal Bheight Bof Bthe B30 Bwomen Bis B30 B× B164 B= B4920.
The Btotal Bheight Bof Ball B50 Bpeople Bis B3560 B+ B4920 B= B8480. BThere Bare B20 B+ B30 B= B50 Bpeople Bin Btotal.
B Therefore Bthe Bmean Bheight Bfor Bboth Bgroups Bput Btogether Bis B8480/50 B= B169.6 Bcm.
13. B(a) BAll Bwould Bbe Bdivided Bby B2.54.
(b) BNot Bexactly Bthe Bsame, Bbecause Bthe Bmeasurements Bwould Bbe Ba Blittle Bdifferent Bthe Bsecond Btime.
15. (a) BThe Bsample Bsize Bis Bn B= B16. BThe Btertiles Bhave Bcutpoints B(1/3)(17) B= B5.67 Band B(2/3)(17) B= B11.33. BThe
Bfirst Btertile Bis Btherefore Bthe Baverage Bof Bthe Bsample Bvalues Bin Bpositions B5 Band B6, Bwhich Bis B(44 B+ B46)/2 B=
B45. B The Bsecond Btertile Bis Bthe Baverage Bof Bthe Bsample Bvalues Bin Bpositions B11 Band B12, Bwhich Bis B(76
B+ B79)/2 B= B77.5.
(b) The Bsample Bsize Bis Bn B= B16. BThe Bquintiles Bhave Bcutpoints B(i/5)(17) Bfor Bi B= B1, B2, B3, B4. B The Bquintiles
Bare Btherefore Bthe Baverages Bof Bthe Bsample Bvalues Bin Bpositions B3 Band B4, Bin Bpositions B6 Band B7, Bin
Bpositions B10 Band B11, Band Bin Bpositions B13 Band B14. B The Bquintiles Bare Btherefore B(23 B+ B41)/2 B= B32,
B(46 B+B49)/2 B= B47.5, B(74 B+B76)/2 B= B75, Band
(82 B+B89)/2 B= B85.5.
