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A Level Maths questions with answers

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A Level Maths questions with answers

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A Level Maths questions with answers

y=af(x) - ** VERIFIED ANSWERS **✔✔stretch graph vertically by scale factor a



y=f(x)+a - ** VERIFIED ANSWERS **✔✔translation in the y-axis of a



y=f(ax) - ** VERIFIED ANSWERS **✔✔stretch graph horizontally by scale factor 1/a



y=f(x+a) - ** VERIFIED ANSWERS **✔✔translation in the x-axis of -a



y=-f(x) - ** VERIFIED ANSWERS **✔✔reflect over x-axis



y=f(-x) - ** VERIFIED ANSWERS **✔✔reflection in y axis



y=(ax+b) - ** VERIFIED ANSWERS **✔✔move -b horizontally, the horizontal stretch of 1/a



Given a centre (a, b) and radius r, the equation of a circle is - ** VERIFIED ANSWERS **✔✔(x-
a)^2+(y-b)^2=r^2



Given x^2+3x+y^2-4x+10=0. How do you find the centre and radius of the circle - ** VERIFIED
ANSWERS **✔✔Complete the square of the x terms, complete the square of the y terms



The angle between the radius and the tangent is - ** VERIFIED ANSWERS **✔✔90 degrees



Midpoint between A and B - ** VERIFIED ANSWERS **✔✔(average of x, average of ys)



Gradient of line between A and B - ** VERIFIED ANSWERS **✔✔Difference between y's over
difference between xs

,Distance between A and B - ** VERIFIED ANSWERS **✔✔Use Pythagaros



Equation of line between A and B - ** VERIFIED ANSWERS **✔✔m(x-x_a)=(y-y_b)



kinematic equation without displacement - ** VERIFIED ANSWERS **✔✔v=u + at



kinematic equation without final velocity - ** VERIFIED ANSWERS **✔✔s= ut+at^2



kinematic equation without acceleration - ** VERIFIED ANSWERS **✔✔s=(u+v)/t



kinematic equation without time - ** VERIFIED ANSWERS **✔✔v^2=u^2+2as



The area under speed time graph is - ** VERIFIED ANSWERS **✔✔the displacement



The gradient of a speed time graph is - ** VERIFIED ANSWERS **✔✔acceleration



differentiate x^n - ** VERIFIED ANSWERS **✔✔nx^(n-1)



Differentiate x - ** VERIFIED ANSWERS **✔✔1



Differentiate 3 - ** VERIFIED ANSWERS **✔✔0



To find the gradient of a tangent a point P on the curve - ** VERIFIED ANSWERS **✔✔Sub the x
coordinate of into the gradient function



dy/dx is - ** VERIFIED ANSWERS **✔✔the gradient function

, Given the gradient (m) of a tangent at point P, find the point P - ** VERIFIED ANSWERS **✔✔Set
the gradient function to equal m, rearrange to find x. Stick x into the original function to find the y
coordinate



The definition of differentiation is - ** VERIFIED ANSWERS **✔✔limit as h tends to 0 of (f(x+h)-
f(x))/h



To find the tangent at point P of a curve - ** VERIFIED ANSWERS **✔✔Use m(x-x_1)=y-y_1. To
find m stick x_1 into the gradient function, to find y_1 stick x_1 into the original function



To find the normal at point P of a curve - ** VERIFIED ANSWERS **✔✔Use m(x-x_1)=y-y_1. To
find m stick x_1 into the gradient function and then use the negative reciprocal, to find y_1 stick x_1
into the original function



To solve sinx=0.5 - ** VERIFIED ANSWERS **✔✔Draw y=sinx. Draw y=0.5. Use the calculator to
find the initial solution. Use the symmetry of the diagram to find the other solutions



Sin^2(x)+cos^2(x)= - ** VERIFIED ANSWERS **✔✔1



tanx= - ** VERIFIED ANSWERS **✔✔sinx/cosx



To solve sin2x - ** VERIFIED ANSWERS **✔✔Draw 2 sinx for double the boundary, then solve as
normal



The first thing to do with a projectiles question is - ** VERIFIED ANSWERS **✔✔break it into a
vertical problem and a horizontal problem



The horizontal acceleration is - ** VERIFIED ANSWERS **✔✔0



The vertical acceleration is - ** VERIFIED ANSWERS **✔✔-9.8

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