3/5/24, 11:35 PM AQA A level Chem: Past paper questions and answers | Quizlet
Name: Score:
36 Multiple choice questions
Term 1 of 36
Which represents the correct order of increasing radius of the ions? [1 mark]
A) F- O2- Li+ Be2+
B) Li+ Be2+ O2- F-
C) Be2+ Li+ F- O2-
D) O2- F- Li+ Be2+
P4+ 5O2-> P4O10
as P always exists as P4
P4 has a oxidation state of +5 which leads to a total of +20 so we need -20 on O2 to
balance the charges so we need -10 as 2 lots of O so O is 10 and to balance stick a 5 in
front of O2
> Mg, Si, Al, P, S
> S has the highest Second IE as ionic radius decreases across a period so electrons
closer to nucleus hence a lot of energy needed when another electron is removed from
a negatively charged ion
> Si and Al don't follow an increase in second IE pattern because
> HCl is formed which gives off steamy white fumes
> NaCl + H2SO4-> NaHSO4+ HCl
> proton acceptor as it accepts e- from H as it needs to gain e- when Na reacts with
H2SO4 to be reduced and H needs to loose one e- to form H+
C
because Be2+ is the smallest ion because it has a greater nuclear charge/more protons
so stronger attraction to outer e- so pulls them closer
Li+ is the second smallest same reason
O-2 more bigger than F- because it has less protons so weaker attraction to outer e- so
e- further apart
https://quizlet.com/656534553/test?answerTermSides=4&promptTermSides=6&questionCount=36&questionTypes=4&showImages=true 1/22
,3/5/24, 11:35 PM AQA A level Chem: Past paper questions and answers | Quizlet
Term 2 of 36
What is the element in period 3, sodium to argon that has the highest second IE and why? Give
an equation with state symbols.
D
because not A as both non-metals
not NH3 as both non-metals
not CHCl3 because it contains covalent bonding
NH4+ and Cl-
Both the e- on N donated to the H to form NH4+ as it contains 1 lp
> sodium
This is because it is in group 1 so has 1 electron when the first ionisation energy occurs it
removes that one electron but when the second ionisation energy occurs then it
removes electron from a positively charged metal ion or from a shell which is closer to
the nucleus and is stable as it has a full outer shell so removing that one electron from a
full outer shell it will takes a lot of energy
Na+-> Na+2 +e-
gg
> HCl is formed which gives off steamy white fumes
> NaCl + H2SO4-> NaHSO4+ HCl
> proton acceptor as it accepts e- from H as it needs to gain e- when Na reacts with
H2SO4 to be reduced and H needs to loose one e- to form H+
C
because Be2+ is the smallest ion because it has a greater nuclear charge/more protons
so stronger attraction to outer e- so pulls them closer
Li+ is the second smallest same reason
O-2 more bigger than F- because it has less protons so weaker attraction to outer e- so
e- further apart
https://quizlet.com/656534553/test?answerTermSides=4&promptTermSides=6&questionCount=36&questionTypes=4&showImages=true 2/22
, 3/5/24, 11:35 PM AQA A level Chem: Past paper questions and answers | Quizlet
Term 3 of 36
Why is conical flask better to use than beaker for TITRATION?
yellow/orange solution as bromine water forms which is
Because it is easier to swirl mixture without loosing any solution
> Brown solution for all as no reaction
as weakest so cannot displace any
> very pale green- no reaction
> yellow solution
> brown solution
Term 4 of 36
What is observed when Br2 is added to KCl, KBr and KI?
> very pale green- no reaction
> yellow solution
> brown solution
yellow/orange solution as bromine water forms which is
> Brown solution for all as no reaction
as weakest so cannot displace any
> yellow solution- no reaction
> yellow solution- no reaction
> brown solution
https://quizlet.com/656534553/test?answerTermSides=4&promptTermSides=6&questionCount=36&questionTypes=4&showImages=true 3/22
Name: Score:
36 Multiple choice questions
Term 1 of 36
Which represents the correct order of increasing radius of the ions? [1 mark]
A) F- O2- Li+ Be2+
B) Li+ Be2+ O2- F-
C) Be2+ Li+ F- O2-
D) O2- F- Li+ Be2+
P4+ 5O2-> P4O10
as P always exists as P4
P4 has a oxidation state of +5 which leads to a total of +20 so we need -20 on O2 to
balance the charges so we need -10 as 2 lots of O so O is 10 and to balance stick a 5 in
front of O2
> Mg, Si, Al, P, S
> S has the highest Second IE as ionic radius decreases across a period so electrons
closer to nucleus hence a lot of energy needed when another electron is removed from
a negatively charged ion
> Si and Al don't follow an increase in second IE pattern because
> HCl is formed which gives off steamy white fumes
> NaCl + H2SO4-> NaHSO4+ HCl
> proton acceptor as it accepts e- from H as it needs to gain e- when Na reacts with
H2SO4 to be reduced and H needs to loose one e- to form H+
C
because Be2+ is the smallest ion because it has a greater nuclear charge/more protons
so stronger attraction to outer e- so pulls them closer
Li+ is the second smallest same reason
O-2 more bigger than F- because it has less protons so weaker attraction to outer e- so
e- further apart
https://quizlet.com/656534553/test?answerTermSides=4&promptTermSides=6&questionCount=36&questionTypes=4&showImages=true 1/22
,3/5/24, 11:35 PM AQA A level Chem: Past paper questions and answers | Quizlet
Term 2 of 36
What is the element in period 3, sodium to argon that has the highest second IE and why? Give
an equation with state symbols.
D
because not A as both non-metals
not NH3 as both non-metals
not CHCl3 because it contains covalent bonding
NH4+ and Cl-
Both the e- on N donated to the H to form NH4+ as it contains 1 lp
> sodium
This is because it is in group 1 so has 1 electron when the first ionisation energy occurs it
removes that one electron but when the second ionisation energy occurs then it
removes electron from a positively charged metal ion or from a shell which is closer to
the nucleus and is stable as it has a full outer shell so removing that one electron from a
full outer shell it will takes a lot of energy
Na+-> Na+2 +e-
gg
> HCl is formed which gives off steamy white fumes
> NaCl + H2SO4-> NaHSO4+ HCl
> proton acceptor as it accepts e- from H as it needs to gain e- when Na reacts with
H2SO4 to be reduced and H needs to loose one e- to form H+
C
because Be2+ is the smallest ion because it has a greater nuclear charge/more protons
so stronger attraction to outer e- so pulls them closer
Li+ is the second smallest same reason
O-2 more bigger than F- because it has less protons so weaker attraction to outer e- so
e- further apart
https://quizlet.com/656534553/test?answerTermSides=4&promptTermSides=6&questionCount=36&questionTypes=4&showImages=true 2/22
, 3/5/24, 11:35 PM AQA A level Chem: Past paper questions and answers | Quizlet
Term 3 of 36
Why is conical flask better to use than beaker for TITRATION?
yellow/orange solution as bromine water forms which is
Because it is easier to swirl mixture without loosing any solution
> Brown solution for all as no reaction
as weakest so cannot displace any
> very pale green- no reaction
> yellow solution
> brown solution
Term 4 of 36
What is observed when Br2 is added to KCl, KBr and KI?
> very pale green- no reaction
> yellow solution
> brown solution
yellow/orange solution as bromine water forms which is
> Brown solution for all as no reaction
as weakest so cannot displace any
> yellow solution- no reaction
> yellow solution- no reaction
> brown solution
https://quizlet.com/656534553/test?answerTermSides=4&promptTermSides=6&questionCount=36&questionTypes=4&showImages=true 3/22
