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INV3702 Assignment 2 2026 – Investment Analysis and Bond Valuation Questions with Correct Answers

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This document contains complete solutions and correct answers for INV3702 Assignment 2 for the 2024–2025 academic period. The material covers bond valuation, spot rates, yield-to-maturity analysis, arbitrage-free pricing, yield curve interpretation, credit analysis, leverage ratios, forward rates, and binomial interest rate tree valuation techniques used in investment analysis and fixed income studies. The assignment provides worked examples and explanations for valuation methods, creditworthiness analysis, and interest rate modeling, making it useful for finance and investment students preparing for assignments, exams, and fixed income assessments. INV3702 ASSIGNMENT 2 2024|QUESTIONS AND CORRECT ANSWERS 100% PASSQUESTION 1 Determine whether Bond E is overvalued, undervalued or fairly valued. All coupons are paid annually. The price of the 3-year coupon bond (as a percent of par) is: N = 3; I/YR = 2.711; PMT = 5; FV = 100; Compute PV = –106.51

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INV3702 ASSIGNMENT 2
2024|QUESTIONS AND
CORRECT ANSWERS
100% PASS
QUESTION 1
Determine whether
Bond E is overvalued,
undervalued or fairly
valued. All coupons
are paid annually.

, The price of the 3-year coupon bond (as a percent of par) is:

N = 3; I/YR = 2.711; PMT = 5; FV = 100;

Compute PV = –106.51



The no-arbitrage price of the 3-year coupon bond based on spot (zero-coupon) rates is:
5 5 105
+ + = 106.51
1.02350 (1.02500)2 1.027253




Therefore the 3-year coupon bond's price equals its no-arbitrage value, therefore the bond
is fairly valued.




QUESTION 2

Explain to Kgomotso why her method leads to an incorrect answer, and advise her on the
correct method to approach this question. No calculations are necessary.

Kgomotso’s method uses the yield-to-maturity as the input for I/YR.

Yield-to-maturity is not appropriate for arbitrage-free valuation when the yield curve is not
flat.

She should value each cash flow separately using the corresponding spot rate.
5
105
Full marks for the correct equation: +
1.035 1.03652

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