be a. F^+. b. lac^-. c. Lac^+. d. both a and c e. all of the above
Solution
The answer is a. F+. The lac is present on naked DNA of the bacteria. During conjugation gene
which are present on F plsmid they will transer only.
An F^-, lac^- E. coli strain is mated with an F-lac cell. After conjugation, the recipient cell will be a. F^+. b. lac^-. c. Lac^+. d. both a and c e. all of the above Solution The answer is a. F+. The lac is present on naked DNA of the bacteria. During conjugation gene which are present on F plsmid they will transer only.
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