AQA GCSE COMBINED SCIENCE: TRILOGY 8464/P/1F Foundation Tier Physics Paper 1F Question Paper + Mark scheme [MERGED] June 2022 *jun228464p1f01* IB/M/Jun22/E13 8464/P/1F For Examiner’s Use Question Mark 1

AQA GCSE COMBINED SCIENCE: TRILOGY 8464/P/1F Foundation Tier Physics Paper 1F Question Paper + Mark scheme [MERGED] June 2022 *junp1f01* IB/M/Jun22/E13 8464/P/1F For Examiner’s Use Question Mark 1 2 3 4 5 6 TOTAL Time allowed: 1 hour 15 minutes Materials For this paper you must have: • a ruler • a scientific calculator • the Physics Equations Sheet (enclosed). Instructions • Use black ink or black ball-point pen. • Pencil should only be used for drawing. • Fill in the boxes at the top of this page. • Answer all questions in the spaces provided. • If you need extra space for your answer(s), use the lined pages at the end of this book. Write the question number against your answer(s). • Do all rough work in this book. Cross through any work you do not want to be marked. • In all calculations, show clearly how you work out your answer. Information • The maximum mark for this paper is 70. • The marks for questions are shown in brackets. • You are expected to use a calculator where appropriate. • You are reminded of the need for good English and clear presentation in your answers. Please write clearly in block capitals. Centre number Candidate number Surname Forename(s) Candidate signature I declare this is my own work. GCSE COMBINED SCIENCE: TRILOGY Foundation Tier Physics Paper 1F F 2 *02* IB/M/Jun22/8464/P/1F 0 1 A student investigated how the potential difference across a filament lamp affects the current in the lamp. Figure 1 shows the circuit the student used. Figure 1 0 1 . 1 Figure 2 shows a circuit symbol. Figure 2 What component does the symbol represent? [1 mark] Tick () one box. Ammeter Battery Lamp Variable resistor Do not write outside the box 3 *03* Turn over ► IB/M/Jun22/8464/P/1F Do not write outside the 0 1 box . 2 Which component from Figure 1 did the student use to adjust the potential difference across the lamp? [1 mark] 0 1 . 3 When the voltmeter was not connected to the circuit it gave a reading of 0.4 volts. How can the student correct all the readings taken from the voltmeter? [1 mark] Tick () one box. Add 0.4 volts to each reading Divide each reading by 0.4 volts Multiply each reading by 0.4 volts Subtract 0.4 volts from each reading Question 1 continues on the next page 4 *04* IB/M/Jun22/8464/P/1F Do not write outside the box 0 1 . 4 The student recorded three values of current for each potential difference. Table 1 shows the results for 2.5 volts. Table 1 Potential difference in volts Current in amps 1 2 3 2.5 0.54 0.58 0.53 Calculate the mean current in the lamp. [2 marks] Mean current = A 0 1 . 5 Calculate the power of the lamp when the potential difference across the lamp was 4.8 V The current in the lamp was 0.75 A Use the equation: power = potential difference × current [2 marks] Power = W 5 *05* Turn over ► IB/M/Jun22/8464/P/1F Do not write outside the 0 1 box . 6 Calculate the resistance of the lamp when the potential difference across the lamp was 4.8 V The current in the lamp was 0.75 A Use the equation: resistance = potential difference current [2 marks] Resistance = Ω 0 1 . 7 Complete the sentence. Choose answers from the box. Each answer may be used once, more than once or not at all. [2 marks] decrease increase stay the same Increasing the current in a filament lamp makes the temperature of the lamp and the resistance of the lamp . Question 1 continues on the next page 6 *06* IB/M/Jun22/8464/P/1F Do not write outside the box 12 0 1 . 8 Which graph shows the relationship between potential difference and current for a filament lamp? [1 mark] Tick () one box. 7 *07* Turn over ► IB/M/Jun22/8464/P/1F Do not write outside the Turn over for the next question box DO NOT WRITE ON THIS PAGE ANSWER IN THE SPACES PROVIDED 8 *08* IB/M/Jun22/8464/P/1F Do not write outside the 0 2 Figure 3 shows a lift near the bottom of a building. box The lift is attached by a cable to a counterweight. An electric motor moves the lift. The lift is moving up. Figure 3 0 2 . 1 As the lift moves up, how far does the counterweight move down? [1 mark] Tick () one box. A shorter distance than the lift. The same distance as the lift. A longer distance than the lift. 9 *09* Turn over ► IB/M/Jun22/8464/P/1F Do not write outside the 0 2 box . 2 What happens to the gravitational potential energy of the counterweight as it moves down? [1 mark] Tick () one box. It decreases It stays the same It increases 0 2 . 3 Calculate the change in gravitational potential energy of the lift when it moves up 4.0 m The mass of the lift is 1300 kg gravitational field strength = 9.8 N/kg Use the equation: gravitational potential energy = mass × gravitational field strength × height [2 marks] Change in gravitational potential energy = J Question 2 continues on the next page 10 *10* IB/M/Jun22/8464/P/1F Do not write outside the box 0 2 . 4 Complete the sentences. Choose answers from the box. [2 marks] chemical elastic potential gravitational potential internal kinetic Friction between the brakes and the cable causes the speed of the lift to decrease. As the speed decreases, there is a decrease in the energy of the lift. As the speed decreases, there is an increase in the energy of the brakes. 0 2 . 5 The motor transfers different amounts of energy each time people use the lift. Which factors affect the amount of energy transferred by the motor as the lift moves? [2 marks] Tick () two boxes. The distance moved by the lift The height of the building The length of the steel cable The maximum power of the motor The weight of the people in the lift 11 *11* Turn over ► IB/M/Jun22/8464/P/1F Do not write outside the box 11 0 2 . 6 The weight of the lift and the counterweight stretch the cable by 0.015 m The cable acts like a spring with a spring constant of 880 000 N/m Calculate the elastic potential energy of the stretched cable. Use the equation: elastic potential energy = 0.5 × spring constant × (extension)2 [2 marks] Elastic potential energy = J 0 2 . 7 A lift system using a counterweight is more efficient than a lift system that does not use a counterweight. How does having a more efficient system affect the energy transferred by the motor? [1 mark] Tick () one box. Less energy is transferred. The same amount of energy is transferred. More energy is transferred. Turn over for the next question 12 *12* IB/M/Jun22/8464/P/1F Do not write outside the box 0 3 A teacher demonstrated that the radioactive isotope americium-241 emits alpha particles. Figure 4 shows the equipment used. Figure 4 0 3 . 1 An americium-241 nucleus (Am) emits an alpha particle and turns into a neptunium nucleus (Np). Which is the correct nuclear equation for this decay? Tick () one box. [1 mark] 0 3 . 2 What is the furthest distance that alpha radiation can travel in air? Tick () one box. [1 mark] A few millimetres A few centimetres A few metres 13 *13* Turn over ► IB/M/Jun22/8464/P/1F Do not write outside the 0 3 box . 3 The teacher placed a piece of paper between the americium-241 and the radiation detector. The reading on the count rate meter decreased by a large amount. Why does the decreased reading show that americium-241 emits alpha radiation? Tick () one box. [1 mark] Paper stops alpha radiation. Paper stops all types of radiation. Paper stops beta and gamma radiation