Mcat Exam Practice.
energy of a photon e=hv e=energy of photon h = plancks constant (6.6X10^-34 J) v=frequency *energy of photon is directly proportional to frequency for all waves energy of a photon in a vacumn E=hc/wavelength h=plancks constant (6.6X10^-34J) c= speed of light in a vacuum (3X10^8 m/s) wavelength *energy of photon = 1/wavelength gamma ray shorter wavelength higher frequency higher energy
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