Excanplal: Find HCF 4052 and 125t6.
&aluti- inte 2516>4052, s
appla he
diviaion Samma to 25t6 to 4052.
1251 H052 X3 +20
4652 20 X9+ 2+2
20= 242 x + 148
, 242 =
148 XI+124
148= 124 X1t 24
124=24 X5+4H
24 x 6 +0
.'HCF=
&aluti- inte 2516>4052, s
appla he
diviaion Samma to 25t6 to 4052.
1251 H052 X3 +20
4652 20 X9+ 2+2
20= 242 x + 148
, 242 =
148 XI+124
148= 124 X1t 24
124=24 X5+4H
24 x 6 +0
.'HCF=