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OPM1501 Exam Pack 2026 Distinction Study Guide | Operations Management I Verified Past Exam Papers, Step-by-Step Solutions & Productivity Formulas | UNISA Introduction to Business Process Design Summary Packet

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Dominate your introductory operations management module with this definitive OPM1501 Exam Pack, completely updated for the 2026 academic year. This premium resource contains step-by-step solutions to past exam papers, clear summaries of core operational strategies, and simplified explanations of productivity and capacity formulas. It serves as an essential tool for students looking to eliminate guesswork, master business process design, and guarantee a distinction in their final assessment.

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OPM1501 Exam Pack 2026 Distinction Study Guide |
Operations Management I Verified Past Exam Papers,
Step-by-Step Solutions & Productivity Formulas |
UNISA Introduction to Business Process Design
Summary Packet



Q1. What is the primary focus of the OPM1501 module?



Answer: Developing intermediate phase teachers' understanding of mathematical concepts and
pedagogical content knowledge.



Rationale: The module purpose stated by Unisa is to develop informed understanding of
underpinning mathematics concepts and pedagogical content knowledge in the Intermediate Phase .



Q2. According to OPM1501, what is the key difference between behaviourism and constructivism in
mathematics teaching?



Answer: Behaviourism views learners as passive recipients of knowledge, while constructivism views
learners as active creators of their own knowledge.



Rationale: The study guide contrasts these theories, noting behaviourism produces a follow-the-
rules view, while constructivism emphasises active meaning-making .



Q3. What is assimilation in the context of constructivist mathematics learning?



Answer: Using an existing schema to understand a new experience.



Rationale: Piaget's theory identifies assimilation as fitting new information into existing mental
structures .

,Q4. What is accommodation in constructivist theory?



Answer: Altering existing schemas when new ideas do not fit.



Rationale: Accommodation occurs when learners must modify their mental frameworks to
incorporate new experiences that conflict with prior understanding .



Q5. What does the Zone of Proximal Development (ZPD) refer to?



Answer: The stage where learners can do mathematics with assistance but not alone.



Rationale: Vygotsky's ZPD is crucial for understanding scaffolding and appropriate support in
mathematics teaching .



Q6. What is "teaching by negotiation" in OPM1501?



Answer: A constructivist approach where meaning is co-constructed between teacher and learners.



Rationale: This replaces "teaching by imposition" and promotes engagement and meaning-making .



Q7. In a problem-solving lesson, what is the primary responsibility of the teacher in the "before"
phase?



Answer: To set the stage by connecting to prior knowledge and introducing the problem.



Rationale: The "before" phase ensures learners understand the problem and connect it to what they
already know .



Q8. What is the primary responsibility of the teacher in the "after" phase of a problem-solving
lesson?



Answer: To facilitate a discussion that highlights key mathematical ideas and consolidates learning.

, Rationale: The "after" phase is for consolidating learning and connecting strategies .



Q9. What is compensation in the context of number operations?



Answer: Changing numbers to make the calculation easier, then adjusting the result.



Rationale: For example, 468 + 39 = (468 + 40) − 1 = 507 .



Q10. How would you use compensation to calculate 876 − 59?



Answer: 876 − 60 = 816, then add 1 back = 817.



Rationale: Subtracting a round number (60) is easier, then compensating for the extra 1 subtracted .



Q11. What is the rule for divisibility by 3?



Answer: A number is divisible by 3 if the sum of its digits is divisible by 3.



Rationale: This is a standard divisibility rule tested in OPM1501 exams .



Q12. Test 1 264 032 for divisibility by 3.



Answer: Divisible by 3 because the sum of digits (1+2+6+4+0+3+2 = 18) is divisible by 3.



Rationale: 18 ÷ 3 = 6, confirming divisibility .



Q13. What is the rule for divisibility by 11?



Answer: A number is divisible by 11 if the alternating sum of its digits is divisible by 11 (or equals 0).



Rationale: This rule is frequently tested in OPM1501 without actual division .

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