IBHRE
Prep Exam 2026–2027 | Certification Practice
Questions, Answers & Detailed Rationales
THIS EXAM PREP RESOURCE INCLUDES
➢IBHRE certification exam review material
➢Practice questions, where included
➢Answers and detailed rationales, where provided
,Question 1
Voltage is:
A) The resistance to electron flow
B) The electromotive force pushing on electrons
C) The rate of electron flow
D) The storage of electrons
Answer: B
Rationale: Voltage (electrical potential difference) is the electromotive
force that pushes electrons through a conductor. It is the "pressure"
driving current flow.
Question 2
If the PM output voltage is 5V and the measured lead resistance is 330
ohms, then the current that flows out of the pacemaker into the heart
is:
A) 6.6 mA
B) 15.15 mA
C) 1.5 mA
D) 33 mA
, Answer: B
Rationale: Using Ohm's Law: I = V/R = 5V ÷ 330Ω = 0.01515 A = 15.15
mA. (Note: The original note incorrectly wrote 33 kΩ; the correct
calculation uses 330Ω.)
Question 3
If a unipolar lead wire has an insulation break, one would expect the
resistance to:
A) Increase
B) Decrease
C) Remain unchanged
D) Fluctuate randomly
Answer: B
Rationale: An insulation break allows current to leak into surrounding
tissue/fluid, creating a parallel path that lowers the measured
resistance.
Question 4
For a wire fracture, the resistance:
Prep Exam 2026–2027 | Certification Practice
Questions, Answers & Detailed Rationales
THIS EXAM PREP RESOURCE INCLUDES
➢IBHRE certification exam review material
➢Practice questions, where included
➢Answers and detailed rationales, where provided
,Question 1
Voltage is:
A) The resistance to electron flow
B) The electromotive force pushing on electrons
C) The rate of electron flow
D) The storage of electrons
Answer: B
Rationale: Voltage (electrical potential difference) is the electromotive
force that pushes electrons through a conductor. It is the "pressure"
driving current flow.
Question 2
If the PM output voltage is 5V and the measured lead resistance is 330
ohms, then the current that flows out of the pacemaker into the heart
is:
A) 6.6 mA
B) 15.15 mA
C) 1.5 mA
D) 33 mA
, Answer: B
Rationale: Using Ohm's Law: I = V/R = 5V ÷ 330Ω = 0.01515 A = 15.15
mA. (Note: The original note incorrectly wrote 33 kΩ; the correct
calculation uses 330Ω.)
Question 3
If a unipolar lead wire has an insulation break, one would expect the
resistance to:
A) Increase
B) Decrease
C) Remain unchanged
D) Fluctuate randomly
Answer: B
Rationale: An insulation break allows current to leak into surrounding
tissue/fluid, creating a parallel path that lowers the measured
resistance.
Question 4
For a wire fracture, the resistance:
