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PHS 104A Pulleys & Mechanical Advantage: 110 Practice Questions with Worked Solutions (PDF) | 2026–2027

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INSTANT PDF DOWNLOAD Prepare for PHS 104A Physics with 110 practice questions and worked solutions covering pulleys, mechanical advantage, and simple machines. Review fixed and movable pulleys, compound pulley systems, force calculations, rope tension, load distribution, mechanical efficiency, and work-energy principles. Ideal for physics exam preparation and problem-solving practice for 2026–2027. Pulley Physics Review, Simple Machines Practice, Mechanical Advantage Calculations, Compound Pulley Problems, Force and Tension, Physics Worked Examples, Load Distribution Questions, Ideal Mechanical Advantage, Pulley Efficiency Problems, Work Energy Principles, Rope Tension Calculations, Fixed Pulley Systems, Movable Pulley Review, Applied Mechanics Questions, Physics Problem Solving, Force Equilibrium Practice, Lifting Systems Analysis, Mechanical Efficiency Review, PHS 104A Study Guide, Physics Exam Questions

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PHS 104A | PULLEYS & MECHANICAL ADVANTAGE | 2026–2027



PHS 104A Pulleys &
Mechanical Advantage
Practice Questions 2026–2027 | 110 Original Problems with Worked Solutions

Independent study material, not an official PHS 104A examination. Assume massless
inextensible ropes, frictionless pulleys, and g = 9.8 m/s² unless a problem states otherwise.
A fixed pulley only changes force direction; ideal mechanical advantage equals the number
of supporting rope segments for a movable load.



Formula Reference
• Weight W = mg; force in newtons (N), mass in kilograms (kg).

• Ideal mechanical advantage IMA = load force / effort force = number of load-supporting
rope segments.

• Actual mechanical advantage AMA = measured load force / measured effort force.

• Efficiency (%) = (AMA / IMA) × 100 = (useful output work / input work) × 100.

• Ideal displacement ratio: effort distance / load distance = IMA.

• Work = force × displacement along force; power = work / time.

• For two hanging masses on an ideal Atwood machine: a = (m₂ − m₁)g / (m₁ + m₂), when m₂
> m₁; tension T = 2m₁m₂g/(m₁+m₂).




Independent educational practice | Page 1

,PHS 104A | PULLEYS & MECHANICAL ADVANTAGE | 2026–2027




Ideal Pulley Forces
Question 1. An ideal block-and-tackle supports a 40 N load with 2 rope segments.
What effort force is required?

A. 40 N
B. 20 N
C. 80 N
D. 40 N
Correct Answer: B. 20 N

Worked Solution: IMA = 2; F = 40/2 = 20 N.

Why the Other Options Are Incorrect: A (40 N) does not match the governing
relationship or the calculated result. C (80 N) does not match the governing
relationship or the calculated result. D (40 N) does not match the governing
relationship or the calculated result.



Question 2. An ideal block-and-tackle supports a 60 N load with 3 rope segments.
What effort force is required?

A. 60 N
B. 40 N
C. 20 N
D. 180 N
Correct Answer: C. 20 N

Worked Solution: IMA = 3; F = 60/3 = 20 N.

Why the Other Options Are Incorrect: A (60 N) does not match the governing
relationship or the calculated result. B (40 N) does not match the governing
relationship or the calculated result. D (180 N) does not match the governing
relationship or the calculated result.
Independent educational practice | Page 2

,PHS 104A | PULLEYS & MECHANICAL ADVANTAGE | 2026–2027



Question 3. An ideal block-and-tackle supports a 80 N load with 4 rope segments.
What effort force is required?

A. 320 N
B. 80 N
C. 40 N
D. 20 N
Correct Answer: D. 20 N

Worked Solution: IMA = 4; F = 80/4 = 20 N.

Why the Other Options Are Incorrect: A (320 N) does not match the governing
relationship or the calculated result. B (80 N) does not match the governing
relationship or the calculated result. C (40 N) does not match the governing
relationship or the calculated result.



Question 4. An ideal block-and-tackle supports a 100 N load with 5 rope segments.
What effort force is required?

A. 20 N
B. 500 N
C. 100 N
D. 40 N
Correct Answer: A. 20 N

Worked Solution: IMA = 5; F = 100/5 = 20 N.

Why the Other Options Are Incorrect: B (500 N) does not match the governing
relationship or the calculated result. C (100 N) does not match the governing
relationship or the calculated result. D (40 N) does not match the governing
relationship or the calculated result.



Question 5. An ideal block-and-tackle supports a 120 N load with 6 rope segments.
What effort force is required?

A. 40 N
B. 20 N

Independent educational practice | Page 3

, PHS 104A | PULLEYS & MECHANICAL ADVANTAGE | 2026–2027
C. 720 N
D. 120 N
Correct Answer: B. 20 N

Worked Solution: IMA = 6; F = 120/6 = 20 N.

Why the Other Options Are Incorrect: A (40 N) does not match the governing
relationship or the calculated result. C (720 N) does not match the governing
relationship or the calculated result. D (120 N) does not match the governing
relationship or the calculated result.



Question 6. An ideal block-and-tackle supports a 140 N load with 7 rope segments.
What effort force is required?

A. 140 N
B. 40 N
C. 20 N
D. 980 N
Correct Answer: C. 20 N

Worked Solution: IMA = 7; F = 140/7 = 20 N.

Why the Other Options Are Incorrect: A (140 N) does not match the governing
relationship or the calculated result. B (40 N) does not match the governing
relationship or the calculated result. D (980 N) does not match the governing
relationship or the calculated result.



Question 7. An ideal block-and-tackle supports a 160 N load with 8 rope segments.
What effort force is required?

A. 1280 N
B. 160 N
C. 40 N
D. 20 N
Correct Answer: D. 20 N

Worked Solution: IMA = 8; F = 160/8 = 20 N.

Why the Other Options Are Incorrect: A (1280 N) does not match the governing
relationship or the calculated result. B (160 N) does not match the governing
Independent educational practice | Page 4

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