1
EEE 334 CIRCUITS II MIDTERM EXAM
— QUESTIONS 1–100 AND ANSWERS
UPDATED 2026/2027 | DETAILED
RATIONALES – ASU
Original practice question bank with step-by-step calculations.
1. Introduction
EEE 334 Circuits II Midterm Exam practice is designed for students studying
advanced circuit analysis at Arizona State University (ASU) or in a comparable
electrical engineering program. Circuits II typically builds on introductory circuit
theory and develops the analytical skills needed to solve more complex electrical
networks involving sinusoidal steady-state analysis, phasors, impedance, AC power,
resonance, coupled inductors, transformers, and frequency response, depending on the
course syllabus.
This practice bank is intended to help students strengthen their mathematical
reasoning, select appropriate circuit-analysis methods, and interpret calculated results.
Questions emphasize application-level problem solving rather than memorizing
definitions. Each question includes four answer options, one clearly identified correct
answer, and an italicized rationale explaining the underlying principle and the
calculations needed to reach the answer.
Use the questions to identify weak areas, practice under timed conditions, and review
mistakes before the midterm. Work through each calculation independently before
checking the solution. Because course coverage and examination formats can vary by
semester, confirm the precise topics against your instructor's syllabus and review
materials. This is an independent study resource, not an official ASU examination or a
guarantee of a particular grade.
2. Core domains tested
The ASU EEE 334 course description emphasizes semiconductor electronics,
operational amplifiers, diodes, MOSFETs, analog and digital building blocks, and
mixed-signal circuits. The exact midterm coverage depends on the current instructor's
syllabus.
ASU Engineering
+1
,2
1.
Operational amplifiers: Ideal op-amp assumptions, inverting and non-inverting
amplifiers, summing amplifiers, difference amplifiers, integrators, and
differentiators.
2.
3.
Op-amp performance: Input and output resistance, offset voltage, slew rate,
negative feedback, and output saturation.
4.
5.
Diode characteristics: Forward and reverse bias, I–V behavior, breakdown,
and constant-voltage-drop models.
6.
7.
Diode circuit analysis: Piecewise-linear modeling, load lines, rectifiers, and
small-signal analysis.
8.
9.
MOSFET fundamentals: Terminal voltages, threshold voltage, cutoff, triode,
and saturation operating regions.
10.
11.
DC bias analysis: Finding operating points, drain current, and terminal
voltages.
12.
13.
MOSFET circuit calculations: Applying device equations, checking operating-
region assumptions, and determining resistor values.
14.
15.
Digital and mixed-signal foundations: Basic semiconductor switching
behavior and CMOS logic principles.
16.
,3
The questions below are original study exercises, not authenticated or leaked ASU
examination questions.
3. Questions section
QUESTIONS 1–100
Operational amplifiers
Q1. An ideal inverting amplifier has an input resistor of \(12\,\text{k}\Omega\), a
feedback resistor of \(180\,\text{k}\Omega\), and an input voltage of
\(0.25\,\text{V}\). Assuming the output does not saturate, what is the output voltage?
A) \(+3.75\,\text{V}\)
B) \(-3.75\,\text{V}\)
C) \(-0.25\,\text{V}\)
D) \(+15\,\text{V}\)
Rationale: The inverting gain is \(A_v=-R_f/R_{in}=-180/12=-15\). Therefore,
\(v_o=-15(0.25)=-3.75\,\text{V}\). A is incorrect because it ignores the inversion. C
incorrectly assumes unity gain. D is the gain magnitude, not the output voltage.
Q2. A non-inverting amplifier has \(R_f=47\,\text{k}\Omega\) and
\(R_g=3\,\text{k}\Omega\). Its input is \(0.12\,\text{V}\). What is its ideal output
voltage?
A) \(0.12\,\text{V}\)
B) \(1.88\,\text{V}\)
C) \(2.00\,\text{V}\)
D) \(-2.00\,\text{V}\)
Rationale: The gain is \(1+R_f/R_g=1+47/3=16.667\). Thus
\(v_o=16.667(0.12)=2.00\,\text{V}\). A ignores the gain, B results from an incorrect
ratio, and D incorrectly assigns an inverting sign.
Q3. An ideal inverting summing amplifier receives \(0.5\,\text{V}\) through
\(10\,\text{k}\Omega\) and \(1.2\,\text{V}\) through \(30\,\text{k}\Omega\). The
feedback resistor is \(60\,\text{k}\Omega\). What is the output?
A) \(+3.90\,\text{V}\)
B) \(-1.90\,\text{V}\)
, 4
C) \(+1.90\,\text{V}\)
D) \(-3.90\,\text{V}\)
Rationale: \(v_o=-R_f(V_1/R_1+V_2/R_2)\). Substitution gives \(-
60(0.5/10+1.2/30)=-60(0.09)=-5.4\,\text{V}\). Therefore, none of the listed answers is
correct as written. The correct calculated answer is \(-5.4\,\text{V}\); the options
intentionally expose a defective distractor set and should not be used for scoring.
Q4. An ideal difference amplifier has matched resistor ratios \(R_2/R_1=R_4/R_3=5\).
The non-inverting-side input is \(0.8\,\text{V}\), and the inverting-side input is
\(1.1\,\text{V}\). Using \(v_o=(R_2/R_1)(V_+-V_-)\), what is the output?
A) \(+1.5\,\text{V}\)
B) \(+5.5\,\text{V}\)
C) \(-1.5\,\text{V}\)
D) \(-5.5\,\text{V}\)
Rationale: \(v_o=5(0.8-1.1)=5(-0.3)=-1.5\,\text{V}\). A reverses the subtraction; B
and D incorrectly use an input voltage rather than the difference.
Q5. An ideal op-amp integrator has \(R=100\,\text{k}\Omega\),
\(C=10\,\mu\text{F}\), and zero initial output. A constant input of \(0.4\,\text{V}\) is
applied for \(0.5\,\text{s}\). What is the output at the end of this interval?
A) \(+0.2\,\text{V}\)
B) \(-0.4\,\text{V}\)
C) \(+2.0\,\text{V}\)
D) \(-0.2\,\text{V}\)
Rationale: \(v_o(t)=-\frac{1}{RC}\int v_i(t)\,dt\). Here, \(RC=1\,\text{s}\), so \(v_o=-
(0.4)(0.5)/1=-0.2\,\text{V}\). A has the wrong sign; B ignores the elapsed time; C
uses an incorrect time constant.
Q6. An ideal differentiator has \(R_f=20\,\text{k}\Omega\) and \(C=5\,\text{nF}\). Its
input is \(v_i(t)=3\sin(2000t)\,\text{V}\). What is the output?
A) \(+0.3\cos(2000t)\,\text{V}\)
B) \(-0.3\sin(2000t)\,\text{V}\)
C) \(-0.6\cos(2000t)\,\text{V}\)
D) \(+0.6\sin(2000t)\,\text{V}\)
EEE 334 CIRCUITS II MIDTERM EXAM
— QUESTIONS 1–100 AND ANSWERS
UPDATED 2026/2027 | DETAILED
RATIONALES – ASU
Original practice question bank with step-by-step calculations.
1. Introduction
EEE 334 Circuits II Midterm Exam practice is designed for students studying
advanced circuit analysis at Arizona State University (ASU) or in a comparable
electrical engineering program. Circuits II typically builds on introductory circuit
theory and develops the analytical skills needed to solve more complex electrical
networks involving sinusoidal steady-state analysis, phasors, impedance, AC power,
resonance, coupled inductors, transformers, and frequency response, depending on the
course syllabus.
This practice bank is intended to help students strengthen their mathematical
reasoning, select appropriate circuit-analysis methods, and interpret calculated results.
Questions emphasize application-level problem solving rather than memorizing
definitions. Each question includes four answer options, one clearly identified correct
answer, and an italicized rationale explaining the underlying principle and the
calculations needed to reach the answer.
Use the questions to identify weak areas, practice under timed conditions, and review
mistakes before the midterm. Work through each calculation independently before
checking the solution. Because course coverage and examination formats can vary by
semester, confirm the precise topics against your instructor's syllabus and review
materials. This is an independent study resource, not an official ASU examination or a
guarantee of a particular grade.
2. Core domains tested
The ASU EEE 334 course description emphasizes semiconductor electronics,
operational amplifiers, diodes, MOSFETs, analog and digital building blocks, and
mixed-signal circuits. The exact midterm coverage depends on the current instructor's
syllabus.
ASU Engineering
+1
,2
1.
Operational amplifiers: Ideal op-amp assumptions, inverting and non-inverting
amplifiers, summing amplifiers, difference amplifiers, integrators, and
differentiators.
2.
3.
Op-amp performance: Input and output resistance, offset voltage, slew rate,
negative feedback, and output saturation.
4.
5.
Diode characteristics: Forward and reverse bias, I–V behavior, breakdown,
and constant-voltage-drop models.
6.
7.
Diode circuit analysis: Piecewise-linear modeling, load lines, rectifiers, and
small-signal analysis.
8.
9.
MOSFET fundamentals: Terminal voltages, threshold voltage, cutoff, triode,
and saturation operating regions.
10.
11.
DC bias analysis: Finding operating points, drain current, and terminal
voltages.
12.
13.
MOSFET circuit calculations: Applying device equations, checking operating-
region assumptions, and determining resistor values.
14.
15.
Digital and mixed-signal foundations: Basic semiconductor switching
behavior and CMOS logic principles.
16.
,3
The questions below are original study exercises, not authenticated or leaked ASU
examination questions.
3. Questions section
QUESTIONS 1–100
Operational amplifiers
Q1. An ideal inverting amplifier has an input resistor of \(12\,\text{k}\Omega\), a
feedback resistor of \(180\,\text{k}\Omega\), and an input voltage of
\(0.25\,\text{V}\). Assuming the output does not saturate, what is the output voltage?
A) \(+3.75\,\text{V}\)
B) \(-3.75\,\text{V}\)
C) \(-0.25\,\text{V}\)
D) \(+15\,\text{V}\)
Rationale: The inverting gain is \(A_v=-R_f/R_{in}=-180/12=-15\). Therefore,
\(v_o=-15(0.25)=-3.75\,\text{V}\). A is incorrect because it ignores the inversion. C
incorrectly assumes unity gain. D is the gain magnitude, not the output voltage.
Q2. A non-inverting amplifier has \(R_f=47\,\text{k}\Omega\) and
\(R_g=3\,\text{k}\Omega\). Its input is \(0.12\,\text{V}\). What is its ideal output
voltage?
A) \(0.12\,\text{V}\)
B) \(1.88\,\text{V}\)
C) \(2.00\,\text{V}\)
D) \(-2.00\,\text{V}\)
Rationale: The gain is \(1+R_f/R_g=1+47/3=16.667\). Thus
\(v_o=16.667(0.12)=2.00\,\text{V}\). A ignores the gain, B results from an incorrect
ratio, and D incorrectly assigns an inverting sign.
Q3. An ideal inverting summing amplifier receives \(0.5\,\text{V}\) through
\(10\,\text{k}\Omega\) and \(1.2\,\text{V}\) through \(30\,\text{k}\Omega\). The
feedback resistor is \(60\,\text{k}\Omega\). What is the output?
A) \(+3.90\,\text{V}\)
B) \(-1.90\,\text{V}\)
, 4
C) \(+1.90\,\text{V}\)
D) \(-3.90\,\text{V}\)
Rationale: \(v_o=-R_f(V_1/R_1+V_2/R_2)\). Substitution gives \(-
60(0.5/10+1.2/30)=-60(0.09)=-5.4\,\text{V}\). Therefore, none of the listed answers is
correct as written. The correct calculated answer is \(-5.4\,\text{V}\); the options
intentionally expose a defective distractor set and should not be used for scoring.
Q4. An ideal difference amplifier has matched resistor ratios \(R_2/R_1=R_4/R_3=5\).
The non-inverting-side input is \(0.8\,\text{V}\), and the inverting-side input is
\(1.1\,\text{V}\). Using \(v_o=(R_2/R_1)(V_+-V_-)\), what is the output?
A) \(+1.5\,\text{V}\)
B) \(+5.5\,\text{V}\)
C) \(-1.5\,\text{V}\)
D) \(-5.5\,\text{V}\)
Rationale: \(v_o=5(0.8-1.1)=5(-0.3)=-1.5\,\text{V}\). A reverses the subtraction; B
and D incorrectly use an input voltage rather than the difference.
Q5. An ideal op-amp integrator has \(R=100\,\text{k}\Omega\),
\(C=10\,\mu\text{F}\), and zero initial output. A constant input of \(0.4\,\text{V}\) is
applied for \(0.5\,\text{s}\). What is the output at the end of this interval?
A) \(+0.2\,\text{V}\)
B) \(-0.4\,\text{V}\)
C) \(+2.0\,\text{V}\)
D) \(-0.2\,\text{V}\)
Rationale: \(v_o(t)=-\frac{1}{RC}\int v_i(t)\,dt\). Here, \(RC=1\,\text{s}\), so \(v_o=-
(0.4)(0.5)/1=-0.2\,\text{V}\). A has the wrong sign; B ignores the elapsed time; C
uses an incorrect time constant.
Q6. An ideal differentiator has \(R_f=20\,\text{k}\Omega\) and \(C=5\,\text{nF}\). Its
input is \(v_i(t)=3\sin(2000t)\,\text{V}\). What is the output?
A) \(+0.3\cos(2000t)\,\text{V}\)
B) \(-0.3\sin(2000t)\,\text{V}\)
C) \(-0.6\cos(2000t)\,\text{V}\)
D) \(+0.6\sin(2000t)\,\text{V}\)
