SPI ARDMS TEST A AND B QUESTIONS
AND ANSWERS PLUS RATIONALE NEW
2026-2027 UPDATE
50 QUESTIONS
TABLE OF CONTENTS
# TOPIC
1 Analyze and resolve complex artifact and image quality issues using physics principles
2 Apply Doppler equations and hemodynamic concepts to interpret spectral waveforms and calculate
velocities
3 Evaluate transducer selection, system settings, and safety indices for optimal diagnostic outcomes
4 Synthesize knowledge of sound-tissue interactions to predict and mitigate bioeffects and artifacts
5 Demonstrate proficiency in quality assurance testing and instrumentation calibration
6 SPI ARDMS Test A and B Questions and Answers Plus Rationale New 2026
7 2027 Update
8 Foundations of Sonography Principles and Instrumentation (SPI)
9 Applied Sonography Principles and Instrumentation (SPI)
10 Advanced Sonography Principles and Instrumentation (SPI)
11 Sonography Principles and Instrumentation (SPI) Review
ABSTRACT
This study document brings together 50 carefully worded exam questions drawn from SPI ARDMS
Test A and B Questions and Answers Plus Rationale New 2026-2027 Update, with the strongest
emphasis placed on Analyze and resolve complex artifact and image quality issues using physics
principles, Apply Doppler equations and hemodynamic concepts to interpret spectral waveforms
and calculate velocities, Evaluate transducer selection, system settings and and safety indices for
optimal diagnostic outcomes. Every item follows the wording style and level of reasoning you meet
in the real paper, and each one is paired with a clear rationale so the correct choice is never a
guess. Work through the set at your own pace, mark the questions that slow you down, then come
back to them until the reasoning feels automatic. Learners who revise this way walk into the exam
room recognising the pattern behind the questions instead of meeting them for the first time. Keep
going - steady, honest practice is what turns a difficult paper into a comfortable pass.
Page 1
,Q1 ANALYZE AND RESOLVE COMPLEX ARTIFACT AND IMAGE QUALITY ISSUES USING
PHYSICS PRINCIPLES
A linear array transducer with a 5 MHz center frequency and 2 cm aperture is used
for superficial imaging. If the aperture is reduced to 1 cm while frequency remains
constant, what is the primary effect on the beam profile?
A. Narrower beam width and improved lateral resolution
B. Wider beam width and decreased lateral resolution CORRECT
C. Increased axial resolution due to shorter pulse duration
D. No change in beam width but increased penetration
RATIONALE: Lateral resolution is directly proportional to the wavelength and focal length, and
inversely proportional to the aperture size. Reducing aperture size increases beam width and
worsens lateral resolution. Axial resolution depends on frequency and pulse duration, not
aperture. Penetration is affected by frequency, not aperture.
Q2 ANALYZE AND RESOLVE COMPLEX ARTIFACT AND IMAGE QUALITY ISSUES USING
PHYSICS PRINCIPLES
During a Doppler study, the angle of insonation is 60 degrees. If the measured
Doppler shift is 2 kHz, what is the true velocity of blood flow? (Assume
transmitted frequency = 5 MHz, speed of sound = 1540 m/s)
A. 0.5 m/s
B. 0.68 m/s
C. 0.87 m/s CORRECT
D. 1.0 m/s
RATIONALE: Using the Doppler equation: v = (fd * c) / (2 * f0 * cos). With fd = 2800 Hz, c = 1540
m/s, f0 = 5 MHz, and cos60° = 0.5, v = (2800 * 1540) / (2 * 5,000,000 * 0.5) = 4,312,000 /
5,000,000 = 0.8624 m/s 0.87 m/s. The other options result from errors such as using the wrong
angle or miscalculating the denominator.
Page 2
, Q3 ANALYZE AND RESOLVE COMPLEX ARTIFACT AND IMAGE QUALITY ISSUES USING
PHYSICS PRINCIPLES
Which of the following best explains why a 3 MHz transducer provides better
penetration than a 10 MHz transducer when imaging the same tissue?
A. Lower frequency has longer wavelength, which increases attenuation
B. Lower frequency has shorter wavelength, which decreases scattering
C. Lower frequency has longer wavelength, which decreases attenuation CORRECT
D. Lower frequency has higher duty factor, which increases penetration
RATIONALE: Attenuation is directly proportional to frequency: higher frequencies attenuate more
rapidly. A 3 MHz transducer has a longer wavelength and lower frequency, resulting in less
attenuation and deeper penetration. Options A and B incorrectly relate wavelength to attenuation.
Duty factor affects temporal average intensity, not penetration depth directly.
Q4 ANALYZE AND RESOLVE COMPLEX ARTIFACT AND IMAGE QUALITY ISSUES USING
PHYSICS PRINCIPLES
A sonographer notices a mirror-image artifact in a liver ultrasound. Which of the
following is the most likely cause?
A. Refraction at the diaphragm
B. Reflection at a strong specular reflector CORRECT
C. Scattering from red blood cells
D. Attenuation differences in tissue
RATIONALE: Mirror-image artifact occurs when sound reflects off a strong specular reflector
(e.g., diaphragm) and then reflects back from another interface, creating a duplicate image.
Refraction causes edge shadowing or duplication but not mirror image. Scattering produces
echoes but not mirror images. Attenuation differences cause shadowing or enhancement.
Page 3
AND ANSWERS PLUS RATIONALE NEW
2026-2027 UPDATE
50 QUESTIONS
TABLE OF CONTENTS
# TOPIC
1 Analyze and resolve complex artifact and image quality issues using physics principles
2 Apply Doppler equations and hemodynamic concepts to interpret spectral waveforms and calculate
velocities
3 Evaluate transducer selection, system settings, and safety indices for optimal diagnostic outcomes
4 Synthesize knowledge of sound-tissue interactions to predict and mitigate bioeffects and artifacts
5 Demonstrate proficiency in quality assurance testing and instrumentation calibration
6 SPI ARDMS Test A and B Questions and Answers Plus Rationale New 2026
7 2027 Update
8 Foundations of Sonography Principles and Instrumentation (SPI)
9 Applied Sonography Principles and Instrumentation (SPI)
10 Advanced Sonography Principles and Instrumentation (SPI)
11 Sonography Principles and Instrumentation (SPI) Review
ABSTRACT
This study document brings together 50 carefully worded exam questions drawn from SPI ARDMS
Test A and B Questions and Answers Plus Rationale New 2026-2027 Update, with the strongest
emphasis placed on Analyze and resolve complex artifact and image quality issues using physics
principles, Apply Doppler equations and hemodynamic concepts to interpret spectral waveforms
and calculate velocities, Evaluate transducer selection, system settings and and safety indices for
optimal diagnostic outcomes. Every item follows the wording style and level of reasoning you meet
in the real paper, and each one is paired with a clear rationale so the correct choice is never a
guess. Work through the set at your own pace, mark the questions that slow you down, then come
back to them until the reasoning feels automatic. Learners who revise this way walk into the exam
room recognising the pattern behind the questions instead of meeting them for the first time. Keep
going - steady, honest practice is what turns a difficult paper into a comfortable pass.
Page 1
,Q1 ANALYZE AND RESOLVE COMPLEX ARTIFACT AND IMAGE QUALITY ISSUES USING
PHYSICS PRINCIPLES
A linear array transducer with a 5 MHz center frequency and 2 cm aperture is used
for superficial imaging. If the aperture is reduced to 1 cm while frequency remains
constant, what is the primary effect on the beam profile?
A. Narrower beam width and improved lateral resolution
B. Wider beam width and decreased lateral resolution CORRECT
C. Increased axial resolution due to shorter pulse duration
D. No change in beam width but increased penetration
RATIONALE: Lateral resolution is directly proportional to the wavelength and focal length, and
inversely proportional to the aperture size. Reducing aperture size increases beam width and
worsens lateral resolution. Axial resolution depends on frequency and pulse duration, not
aperture. Penetration is affected by frequency, not aperture.
Q2 ANALYZE AND RESOLVE COMPLEX ARTIFACT AND IMAGE QUALITY ISSUES USING
PHYSICS PRINCIPLES
During a Doppler study, the angle of insonation is 60 degrees. If the measured
Doppler shift is 2 kHz, what is the true velocity of blood flow? (Assume
transmitted frequency = 5 MHz, speed of sound = 1540 m/s)
A. 0.5 m/s
B. 0.68 m/s
C. 0.87 m/s CORRECT
D. 1.0 m/s
RATIONALE: Using the Doppler equation: v = (fd * c) / (2 * f0 * cos). With fd = 2800 Hz, c = 1540
m/s, f0 = 5 MHz, and cos60° = 0.5, v = (2800 * 1540) / (2 * 5,000,000 * 0.5) = 4,312,000 /
5,000,000 = 0.8624 m/s 0.87 m/s. The other options result from errors such as using the wrong
angle or miscalculating the denominator.
Page 2
, Q3 ANALYZE AND RESOLVE COMPLEX ARTIFACT AND IMAGE QUALITY ISSUES USING
PHYSICS PRINCIPLES
Which of the following best explains why a 3 MHz transducer provides better
penetration than a 10 MHz transducer when imaging the same tissue?
A. Lower frequency has longer wavelength, which increases attenuation
B. Lower frequency has shorter wavelength, which decreases scattering
C. Lower frequency has longer wavelength, which decreases attenuation CORRECT
D. Lower frequency has higher duty factor, which increases penetration
RATIONALE: Attenuation is directly proportional to frequency: higher frequencies attenuate more
rapidly. A 3 MHz transducer has a longer wavelength and lower frequency, resulting in less
attenuation and deeper penetration. Options A and B incorrectly relate wavelength to attenuation.
Duty factor affects temporal average intensity, not penetration depth directly.
Q4 ANALYZE AND RESOLVE COMPLEX ARTIFACT AND IMAGE QUALITY ISSUES USING
PHYSICS PRINCIPLES
A sonographer notices a mirror-image artifact in a liver ultrasound. Which of the
following is the most likely cause?
A. Refraction at the diaphragm
B. Reflection at a strong specular reflector CORRECT
C. Scattering from red blood cells
D. Attenuation differences in tissue
RATIONALE: Mirror-image artifact occurs when sound reflects off a strong specular reflector
(e.g., diaphragm) and then reflects back from another interface, creating a duplicate image.
Refraction causes edge shadowing or duplication but not mirror image. Scattering produces
echoes but not mirror images. Attenuation differences cause shadowing or enhancement.
Page 3
