NURS 6501 Clinical Case Studies 2026–2027
NURS 6501 Clinical Case Studies 2026–2027 | Disease
Processes & Reasoning
Prepared for Advanced Pathophysiology Exam Preparation
100 Clinical Case Studies • Advanced Pathophysiology • 2026–2027
Case Study 1: Acid–Base Physiology in Chronic Respiratory Disease
Clinical Scenario:
A 65-year-old male with a 40-pack-year history of chronic obstructive pulmonary disease (COPD) presents
with increased dyspnea, productive cough, and bilateral lower extremity edema. Arterial blood gas (ABG)
analysis reveals:
pH: 7.32
PaCO₂: 68 mmHg
HCO₃⁻: 36 mEq/L
PaO₂: 55 mmHg
Question:
This clinical picture is most consistent with which acid–base disorder?
Options:
A. Acute respiratory acidosis without renal compensation
B. Chronic respiratory acidosis with renal compensation
C. Acute respiratory acidosis with superimposed metabolic alkalosis
D. Chronic respiratory acidosis with superimposed metabolic acidosis
Correct Answer: B. Chronic respiratory acidosis with renal compensation
Rationale:
The ABG demonstrates acidemia (pH < 7.35) with an elevated PaCO₂ (> 45 mmHg), confirming respiratory
acidosis. The key to determining chronicity lies in the bicarbonate level. In acute respiratory acidosis,
HCO₃⁻ rises only slightly (1 mEq/L for every 10 mmHg increase in PaCO₂) because renal compensation
requires 3–5 days to fully develop. In chronic respiratory acidosis, the kidneys increase HCO₃⁻
reabsorption and generate new bicarbonate, producing a rise of approximately 3.5–4 mEq/L for every 10
mmHg elevation in PaCO₂.
Here, the PaCO₂ is elevated by 28 mmHg above normal (68 − 40 = 28). Expected HCO₃⁻ for chronic
compensation: 24 + (2.8 × 3.5) ≈ 33.8 mEq/L, or using 4 mEq/L per 10 mmHg: 24 + (2.8 × 4) = 35.2 mEq/L.
The patient's HCO₃⁻ of 36 mEq/L closely approximates this predicted value, indicating maximal renal
compensation. This confirms a chronic process, consistent with the patient's underlying COPD.
Why Other Options Are Incorrect:
A. Acute respiratory acidosis without renal compensation would show a pH depression proportional to
the PaCO₂ elevation with minimal HCO₃⁻ increase (expected HCO₃⁻ ≈ 24 + 2.8 = 26.8 mEq/L, not 36). The
degree of bicarbonate elevation here rules out an acute process.
C. Acute respiratory acidosis with metabolic alkalosis would require evidence of an independent
metabolic alkalosis (e.g., HCO₃⁻ higher than expected for the degree of CO₂ retention, or a concomitant
cause such as vomiting or diuretic use). The HCO₃⁻ is appropriate for chronic compensation, not a
superimposed metabolic alkalosis.
D. Chronic respiratory acidosis with superimposed metabolic acidosis would present with an HCO₃⁻
lower than expected for chronic compensation and a pH lower than predicted for the CO₂ elevation.
Here, the HCO₃⁻ is fully compensatory and the pH is consistent with chronic respiratory acidosis alone.
──────────────────────────────────────────────────────────────────────
Advanced Pathophysiology • Educational Practice Resource
, NURS 6501 Clinical Case Studies 2026–2027
Case Study 2: Renal–Endocrine Interactions in Chronic Kidney Disease
Clinical Scenario:
A 58-year-old female with end-stage renal disease (ESRD) on maintenance hemodialysis is evaluated for bone
pain and muscle weakness. Laboratory studies reveal:
Serum calcium: 7.2 mg/dL (normal: 8.5–10.5)
Serum phosphate: 6.5 mg/dL (normal: 2.5–4.5)
Parathyroid hormone (PTH): markedly elevated
Question:
The pathophysiologic mechanism most directly responsible for the elevated PTH in this patient is:
Options:
A. Decreased renal conversion of 25-hydroxyvitamin D to 1,25-dihydroxyvitamin D
B. Increased renal excretion of calcium
C. Direct stimulation of the parathyroid gland by uremic toxins
D. Increased intestinal absorption of phosphate
Correct Answer: A. Decreased renal conversion of 25-hydroxyvitamin D to 1,25-dihydroxyvitamin D
Rationale:
In ESRD, the failing kidneys lose the capacity to perform 1α-hydroxylation, the final step in activating
vitamin D. Specifically, the proximal tubule enzyme 1α-hydroxylase converts 25-hydroxyvitamin D to its
active form, 1,25-dihydroxyvitamin D (calcitriol). Calcitriol serves two critical functions relevant to this
case: it promotes intestinal calcium absorption and it directly inhibits PTH gene transcription and
parathyroid cell proliferation. When calcitriol production falls, both of these inhibitory influences are
lost. The resulting hypocalcemia (from decreased intestinal absorption) and the direct loss of calcitriol-
mediated suppression of the parathyroid gland together drive compensatory PTH hypersecretion,
producing secondary hyperparathyroidism.
Hyperphosphatemia, also present in ESRD due to reduced renal excretion, contributes to PTH elevation
through two additional mechanisms: phosphate directly stabilizes PTH mRNA and promotes parathyroid
hyperplasia, and it lowers ionized calcium by forming calcium-phosphate complexes. However, the
question asks for the mechanism most directly responsible, and the loss of calcitriol-mediated
inhibition is the proximate endocrine driver.
Why Other Options Are Incorrect:
B. Increased renal excretion of calcium does not occur in ESRD; the failing kidney cannot excrete
calcium effectively. In fact, renal calcium excretion is reduced. Hypocalcemia in CKD results primarily
from decreased intestinal absorption (due to calcitriol deficiency) and phosphate retention, not from
renal calcium wasting.
C. While uremic toxins may contribute to parathyroid dysfunction in advanced CKD, direct stimulation of
the parathyroid gland by uremic toxins is not the primary established mechanism for secondary
hyperparathyroidism. The dominant drivers are calcitriol deficiency, hypocalcemia, and
hyperphosphatemia.
D. Increased intestinal absorption of phosphate does not occur in CKD. Phosphate absorption is
actually reduced by the calcitriol deficiency. Hyperphosphatemia in CKD results from decreased renal
excretion, not increased absorption.
──────────────────────────────────────────────────────────────────────
Case Study 3: Thyroid Axis Pathophysiology
Clinical Scenario:
Advanced Pathophysiology • Educational Practice Resource
, NURS 6501 Clinical Case Studies 2026–2027
A 45-year-old female presents with a 6-month history of progressive fatigue, weight gain, cold intolerance,
constipation, and dry skin. Physical examination reveals bradycardia (heart rate 52 bpm) and delayed deep
tendon reflexes. Laboratory studies show:
Free T4: low
Thyroid-stimulating hormone (TSH): markedly elevated
Question:
Which physiological principle best explains the elevated TSH level?
Options:
A. Increased negative feedback from low free T4 on the pituitary gland
B. Loss of inhibition from low free T4 on the pituitary gland, leading to increased TSH secretion
C. Primary dysfunction of the hypothalamus leading to increased thyrotropin-releasing hormone (TRH)
D. Increased peripheral conversion of T4 to reverse T3 (rT3)
Correct Answer: B. Loss of inhibition from low free T4 on the pituitary gland, leading to increased TSH
secretion
Rationale:
The hypothalamic–pituitary–thyroid (HPT) axis operates via negative feedback. Under normal conditions,
free T4 and T3 circulate to the anterior pituitary and hypothalamus, where they suppress the secretion of
TSH and TRH, respectively. In primary hypothyroidism, the defect lies within the thyroid gland itself—it
cannot synthesize adequate thyroid hormone despite adequate or elevated stimulation. The resulting
low circulating free T4 reduces the negative feedback signal to the pituitary. The pituitary, sensing a
deficiency in thyroid hormone, increases TSH secretion in an attempt to drive the thyroid gland to
produce more hormone. The markedly elevated TSH with low free T4 is the diagnostic hallmark of
primary hypothyroidism.
Why Other Options Are Incorrect:
A. Increased negative feedback would suppress TSH secretion, producing a low TSH. This pattern is seen
in secondary (central) hypothyroidism (pituitary failure) or hyperthyroidism. The scenario describes the
opposite: low T4 and high TSH.
C. Primary hypothalamic dysfunction leading to increased TRH would produce a pattern of tertiary
hypothyroidism (low TSH, low T4) if the hypothalamus fails to produce TRH, or would be part of a central
hypothyroidism picture. Elevated TRH would only occur if the hypothalamus were attempting to
stimulate a failing pituitary, but the clinical presentation of low T4 with high TSH points to a primary
thyroid defect, not a hypothalamic one.
D. Increased peripheral conversion of T4 to reverse T3 is a pattern seen in nonthyroidal illness (euthyroid
sick syndrome), where T4 is shunted toward inactive rT3 rather than active T3. This condition typically
presents with low or normal TSH, not markedly elevated TSH, and is not associated with the classic
hypothyroid symptoms described here.
──────────────────────────────────────────────────────────────────────
Case Study 4: Vascular Pathology
Clinical Scenario:
A 60-year-old male with a history of poorly controlled hypertension and type 2 diabetes mellitus presents to
the emergency department with sudden-onset, severe, "tearing" chest pain that radiates to the interscapular
region. He is diaphoretic and hypotensive (blood pressure 88/54 mmHg) with a heart rate of 110 bpm. A CT
angiogram demonstrates a dissection flap in the descending thoracic aorta.
Question:
The most common initiating pathophysiologic event in aortic dissection is:
Options:
Advanced Pathophysiology • Educational Practice Resource
, NURS 6501 Clinical Case Studies 2026–2027
A. Atherosclerotic plaque rupture
B. A tear in the intimal layer of the aortic wall
C. Rupture of the vasa vasorum within the media
D. Autoimmune destruction of the aortic media
Correct Answer: B. A tear in the intimal layer of the aortic wall
Rationale:
Aortic dissection is initiated by a tear in the aortic intima, which allows pulsatile blood to enter the
media under systemic pressure. This creates a false lumen that propagates distally (and sometimes
proximally) along the aortic wall, separating the intima from the adventitia. The underlying vulnerability
of the media—often related to cystic medial degeneration, chronic hypertension, or connective tissue
disorders—predisposes to this event. The classic clinical presentation is severe, abrupt, tearing pain
radiating to the back, reflecting the propagation of the dissection along the aortic wall. The initiating
event is the intimal tear.
Why Other Options Are Incorrect:
A. Atherosclerotic plaque rupture is the primary initiating event in acute coronary syndromes and
atheroembolic disease, not aortic dissection. While atherosclerosis is a risk factor for aortic disease,
the acute dissection event begins with an intimal tear, not plaque rupture.
C. Rupture of the vasa vasorum (the small vessels that supply the aortic wall) is a proposed mechanism
for intramural hematoma, a variant of aortic dissection. However, the most common initiating event in
classic aortic dissection is an intimal tear, which may or may not be preceded by vasa vasorum rupture.
Intramural hematoma is less common than classic dissection.
D. Autoimmune destruction of the aortic media is not the primary mechanism of aortic dissection. While
inflammatory aortitis (e.g., Takayasu arteritis, giant cell arteritis) can weaken the aortic wall and
predispose to dissection, this is a rare cause compared to hypertensive and degenerative etiologies.
──────────────────────────────────────────────────────────────────────
Case Study 5: Cellular Adaptation and Carcinogenesis
Clinical Scenario:
A 55-year-old male with a 30-pack-year smoking history undergoes bronchoscopy for a persistent cough and
hemoptysis. Biopsy of the bronchial epithelium reveals squamous cell carcinoma. The pathologist notes that
the surrounding bronchial mucosa demonstrates replacement of normal ciliated columnar epithelium with
stratified squamous epithelium in multiple areas.
Question:
The cellular adaptation most commonly preceding the development of this malignancy in the bronchial
epithelium is:
Options:
A. Hyperplasia
B. Metaplasia
C. Hypertrophy
D. Dysplasia
Correct Answer: B. Metaplasia
Rationale:
Chronic exposure to cigarette smoke irritates the bronchial epithelium, causing the normal ciliated
columnar epithelium to be replaced by stratified squamous epithelium—a change known as squamous
metaplasia. This is an adaptive response because squamous epithelium is more resistant to the toxic
effects of smoke than ciliated columnar epithelium. However, this adaptation comes at a cost: the
squamous epithelium lacks cilia and mucus-producing capacity, impairing mucociliary clearance. More
Advanced Pathophysiology • Educational Practice Resource
NURS 6501 Clinical Case Studies 2026–2027 | Disease
Processes & Reasoning
Prepared for Advanced Pathophysiology Exam Preparation
100 Clinical Case Studies • Advanced Pathophysiology • 2026–2027
Case Study 1: Acid–Base Physiology in Chronic Respiratory Disease
Clinical Scenario:
A 65-year-old male with a 40-pack-year history of chronic obstructive pulmonary disease (COPD) presents
with increased dyspnea, productive cough, and bilateral lower extremity edema. Arterial blood gas (ABG)
analysis reveals:
pH: 7.32
PaCO₂: 68 mmHg
HCO₃⁻: 36 mEq/L
PaO₂: 55 mmHg
Question:
This clinical picture is most consistent with which acid–base disorder?
Options:
A. Acute respiratory acidosis without renal compensation
B. Chronic respiratory acidosis with renal compensation
C. Acute respiratory acidosis with superimposed metabolic alkalosis
D. Chronic respiratory acidosis with superimposed metabolic acidosis
Correct Answer: B. Chronic respiratory acidosis with renal compensation
Rationale:
The ABG demonstrates acidemia (pH < 7.35) with an elevated PaCO₂ (> 45 mmHg), confirming respiratory
acidosis. The key to determining chronicity lies in the bicarbonate level. In acute respiratory acidosis,
HCO₃⁻ rises only slightly (1 mEq/L for every 10 mmHg increase in PaCO₂) because renal compensation
requires 3–5 days to fully develop. In chronic respiratory acidosis, the kidneys increase HCO₃⁻
reabsorption and generate new bicarbonate, producing a rise of approximately 3.5–4 mEq/L for every 10
mmHg elevation in PaCO₂.
Here, the PaCO₂ is elevated by 28 mmHg above normal (68 − 40 = 28). Expected HCO₃⁻ for chronic
compensation: 24 + (2.8 × 3.5) ≈ 33.8 mEq/L, or using 4 mEq/L per 10 mmHg: 24 + (2.8 × 4) = 35.2 mEq/L.
The patient's HCO₃⁻ of 36 mEq/L closely approximates this predicted value, indicating maximal renal
compensation. This confirms a chronic process, consistent with the patient's underlying COPD.
Why Other Options Are Incorrect:
A. Acute respiratory acidosis without renal compensation would show a pH depression proportional to
the PaCO₂ elevation with minimal HCO₃⁻ increase (expected HCO₃⁻ ≈ 24 + 2.8 = 26.8 mEq/L, not 36). The
degree of bicarbonate elevation here rules out an acute process.
C. Acute respiratory acidosis with metabolic alkalosis would require evidence of an independent
metabolic alkalosis (e.g., HCO₃⁻ higher than expected for the degree of CO₂ retention, or a concomitant
cause such as vomiting or diuretic use). The HCO₃⁻ is appropriate for chronic compensation, not a
superimposed metabolic alkalosis.
D. Chronic respiratory acidosis with superimposed metabolic acidosis would present with an HCO₃⁻
lower than expected for chronic compensation and a pH lower than predicted for the CO₂ elevation.
Here, the HCO₃⁻ is fully compensatory and the pH is consistent with chronic respiratory acidosis alone.
──────────────────────────────────────────────────────────────────────
Advanced Pathophysiology • Educational Practice Resource
, NURS 6501 Clinical Case Studies 2026–2027
Case Study 2: Renal–Endocrine Interactions in Chronic Kidney Disease
Clinical Scenario:
A 58-year-old female with end-stage renal disease (ESRD) on maintenance hemodialysis is evaluated for bone
pain and muscle weakness. Laboratory studies reveal:
Serum calcium: 7.2 mg/dL (normal: 8.5–10.5)
Serum phosphate: 6.5 mg/dL (normal: 2.5–4.5)
Parathyroid hormone (PTH): markedly elevated
Question:
The pathophysiologic mechanism most directly responsible for the elevated PTH in this patient is:
Options:
A. Decreased renal conversion of 25-hydroxyvitamin D to 1,25-dihydroxyvitamin D
B. Increased renal excretion of calcium
C. Direct stimulation of the parathyroid gland by uremic toxins
D. Increased intestinal absorption of phosphate
Correct Answer: A. Decreased renal conversion of 25-hydroxyvitamin D to 1,25-dihydroxyvitamin D
Rationale:
In ESRD, the failing kidneys lose the capacity to perform 1α-hydroxylation, the final step in activating
vitamin D. Specifically, the proximal tubule enzyme 1α-hydroxylase converts 25-hydroxyvitamin D to its
active form, 1,25-dihydroxyvitamin D (calcitriol). Calcitriol serves two critical functions relevant to this
case: it promotes intestinal calcium absorption and it directly inhibits PTH gene transcription and
parathyroid cell proliferation. When calcitriol production falls, both of these inhibitory influences are
lost. The resulting hypocalcemia (from decreased intestinal absorption) and the direct loss of calcitriol-
mediated suppression of the parathyroid gland together drive compensatory PTH hypersecretion,
producing secondary hyperparathyroidism.
Hyperphosphatemia, also present in ESRD due to reduced renal excretion, contributes to PTH elevation
through two additional mechanisms: phosphate directly stabilizes PTH mRNA and promotes parathyroid
hyperplasia, and it lowers ionized calcium by forming calcium-phosphate complexes. However, the
question asks for the mechanism most directly responsible, and the loss of calcitriol-mediated
inhibition is the proximate endocrine driver.
Why Other Options Are Incorrect:
B. Increased renal excretion of calcium does not occur in ESRD; the failing kidney cannot excrete
calcium effectively. In fact, renal calcium excretion is reduced. Hypocalcemia in CKD results primarily
from decreased intestinal absorption (due to calcitriol deficiency) and phosphate retention, not from
renal calcium wasting.
C. While uremic toxins may contribute to parathyroid dysfunction in advanced CKD, direct stimulation of
the parathyroid gland by uremic toxins is not the primary established mechanism for secondary
hyperparathyroidism. The dominant drivers are calcitriol deficiency, hypocalcemia, and
hyperphosphatemia.
D. Increased intestinal absorption of phosphate does not occur in CKD. Phosphate absorption is
actually reduced by the calcitriol deficiency. Hyperphosphatemia in CKD results from decreased renal
excretion, not increased absorption.
──────────────────────────────────────────────────────────────────────
Case Study 3: Thyroid Axis Pathophysiology
Clinical Scenario:
Advanced Pathophysiology • Educational Practice Resource
, NURS 6501 Clinical Case Studies 2026–2027
A 45-year-old female presents with a 6-month history of progressive fatigue, weight gain, cold intolerance,
constipation, and dry skin. Physical examination reveals bradycardia (heart rate 52 bpm) and delayed deep
tendon reflexes. Laboratory studies show:
Free T4: low
Thyroid-stimulating hormone (TSH): markedly elevated
Question:
Which physiological principle best explains the elevated TSH level?
Options:
A. Increased negative feedback from low free T4 on the pituitary gland
B. Loss of inhibition from low free T4 on the pituitary gland, leading to increased TSH secretion
C. Primary dysfunction of the hypothalamus leading to increased thyrotropin-releasing hormone (TRH)
D. Increased peripheral conversion of T4 to reverse T3 (rT3)
Correct Answer: B. Loss of inhibition from low free T4 on the pituitary gland, leading to increased TSH
secretion
Rationale:
The hypothalamic–pituitary–thyroid (HPT) axis operates via negative feedback. Under normal conditions,
free T4 and T3 circulate to the anterior pituitary and hypothalamus, where they suppress the secretion of
TSH and TRH, respectively. In primary hypothyroidism, the defect lies within the thyroid gland itself—it
cannot synthesize adequate thyroid hormone despite adequate or elevated stimulation. The resulting
low circulating free T4 reduces the negative feedback signal to the pituitary. The pituitary, sensing a
deficiency in thyroid hormone, increases TSH secretion in an attempt to drive the thyroid gland to
produce more hormone. The markedly elevated TSH with low free T4 is the diagnostic hallmark of
primary hypothyroidism.
Why Other Options Are Incorrect:
A. Increased negative feedback would suppress TSH secretion, producing a low TSH. This pattern is seen
in secondary (central) hypothyroidism (pituitary failure) or hyperthyroidism. The scenario describes the
opposite: low T4 and high TSH.
C. Primary hypothalamic dysfunction leading to increased TRH would produce a pattern of tertiary
hypothyroidism (low TSH, low T4) if the hypothalamus fails to produce TRH, or would be part of a central
hypothyroidism picture. Elevated TRH would only occur if the hypothalamus were attempting to
stimulate a failing pituitary, but the clinical presentation of low T4 with high TSH points to a primary
thyroid defect, not a hypothalamic one.
D. Increased peripheral conversion of T4 to reverse T3 is a pattern seen in nonthyroidal illness (euthyroid
sick syndrome), where T4 is shunted toward inactive rT3 rather than active T3. This condition typically
presents with low or normal TSH, not markedly elevated TSH, and is not associated with the classic
hypothyroid symptoms described here.
──────────────────────────────────────────────────────────────────────
Case Study 4: Vascular Pathology
Clinical Scenario:
A 60-year-old male with a history of poorly controlled hypertension and type 2 diabetes mellitus presents to
the emergency department with sudden-onset, severe, "tearing" chest pain that radiates to the interscapular
region. He is diaphoretic and hypotensive (blood pressure 88/54 mmHg) with a heart rate of 110 bpm. A CT
angiogram demonstrates a dissection flap in the descending thoracic aorta.
Question:
The most common initiating pathophysiologic event in aortic dissection is:
Options:
Advanced Pathophysiology • Educational Practice Resource
, NURS 6501 Clinical Case Studies 2026–2027
A. Atherosclerotic plaque rupture
B. A tear in the intimal layer of the aortic wall
C. Rupture of the vasa vasorum within the media
D. Autoimmune destruction of the aortic media
Correct Answer: B. A tear in the intimal layer of the aortic wall
Rationale:
Aortic dissection is initiated by a tear in the aortic intima, which allows pulsatile blood to enter the
media under systemic pressure. This creates a false lumen that propagates distally (and sometimes
proximally) along the aortic wall, separating the intima from the adventitia. The underlying vulnerability
of the media—often related to cystic medial degeneration, chronic hypertension, or connective tissue
disorders—predisposes to this event. The classic clinical presentation is severe, abrupt, tearing pain
radiating to the back, reflecting the propagation of the dissection along the aortic wall. The initiating
event is the intimal tear.
Why Other Options Are Incorrect:
A. Atherosclerotic plaque rupture is the primary initiating event in acute coronary syndromes and
atheroembolic disease, not aortic dissection. While atherosclerosis is a risk factor for aortic disease,
the acute dissection event begins with an intimal tear, not plaque rupture.
C. Rupture of the vasa vasorum (the small vessels that supply the aortic wall) is a proposed mechanism
for intramural hematoma, a variant of aortic dissection. However, the most common initiating event in
classic aortic dissection is an intimal tear, which may or may not be preceded by vasa vasorum rupture.
Intramural hematoma is less common than classic dissection.
D. Autoimmune destruction of the aortic media is not the primary mechanism of aortic dissection. While
inflammatory aortitis (e.g., Takayasu arteritis, giant cell arteritis) can weaken the aortic wall and
predispose to dissection, this is a rare cause compared to hypertensive and degenerative etiologies.
──────────────────────────────────────────────────────────────────────
Case Study 5: Cellular Adaptation and Carcinogenesis
Clinical Scenario:
A 55-year-old male with a 30-pack-year smoking history undergoes bronchoscopy for a persistent cough and
hemoptysis. Biopsy of the bronchial epithelium reveals squamous cell carcinoma. The pathologist notes that
the surrounding bronchial mucosa demonstrates replacement of normal ciliated columnar epithelium with
stratified squamous epithelium in multiple areas.
Question:
The cellular adaptation most commonly preceding the development of this malignancy in the bronchial
epithelium is:
Options:
A. Hyperplasia
B. Metaplasia
C. Hypertrophy
D. Dysplasia
Correct Answer: B. Metaplasia
Rationale:
Chronic exposure to cigarette smoke irritates the bronchial epithelium, causing the normal ciliated
columnar epithelium to be replaced by stratified squamous epithelium—a change known as squamous
metaplasia. This is an adaptive response because squamous epithelium is more resistant to the toxic
effects of smoke than ciliated columnar epithelium. However, this adaptation comes at a cost: the
squamous epithelium lacks cilia and mucus-producing capacity, impairing mucociliary clearance. More
Advanced Pathophysiology • Educational Practice Resource
