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TEST BANK For Fundamentals of Physics 10th Edition By Resnick, Walker and Halliday Chapters 1 - 44

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TEST BANK For Fundamentals of Physics 10th Edition By Resnick, Walker and Halliday Chapters 1 - 44

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TEST BANK For Fundamentals of Physics
gw gw gw gw gw




10th Edition By Resnick, Walker and Halliday
gw gw gw gw gw gw gw




gw Chapters 1 - 44
gw gw gw

,Chapter 1 gw




1. Various geometric formulas are given in Appendix E.
gw gw gw gw gw gw gw




(a) Expressing the radius of the Earth as gw gw gw gw gw gw




R g w  g w 6.37 gw  106 m103 km m  6.37  103
gw gw gw gw gw g w gw gw g w km,

its circumference is s  2 R  2 (6.37  103 km)  4.00 104 km.
gw gw g w gw gw gw gw gw gw gw gw g w gw gw gw g w




(b) The surface area of Earth is A 
gw gw gw gw gw gw gw  4  6.37  103
gw gw gw gw gw  5.10 
gw gw km2.
4 R2 108
km 
gw gw 2 gw

gw




4 4
 6.37  103 km 
3 gw gw gw
(c) The volume of Earth is V  R3   1.08  1012 km 3 .
gwgw gw
gw gw gw gw gw gw g w gw gwgw gwgw gw gw gwgw gw gw gw gwgw


3 3

2. The conversion factors are: 1 gry  1/10 line , 1 line  1/12 inch and 1
gw gw gw gw gw gw gw gw gw g w gw gw gw g w gw gw



point = 1/72inch. The factors imply that
gw gw gw gw gw gw gw gw




1 gry = (1/10)(1/12)(72 points) = 0.60 point.
gw gw gw gw gw gw gw




Thus, 1 gry2 = (0.60 point)2 = 0.36 point2, which means that 0.50
gw gw gw gw gw gw gw gw gw gw gw gw g w gry 2 =
gw g w 0.18 g w point 2
.
gw




3. The metric prefixes (micro, pico, nano, …) are given for ready reference on
gw gw gw gw gw gw gw gw gw gw gw gw


the insidefront cover of the textbook (see also Table 1–2).
gw gw gw gw gw gw gw gw gw gw gw




(a) Since 1 km = 1  103 m and 1 m = 1  106 m,
gw gw gw gw gw gw gw gw gw gw gw gw gw gw gw gw




1km  103 m  g w gw gw g w g w 103  m m 
gw g w gw m.
109
m106
gw
gw




The given measurement is 1.0 km (two significant
g w g w g w g w g w g w g w g w figures), g w which
implies our resultshould be written as 1.0  109 m.
g w g w g w gw gw gw gw gw gw gw gw




(b) We calculate the number of microns in 1 centimeter. Since 1 cm = 102 m,
gw gw gw gw gw gw gw gw gw gw gw gw gw gw gw




1cm = 102 m = g w gw gw gw g w 102m106 gw  m gw m.
g w m  104 gw gw




We conclude that the fraction of one centimeter equal to 1.0 m is 1.0
gw gw gw gw gw gw gw gw gw gw gw gw gw

,  104.(c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m,
gw gw gw gw gw gw gw gw gw gw gw gw gw




1

, 2 CHAPTER 1



1.0 yd = 0.91m106  m
gw g w gw gw gw g w m  gw m.
9.1  105
gw gw gw




4. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas
gw gw gw gw gw gw gw gw gw gw gw gw gw


= 1 inch, weobtain
gw gw gw
 6 picas 
g w gw


 = 0.80  1.9 picas.
gw gw gw g w
0.80 cm 1
cm 
gw gw g w

  
gw gw

inch
2.54 cm 1 inch gw
 gw
gw gw
gw gw
gw
gw g w


   
(b) With 12 points = 1 pica, we
gw gw gw gw gw gw gw


have
gw



 =
0.80 cm 0.80 1  6 picas  12 points 
cm   
gw gw gw

  
gw g w gw gw g w gw g w

inch 23 points.

gw gw gw g w g w gw
gw gw
2.54 cm 1 inch gw
gw 1 pica gw gw g w gw


   


5. Given that 1  201.168 m , 1 rod 
gw gw g w gw gw g w gw gw and 1 chain  20.117 m , we find
gw gw gw gw gw gw g w gw


furlong
gw 5.0292 m gw gw



the relevant conversion factors to be
gw gw gw gw gw


1 rod
1.0 furlong  201.168 m  (201.168  40 rods,
gw
gw gw gw gw gw gw g w gw


m)
gw gw
5.0292 m

and
1 chain
1.0 furlong  201.168 m  10 chains .
gw
g w g w gw gw gw gw gw


(201.168 m )
gw gw gw
20.117
m gw


Note the cancellation of m (meters),
g w g w g w g w g w g w the unwanted unit. Using
g w g w g w g w the
given conversionfactors, we find
g w g w gw gw gw




(a) the distance d in rods to be
gw gw gw gw gw gw

40
d  4.0 furlongs 4.0 furlongs
g w gw gw gw gw g w
 160 rods,
gw gw

rods
gw




1 furlong
gw




(b) and that distance in chains to be
gw gw gw gw gw gw




10 chains
d  4.0 furlongs 4.0 furlongs  40 chains.
gw g w
g w gw gw gw gw gw gw


1 furlong gw




6. We make use of Table 1-6.
gw gw gw gw gw




(a) We look at the first (―cahiz‖) column: 1 fanega is equivalent to what amount
gw gw gw gw gw gw gw gw gw gw gw gw gw


of cahiz? We note from the already completed part of the table that 1 cahiz
gw gw gw gw gw gw gw gw gw gw gw gw gw gw gw


equals a dozen12 fanega. Thus, 1 fanega = 1
gw gw gw cahiz, or 8.33  102 cahiz.
gw gw gw gw gw g w g w gw gw gw gw gw


g wSimilarly, ―1 cahiz = 48 cuartilla‖ (in the
gw gw gw gw gw gw gw




already completed part) implies that 1 cuartilla =
gw gw gw gw gw gw gw
1
gw
gw cahiz, or 2.08 
48
gw gw gw g w 102 g w cahiz.
gw Continuing g w in g w this g w way, g w the g w remaining g w entries g w in g w the g w first g w column g w are

Connected book
 image
David Halliday, Robert Resnick, Jearl Walker Fundamentals of Physics 10e, Volume 2 + WileyPLUS Registration Card
Publisher: 2013 ISBN: 9781118731406 Edition: Unknown

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