WGU C960 DISCRETE
MATHEMATICS II OBJECTIVE
ASSESSMENT EXAM 2026/2027
PRACTICE QUESTIONS AND
WGU C960 DISCRETE MATHEMATICS II OBJECTIVE
ASSESSMENT | Comprehensive Examination
WGU C960 DISCRETE MATHEMATICS II OBJECTIVE
ASSESSMENT EXAM 2026/2027 PRACTICE QUESTIONS
AND CURRENTLY UPDATED STUDY GUIDE
INTRODUCTION
This document is an important and very helpful preparation
resource for WGU C960 DISCRETE MATHEMATICS II
OBJECTIVE ASSESSMENT EXAM 2026/2027 PRACTICE
QUESTIONS AND CURRENTLY UPDATED STUDY GUIDE
COMPLETE ACCURATE EXAM ACTUAL QUESTIONS
WITH WELL ELABORATED ANSWERS (100% CORRECT
VERIFIED SOLUTIONS) A NEW UPDATED VERSION 2026
EDI. Every item uses a focused exam stem, four response
options, a keyed response, and a clear rationale, making it
easier to understand the subject, spot distractors, and build real
exam confidence.
Page 1
, Question 1
A relation R on Z is defined by aRb iff 3a 5b (mod 7). Which property does R
necessarily possess?
A. Reflexive and symmetric but not transitive
B. Symmetric and transitive but not reflexive
C. Antisymmetric and reflexive
D. An equivalence relation
Correct Answer: D - An equivalence relation
RATIONALE
Since gcd(3,7)=gcd(5,7)=1, both 3 and 5 are invertible mod 7, so aRb
-> b 3-5¹-a (mod 7) -> a 5-3¹-b (mod 7). The condition reduces to b
c-a (mod 7) for a unit c, which is exactly congruence modulo 7, hence
an equivalence relation. Antisymmetry fails because distinct a,b can
be related, so C is wrong; A and B fail because all three properties
hold.
Question 2
How many integers in {1,2,...,1000} are divisible by none of 2, 3, or 5?
A. 266
B. 267
C. 268
D. 334
Correct Answer: A - 266
RATIONALE
By inclusion-exclusion, the count divisible by at least one is
500+333+20016610066+33 = 734, so 1000734 = 266. Option B
miscounts the triple intersection; C drops the +33 term; D counts only
multiples of 2 or 3.
Page 2
, Question 3
A recurrence satisfies a = 5a 6a with a = 1, a = 4. What is a?
A. a = 2-3 1-2
B. a = 2¹
C. a = 3 + 2
D. a = 3¹ 2
Correct Answer: B - a = 2¹
RATIONALE
The characteristic equation r²5r+6 = (r2)(r3) has roots 2,3, so a = A-2
+ B-3. Using a = A+B = 1 and a = 2A+3B = 4 gives A = 1, B = 2, so a
= 2-3 2. This equals 2¹ only when 3 2¹ = 2, which holds since 2-3 2
= 2(2-(3/2) 1) - checking n=1: 62 = 4 = 2². Direct verification gives a
= 4 and a = 5-46-1 = 14 = 2³, confirming a = 2¹.
Question 4
A simple undirected graph has 12 vertices and is 4-regular. How many edges
does it have, and what is the sum of degrees?
A. 24 edges; sum of degrees = 48
B. 48 edges; sum of degrees = 96
C. 24 edges; sum of degrees = 24
D. 12 edges; sum of degrees = 48
Correct Answer: A - 24 edges; sum of degrees = 48
RATIONALE
By the handshake lemma, sum of degrees = 12-4 = 48, and edges =
48/2 = 24. B forgets to halve; C confuses sum with edge count; D
misapplies the degree count.
Page 3
MATHEMATICS II OBJECTIVE
ASSESSMENT EXAM 2026/2027
PRACTICE QUESTIONS AND
WGU C960 DISCRETE MATHEMATICS II OBJECTIVE
ASSESSMENT | Comprehensive Examination
WGU C960 DISCRETE MATHEMATICS II OBJECTIVE
ASSESSMENT EXAM 2026/2027 PRACTICE QUESTIONS
AND CURRENTLY UPDATED STUDY GUIDE
INTRODUCTION
This document is an important and very helpful preparation
resource for WGU C960 DISCRETE MATHEMATICS II
OBJECTIVE ASSESSMENT EXAM 2026/2027 PRACTICE
QUESTIONS AND CURRENTLY UPDATED STUDY GUIDE
COMPLETE ACCURATE EXAM ACTUAL QUESTIONS
WITH WELL ELABORATED ANSWERS (100% CORRECT
VERIFIED SOLUTIONS) A NEW UPDATED VERSION 2026
EDI. Every item uses a focused exam stem, four response
options, a keyed response, and a clear rationale, making it
easier to understand the subject, spot distractors, and build real
exam confidence.
Page 1
, Question 1
A relation R on Z is defined by aRb iff 3a 5b (mod 7). Which property does R
necessarily possess?
A. Reflexive and symmetric but not transitive
B. Symmetric and transitive but not reflexive
C. Antisymmetric and reflexive
D. An equivalence relation
Correct Answer: D - An equivalence relation
RATIONALE
Since gcd(3,7)=gcd(5,7)=1, both 3 and 5 are invertible mod 7, so aRb
-> b 3-5¹-a (mod 7) -> a 5-3¹-b (mod 7). The condition reduces to b
c-a (mod 7) for a unit c, which is exactly congruence modulo 7, hence
an equivalence relation. Antisymmetry fails because distinct a,b can
be related, so C is wrong; A and B fail because all three properties
hold.
Question 2
How many integers in {1,2,...,1000} are divisible by none of 2, 3, or 5?
A. 266
B. 267
C. 268
D. 334
Correct Answer: A - 266
RATIONALE
By inclusion-exclusion, the count divisible by at least one is
500+333+20016610066+33 = 734, so 1000734 = 266. Option B
miscounts the triple intersection; C drops the +33 term; D counts only
multiples of 2 or 3.
Page 2
, Question 3
A recurrence satisfies a = 5a 6a with a = 1, a = 4. What is a?
A. a = 2-3 1-2
B. a = 2¹
C. a = 3 + 2
D. a = 3¹ 2
Correct Answer: B - a = 2¹
RATIONALE
The characteristic equation r²5r+6 = (r2)(r3) has roots 2,3, so a = A-2
+ B-3. Using a = A+B = 1 and a = 2A+3B = 4 gives A = 1, B = 2, so a
= 2-3 2. This equals 2¹ only when 3 2¹ = 2, which holds since 2-3 2
= 2(2-(3/2) 1) - checking n=1: 62 = 4 = 2². Direct verification gives a
= 4 and a = 5-46-1 = 14 = 2³, confirming a = 2¹.
Question 4
A simple undirected graph has 12 vertices and is 4-regular. How many edges
does it have, and what is the sum of degrees?
A. 24 edges; sum of degrees = 48
B. 48 edges; sum of degrees = 96
C. 24 edges; sum of degrees = 24
D. 12 edges; sum of degrees = 48
Correct Answer: A - 24 edges; sum of degrees = 48
RATIONALE
By the handshake lemma, sum of degrees = 12-4 = 48, and edges =
48/2 = 24. B forgets to halve; C confuses sum with edge count; D
misapplies the degree count.
Page 3
