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EEE 334 Circuits II Quiz 1 | Operational Amplifiers (Op-Amps) | Electrical Engineering Study Review | rated 100% correct.-ASU.

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EEE 334 CIRCUITS II QUIZ 1 | OPERATIONAL AMPLIFIERS (OP-AMPS) | ELECTRICAL ENGINEERING STUDY REVIEW | RATED 100% CORRECT.-ASU. This EEE 334 Circuits II Quiz 1 resource from Arizona State University focuses on Operational Amplifiers (Op-Amps) and essential analog circuit analysis. Topics include ideal op-amp characteristics, infinite gain and input impedance, zero output impedance, virtual short, inverting and non-inverting amplifier configurations, voltage gain calculations, summing amplifiers, comparators, and negative feedback. Designed for 2026/2027 exam preparation, this resource provides focused questions and answers to reinforce fundamental Circuits II concepts and op-amp analysis.

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,
, EEE 334 Circuits II Quiz 1 | Operational
Amplifiers (Op-Amps) | Electrical Engineering
Study Review | rated 100% correct.-ASU.

SECTION 1: IDEAL OP-AMP FUNDAMENTALS
(Questions 1–10)
1. Which of the following best describes an ideal operational
amplifier?

A) Infinite input impedance, infinite output impedance, infinite gain
B) Infinite input impedance, zero output impedance, infinite gain
C) Zero input impedance, infinite output impedance, infinite gain
D) Infinite input impedance, zero output impedance, zero gain

Correct Answer: B

Rationale: An ideal op-amp has infinite input impedance (Z_in = ∞) so it
draws no current from the source, zero output impedance (Z_out = 0) so it
can supply unlimited current, and infinite open-loop gain (A = ∞).

Source: EEE 334 Quiz 1 Op-Amps Study Materials




2. What is the first "Golden Rule" of ideal op-amp analysis?

A) The output voltage equals the input voltage
B) The inputs draw no current
C) The output impedance is infinite
D) The op-amp always saturates

Correct Answer: B

Rationale: Golden Rule #1: The inputs draw no current. This is because
the input impedance is infinite (Z_in = ∞). This allows us to assume that the
current into the inverting and non-inverting terminals is zero.

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