CHEM 120 Week 4 Lab Report 4 Ideal Gas Law
200 Multiple Choice Questions with Verified
Answers and Rationales for Chemistry Lab
Success||Graded A+
SECTION 1: IDEAL GAS LAW FUNDAMENTALS (Questions 1–40)
Question 1
The ideal gas law is expressed by which equation?
A) PV = nRT
B) P₁V₁ = P₂V₂
C) V₁/T₁ = V₂/T₂
D) P₁/T₁ = P₂/T₂
Correct Answer: A
Rationale: The ideal gas law combines Boyle's law, Charles's law, and Avogadro's law into a
single equation: PV = nRT, where P is pressure, V is volume, n is moles, R is the gas constant, and
T is temperature in Kelvin .
Question 2
In the ideal gas law, what does the variable "n" represent?
A) Number of molecules
B) Number of moles of gas
C) Number of collisions
D) Number of atmospheres
Correct Answer: B
Rationale: In PV = nRT, the variable n represents the number of moles of gas present .
Question 3
,What is the value of the ideal gas constant R when pressure is in atmospheres and volume is in
liters?
A) 8.314
B) 0.0821
C) 62.4
D) 1.987
Correct Answer: B
Rationale: When pressure is measured in atmospheres and volume in liters, R = 0.0821
L·atm/mol·K .
Question 4
Which temperature scale must be used in the ideal gas law?
A) Celsius
B) Fahrenheit
C) Kelvin
D) Rankine
Correct Answer: C
Rationale: The ideal gas law requires absolute temperature, which is measured in Kelvin. Celsius
and Fahrenheit scales cannot be used because they do not begin at absolute zero .
Question 5
Convert 25°C to Kelvin.
A) 25 K
B) 248 K
C) 298 K
D) 325 K
Correct Answer: C
Rationale: K = °C + 273. Therefore, 25 + 273 = 298 K .
Question 6
,What is standard temperature and pressure (STP)?
A) 0°C and 1 atm
B) 25°C and 1 atm
C) 0°C and 760 atm
D) 100°C and 1 atm
Correct Answer: A
Rationale: STP is defined as 0°C (273.15 K) and 1 atmosphere pressure .
Question 7
At STP, one mole of any ideal gas occupies what volume?
A) 11.2 L
B) 22.4 L
C) 44.8 L
D) 33.6 L
Correct Answer: B
Rationale: At STP (273 K and 1 atm), one mole of any ideal gas occupies a volume of
approximately 22.4 liters .
Question 8
The gas constant R has a value of 8.314 when expressed in which units?
A) L·atm/mol·K
B) J/mol·K
C) L·mmHg/mol·K
D) cal/mol·K
Correct Answer: B
Rationale: The universal gas constant R = 8.314 J/(mol·K) when using SI units (Joules, moles,
Kelvin) .
Question 9
, Which of the following is NOT a variable in the ideal gas law?
A) Pressure
B) Volume
C) Density
D) Temperature
Correct Answer: C
Rationale: The ideal gas law variables are pressure (P), volume (V), moles (n), temperature (T),
and the gas constant (R). Density is not a direct variable in the equation .
Question 10
The ideal gas law is a combination of which gas laws?
A) Boyle's, Charles's, and Avogadro's laws
B) Dalton's and Graham's laws
C) Henry's and Raoult's laws
D) Newton's and Kepler's laws
Correct Answer: A
Rationale: The ideal gas law combines Boyle's law (P-V relationship), Charles's law (V-T
relationship), and Avogadro's law (V-n relationship) .
Question 11
What is the pressure of a gas if 2.0 moles occupy 10.0 L at 300 K?
A) 4.92 atm
B) 2.46 atm
C) 9.84 atm
D) 1.23 atm
Correct Answer: A
Rationale: P = nRT/V = (2.0 mol)(0.0821 L·atm/mol·K)(300 K)/(10.0 L) = 4.92 atm.
Question 12
200 Multiple Choice Questions with Verified
Answers and Rationales for Chemistry Lab
Success||Graded A+
SECTION 1: IDEAL GAS LAW FUNDAMENTALS (Questions 1–40)
Question 1
The ideal gas law is expressed by which equation?
A) PV = nRT
B) P₁V₁ = P₂V₂
C) V₁/T₁ = V₂/T₂
D) P₁/T₁ = P₂/T₂
Correct Answer: A
Rationale: The ideal gas law combines Boyle's law, Charles's law, and Avogadro's law into a
single equation: PV = nRT, where P is pressure, V is volume, n is moles, R is the gas constant, and
T is temperature in Kelvin .
Question 2
In the ideal gas law, what does the variable "n" represent?
A) Number of molecules
B) Number of moles of gas
C) Number of collisions
D) Number of atmospheres
Correct Answer: B
Rationale: In PV = nRT, the variable n represents the number of moles of gas present .
Question 3
,What is the value of the ideal gas constant R when pressure is in atmospheres and volume is in
liters?
A) 8.314
B) 0.0821
C) 62.4
D) 1.987
Correct Answer: B
Rationale: When pressure is measured in atmospheres and volume in liters, R = 0.0821
L·atm/mol·K .
Question 4
Which temperature scale must be used in the ideal gas law?
A) Celsius
B) Fahrenheit
C) Kelvin
D) Rankine
Correct Answer: C
Rationale: The ideal gas law requires absolute temperature, which is measured in Kelvin. Celsius
and Fahrenheit scales cannot be used because they do not begin at absolute zero .
Question 5
Convert 25°C to Kelvin.
A) 25 K
B) 248 K
C) 298 K
D) 325 K
Correct Answer: C
Rationale: K = °C + 273. Therefore, 25 + 273 = 298 K .
Question 6
,What is standard temperature and pressure (STP)?
A) 0°C and 1 atm
B) 25°C and 1 atm
C) 0°C and 760 atm
D) 100°C and 1 atm
Correct Answer: A
Rationale: STP is defined as 0°C (273.15 K) and 1 atmosphere pressure .
Question 7
At STP, one mole of any ideal gas occupies what volume?
A) 11.2 L
B) 22.4 L
C) 44.8 L
D) 33.6 L
Correct Answer: B
Rationale: At STP (273 K and 1 atm), one mole of any ideal gas occupies a volume of
approximately 22.4 liters .
Question 8
The gas constant R has a value of 8.314 when expressed in which units?
A) L·atm/mol·K
B) J/mol·K
C) L·mmHg/mol·K
D) cal/mol·K
Correct Answer: B
Rationale: The universal gas constant R = 8.314 J/(mol·K) when using SI units (Joules, moles,
Kelvin) .
Question 9
, Which of the following is NOT a variable in the ideal gas law?
A) Pressure
B) Volume
C) Density
D) Temperature
Correct Answer: C
Rationale: The ideal gas law variables are pressure (P), volume (V), moles (n), temperature (T),
and the gas constant (R). Density is not a direct variable in the equation .
Question 10
The ideal gas law is a combination of which gas laws?
A) Boyle's, Charles's, and Avogadro's laws
B) Dalton's and Graham's laws
C) Henry's and Raoult's laws
D) Newton's and Kepler's laws
Correct Answer: A
Rationale: The ideal gas law combines Boyle's law (P-V relationship), Charles's law (V-T
relationship), and Avogadro's law (V-n relationship) .
Question 11
What is the pressure of a gas if 2.0 moles occupy 10.0 L at 300 K?
A) 4.92 atm
B) 2.46 atm
C) 9.84 atm
D) 1.23 atm
Correct Answer: A
Rationale: P = nRT/V = (2.0 mol)(0.0821 L·atm/mol·K)(300 K)/(10.0 L) = 4.92 atm.
Question 12
