New Jersey Master Electrician Exam
Practice Questions and Correct Answers
(Verified Answers) Plus Rationales 2027
Q&A | Instant Download Pdf
General Requirements, Theory, Branch Circuits, Grounding & Bonding, and
Overcurrent Protection
1. What is the primary purpose of the National Electrical Code (NEC)?
A. Establish electrical utility rates
B. Provide practical safeguarding requirements for persons and property from
hazards arising from the use of electricity
C. Establish construction labor rates
D. Specify the electrical equipment brands that must be used
Answer: B. Provide practical safeguarding requirements for persons and
property from hazards arising from the use of electricity
Rationale: The NEC is intended to provide practical safeguards against hazards
associated with electricity. It establishes minimum requirements for electrical
installations rather than regulating utility rates, labor costs, or specific
manufacturers.
2. Under New Jersey's current Electrical Subcode, which NEC edition is currently
adopted?
A. 2017 NEC
B. 2020 NEC
C. 2023 NEC
D. 2026 NEC
Answer: C. 2023 NEC
,Rationale: New Jersey's current construction-code information identifies the
National Electrical Code (NFPA 70)/2023 as the Electrical Subcode, with the
current adoption effective August 17, 2026. (NJ.gov)
3. Which NEC article contains the general requirements for electrical
installations and equipment use?
A. Article 110
B. Article 210
C. Article 250
D. Article 300
Answer: A. Article 110
Rationale: Article 110 contains general requirements for electrical installations,
including examination and approval, electrical connections, conductor
termination, working space, and equipment installation requirements.
4. What does Ohm's Law indicate when calculating current?
A. Current equals resistance multiplied by voltage
B. Current equals voltage divided by resistance
C. Current equals voltage plus resistance
D. Current equals resistance divided by voltage
Answer: B. Current equals voltage divided by resistance
Rationale: Ohm's Law is expressed as I = E/R. Current is calculated by dividing
voltage by resistance.
5. A 240-volt resistive load has a resistance of 30 ohms. What current does it
draw?
A. 4 A
B. 6 A
,C. 8 A
D. 12 A
Answer: C. 8 A
Rationale: Using Ohm's Law, I = E/R = 240/30 = 8 amperes.
6. What is the unit of electrical resistance?
A. Watt
B. Volt
C. Ampere
D. Ohm
Answer: D. Ohm
Rationale: Electrical resistance is measured in ohms, represented by the symbol Ω.
7. Which formula is used to calculate electrical power in a simple DC or resistive
circuit?
A. P = E × I
B. P = E ÷ I
C. P = R ÷ I
D. P = E + I
Answer: A. P = E × I
Rationale: Electrical power is calculated as voltage multiplied by current.
Therefore, P = E × I, with power expressed in watts.
8. A 120-volt circuit supplies a 10-ampere resistive load. What is the
approximate power?
A. 12 W
B. 120 W
, C. 1,200 W
D. 12,000 W
Answer: C. 1,200 W
Rationale: Applying P = E × I gives 120 × 10 = 1,200 watts.
9. What is the primary purpose of an overcurrent protective device?
A. Increase circuit voltage
B. Protect conductors and equipment against excessive current
C. Improve the power factor of a motor
D. Establish the grounding electrode system
Answer: B. Protect conductors and equipment against excessive current
Rationale: Overcurrent protective devices such as fuses and circuit breakers open
circuits when excessive current occurs under their applicable operating conditions.
10. Which condition is an example of an overcurrent?
A. A conductor carrying its normal design current
B. A properly balanced load
C. A circuit carrying current above its allowable rating
D. A properly bonded enclosure
Answer: C. A circuit carrying current above its allowable rating
Rationale: Overcurrent includes current exceeding the rated or allowable capacity
of conductors or equipment. Overload, short circuit, and ground fault conditions
can produce overcurrent.
11. What is the primary purpose of an equipment grounding conductor?
A. Carry normal neutral current
B. Provide a low-impedance path for fault current
Practice Questions and Correct Answers
(Verified Answers) Plus Rationales 2027
Q&A | Instant Download Pdf
General Requirements, Theory, Branch Circuits, Grounding & Bonding, and
Overcurrent Protection
1. What is the primary purpose of the National Electrical Code (NEC)?
A. Establish electrical utility rates
B. Provide practical safeguarding requirements for persons and property from
hazards arising from the use of electricity
C. Establish construction labor rates
D. Specify the electrical equipment brands that must be used
Answer: B. Provide practical safeguarding requirements for persons and
property from hazards arising from the use of electricity
Rationale: The NEC is intended to provide practical safeguards against hazards
associated with electricity. It establishes minimum requirements for electrical
installations rather than regulating utility rates, labor costs, or specific
manufacturers.
2. Under New Jersey's current Electrical Subcode, which NEC edition is currently
adopted?
A. 2017 NEC
B. 2020 NEC
C. 2023 NEC
D. 2026 NEC
Answer: C. 2023 NEC
,Rationale: New Jersey's current construction-code information identifies the
National Electrical Code (NFPA 70)/2023 as the Electrical Subcode, with the
current adoption effective August 17, 2026. (NJ.gov)
3. Which NEC article contains the general requirements for electrical
installations and equipment use?
A. Article 110
B. Article 210
C. Article 250
D. Article 300
Answer: A. Article 110
Rationale: Article 110 contains general requirements for electrical installations,
including examination and approval, electrical connections, conductor
termination, working space, and equipment installation requirements.
4. What does Ohm's Law indicate when calculating current?
A. Current equals resistance multiplied by voltage
B. Current equals voltage divided by resistance
C. Current equals voltage plus resistance
D. Current equals resistance divided by voltage
Answer: B. Current equals voltage divided by resistance
Rationale: Ohm's Law is expressed as I = E/R. Current is calculated by dividing
voltage by resistance.
5. A 240-volt resistive load has a resistance of 30 ohms. What current does it
draw?
A. 4 A
B. 6 A
,C. 8 A
D. 12 A
Answer: C. 8 A
Rationale: Using Ohm's Law, I = E/R = 240/30 = 8 amperes.
6. What is the unit of electrical resistance?
A. Watt
B. Volt
C. Ampere
D. Ohm
Answer: D. Ohm
Rationale: Electrical resistance is measured in ohms, represented by the symbol Ω.
7. Which formula is used to calculate electrical power in a simple DC or resistive
circuit?
A. P = E × I
B. P = E ÷ I
C. P = R ÷ I
D. P = E + I
Answer: A. P = E × I
Rationale: Electrical power is calculated as voltage multiplied by current.
Therefore, P = E × I, with power expressed in watts.
8. A 120-volt circuit supplies a 10-ampere resistive load. What is the
approximate power?
A. 12 W
B. 120 W
, C. 1,200 W
D. 12,000 W
Answer: C. 1,200 W
Rationale: Applying P = E × I gives 120 × 10 = 1,200 watts.
9. What is the primary purpose of an overcurrent protective device?
A. Increase circuit voltage
B. Protect conductors and equipment against excessive current
C. Improve the power factor of a motor
D. Establish the grounding electrode system
Answer: B. Protect conductors and equipment against excessive current
Rationale: Overcurrent protective devices such as fuses and circuit breakers open
circuits when excessive current occurs under their applicable operating conditions.
10. Which condition is an example of an overcurrent?
A. A conductor carrying its normal design current
B. A properly balanced load
C. A circuit carrying current above its allowable rating
D. A properly bonded enclosure
Answer: C. A circuit carrying current above its allowable rating
Rationale: Overcurrent includes current exceeding the rated or allowable capacity
of conductors or equipment. Overload, short circuit, and ground fault conditions
can produce overcurrent.
11. What is the primary purpose of an equipment grounding conductor?
A. Carry normal neutral current
B. Provide a low-impedance path for fault current
