TEST BANK For Fundamentals of Physics
10th Edition By Resnick, Walker and Halliday
Chapters 1 - 44
,Chapter 1
1. Various geometric formulas are given in Appendix E.
(a) Expressing the radius of the Earth as
R = (6.37 106 m)(10−3 km m) = 6.37 103 km,
its circumference is s = 2 R = 2 (6.37 103 km) = 4.00 104 km.
(b) The surface area of Earth is A = 4 R2 = 4 ( 6.37 103 km ) = 5.10 108 km2.
2
4 4
( 6.37 103 km )
3
(c) The volume of Earth is V = R3 = = 1.08 1012 km 3 .
3 3
2. The conversion factors are: 1 gry = 1/10 line , 1 line = 1/12 inch and 1 point = 1/72
inch. The factors imply that
1 gry = (1/10)(1/12)(72 points) = 0.60 point.
Thus, 1 gry2 = (0.60 point)2 = 0.36 point2, which means that 0.50 gry 2 = 0.18 point 2 .
3. The metric prefixes (micro, pico, nano, …) are given for ready reference on the inside
front cover of the textbook (see also Table 1–2).
(a) Since 1 km = 1 103 m and 1 m = 1 106 m,
1km = 103 m = (103 m)(106 m m) = 109 m.
The given measurement is 1.0 km (two significant figures), which implies our result
should be written as 1.0 109 m.
(b) We calculate the number of microns in 1 centimeter. Since 1 cm = 10−2 m,
1cm = 10−2 m = (10−2m)(106 m m) = 104 m.
We conclude that the fraction of one centimeter equal to 1.0 m is 1.0 10−4.
(c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m,
1
,
, 2 CHAPTER 1
1.0 yd = (0.91m)(106 m m) = 9.1 105 m.
4. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas = 1 inch, we
obtain 6 picas
0.80 cm = (0.80 cm) 1 inch 1.9 picas.
2.54 cm 1 inch
(b) With 12 points = 1 pica, we have
0.80 cm = (0.80 cm) 1 inch 12 points
6 picas
2.54 cm 1 inch 1 pica 23 points.
5. Given that 1 furlong = 201.168 m , 1 rod = 5.0292 m and 1 chain = 20.117 m , we find
the relevant conversion factors to be
1 rod
1.0 furlong = 201.168 m = (201.168 m ) = 40 rods,
5.0292 m
and
1 chain
1.0 furlong = 201.168 m = (201.168 m ) =10 chains .
20.117 m
Note the cancellation of m (meters), the unwanted unit. Using the given conversion
factors, we find
(a) the distance d in rods to be
40 rods
d = 4.0 furlongs =(4.0 furlongs) = 160 rods,
1 furlong
(b) and that distance in chains to be
10 chains
d = 4.0 furlongs =(4.0 furlongs) = 40 chains.
1 furlong
6. We make use of Table 1-6.
(a) We look at the first (“cahiz”) column: 1 fanega is equivalent to what amount of cahiz?
We note from the already completed part of the table that 1 cahiz equals a dozen fanega.
1
Thus, 1 fanega = 12 cahiz, or 8.33 10−2 cahiz. Similarly, “1 cahiz = 48 cuartilla” (in the
already completed part) implies that 1 cuartilla = 1
48cahiz, or 2.08 10−2 cahiz.
Continuing in this way, the remaining entries in the first column are 6.94 10−3 and
3.4710−3 .
10th Edition By Resnick, Walker and Halliday
Chapters 1 - 44
,Chapter 1
1. Various geometric formulas are given in Appendix E.
(a) Expressing the radius of the Earth as
R = (6.37 106 m)(10−3 km m) = 6.37 103 km,
its circumference is s = 2 R = 2 (6.37 103 km) = 4.00 104 km.
(b) The surface area of Earth is A = 4 R2 = 4 ( 6.37 103 km ) = 5.10 108 km2.
2
4 4
( 6.37 103 km )
3
(c) The volume of Earth is V = R3 = = 1.08 1012 km 3 .
3 3
2. The conversion factors are: 1 gry = 1/10 line , 1 line = 1/12 inch and 1 point = 1/72
inch. The factors imply that
1 gry = (1/10)(1/12)(72 points) = 0.60 point.
Thus, 1 gry2 = (0.60 point)2 = 0.36 point2, which means that 0.50 gry 2 = 0.18 point 2 .
3. The metric prefixes (micro, pico, nano, …) are given for ready reference on the inside
front cover of the textbook (see also Table 1–2).
(a) Since 1 km = 1 103 m and 1 m = 1 106 m,
1km = 103 m = (103 m)(106 m m) = 109 m.
The given measurement is 1.0 km (two significant figures), which implies our result
should be written as 1.0 109 m.
(b) We calculate the number of microns in 1 centimeter. Since 1 cm = 10−2 m,
1cm = 10−2 m = (10−2m)(106 m m) = 104 m.
We conclude that the fraction of one centimeter equal to 1.0 m is 1.0 10−4.
(c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m,
1
,
, 2 CHAPTER 1
1.0 yd = (0.91m)(106 m m) = 9.1 105 m.
4. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas = 1 inch, we
obtain 6 picas
0.80 cm = (0.80 cm) 1 inch 1.9 picas.
2.54 cm 1 inch
(b) With 12 points = 1 pica, we have
0.80 cm = (0.80 cm) 1 inch 12 points
6 picas
2.54 cm 1 inch 1 pica 23 points.
5. Given that 1 furlong = 201.168 m , 1 rod = 5.0292 m and 1 chain = 20.117 m , we find
the relevant conversion factors to be
1 rod
1.0 furlong = 201.168 m = (201.168 m ) = 40 rods,
5.0292 m
and
1 chain
1.0 furlong = 201.168 m = (201.168 m ) =10 chains .
20.117 m
Note the cancellation of m (meters), the unwanted unit. Using the given conversion
factors, we find
(a) the distance d in rods to be
40 rods
d = 4.0 furlongs =(4.0 furlongs) = 160 rods,
1 furlong
(b) and that distance in chains to be
10 chains
d = 4.0 furlongs =(4.0 furlongs) = 40 chains.
1 furlong
6. We make use of Table 1-6.
(a) We look at the first (“cahiz”) column: 1 fanega is equivalent to what amount of cahiz?
We note from the already completed part of the table that 1 cahiz equals a dozen fanega.
1
Thus, 1 fanega = 12 cahiz, or 8.33 10−2 cahiz. Similarly, “1 cahiz = 48 cuartilla” (in the
already completed part) implies that 1 cuartilla = 1
48cahiz, or 2.08 10−2 cahiz.
Continuing in this way, the remaining entries in the first column are 6.94 10−3 and
3.4710−3 .
