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A Solution Manual for An Introduction to M – John Weatherwax | Solution Manual & Study Guide

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A Solution Manual for An Introduction to M by John Weatherwax provides supplementary support for students working through mathematical problems and exercises. It can be useful for reviewing solution methods, strengthening problem-solving skills, checking coursework, and preparing for assignments, quizzes, and examinations.

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Solutions to the Questions in
An Introduction to Mathematical Statistics
and Its Applications
by Richard J. Larsen and Morris L. Marx
John Weatherwax


Text copyright © 2018 John L. Weatherwax
All Rights Reserved
Please Do Not Redistribute Without Permission from the Author
To my family.

Introduction
This is a solution manual all of the questions in the excellent statistical textbook:

An Introduction to Mathematical Statistics and Its Applications
by Richard Larsen and Morris Marx

This solution manual was prepared form the fifth edition of the textbook. I have looked at other editions
of the book and have had a hard time finding any significant differences between the editions.

I’ve tried to provide much more detail than is normally found in a typical solutions manual. Thus rather
than just give the solution I try to explain in great detail how I arrived a the solution. This will further
reinforce the main ideas from class and better teach the material. The manual stands at over 400 pages.

One of the benefits of this manual is that I heavily use the R statistical language to perform any of the
needed numerical computations (rather than do them ”by-hand”). Thus if you use this manual you will be
learning some R programming at the same time as you learn statistics. The R programming language is
one of the most desired skills for anyone who hopes to use data/statistics in their future career. All the R
code can be found at the following location:
http://waxworksmath.com/Authors/G_M/Larsen/larsen.html

As a final comment, I’ve worked hard to make these notes as good as I can, but I have no illusions that
they are perfect. If you feel that that there is a better way to accomplish or explain an exercise or
derivation presented in these notes; or that one or more of the explanations is unclear, incomplete, or
misleading, please tell me. If you find an error of any kind – technical, grammatical, typographical,
whatever – please tell me that, too. I’ll gladly add to the acknowledgments in later printings the name of
the first person to bring each problem to my attention.

Chapter 2 (Probability)
In working some of these questions I have chosen to use R or python to explicitly enumerate the spaces
requested rather than to derive them by hand. While many of these questions could no doubt be done “by
hand” it is very easy to change a problem statement in such a way that will make that impossible. Using a




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computer is a more robust (with respect to problem specification) way to work problems like these and is
a helpful skill to have.

Question 2.2.1


The full sample space in this case would be


Event A would be the set



Event B would be the set



Question 2.2.2


We can use R to enumerate the possible outcomes when we toss three die. We have
D = 1:6
outcomes = expand.grid(D, D, D)
colnames(outcomes) = c(’R’, ’B’, ’G’)
mask = apply(outcomes, 1, sum) == 5
print(outcomes[mask, ])

Running the above we get
> print(outcomes[mask, ])
R B G
3 3 1 1
8 2 2 1
13 1 3 1
38 2 1 2
43 1 2 2
73 1 1 3

for the members of the event A .

Question 2.2.3


We can generate this sample space with the following python code
from itertools import combinations
for it in combinations(range(1, 7), 3):
if sorted(it)[1]==3: print it

Running the above python code gives
(1, 3, 4)
(1, 3, 5)
(1, 3, 6)
(2, 3, 4)
(2, 3, 5)
(2, 3, 6)

for the elements of the sample space.




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Question 2.2.4


We can pick the suit of the first card in four ways. We can pick the number on the first card to be one of
the numbers 1, 2, 3, 4, 5, 6, 7. For all of these choices (excluding 4) the number on the other card required
that the two cards sum to 8 is determined and different than the number on the first card. Ignoring the
choice of the number 4 (for the time being) on the first card we have 7 − 1 = 6 ways to pick the number.
We then have four ways to pick the suit of the second card. This gives


total ways to draw this type of pair.

If we pick the number 4 on the first card the number 4 must be picked on the second card (so the sum is
eight) and we thus can’t select the same suit for the second card as we did on the first card. This means
that the number of ways we can draw two cards that sum two eight in this way is


The total number of ways to pick this type of pairs is the sum of the two above numbers or 96 + 12 = 108.

Question 2.2.5


One would expect that this would have the sum of the two die to be eight and is perhaps the special case
where both die show four.

Question 2.2.6


There are = 1287 ways to draw five cards in the suit of hearts (i.e. a flush). The “straight flushes”
are



of which there are ten such hands. If we let N F be the number of flushes of the form we are interested in
then


Question 2.2.7


This would be the set of triangles that satisfy a 2 + b 2 = 5 2 .

Question 2.2.8


We can generate this sample space using the following python code
from itertools import permutations
for it in permutations(’B B B S S’.split(), 5):
print it

Running the above give the following output (partial)
(’B’, ’B’, ’B’, ’S’, ’S’)
(’B’, ’B’, ’B’, ’S’, ’S’)
(’B’, ’B’, ’S’, ’B’, ’S’)
(’B’, ’B’, ’S’, ’S’, ’B’)




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