Comprehensive Practice Exam & Study Guide
| Updated Questions, Detailed Answers,
Explanations & In-Depth Rationales
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1. A solution is prepared by dissolving 0.50 mol of a
nonelectrolyte solute in 1.50 kg of water. If the vapor
pressure of pure water at a particular temperature is
31.8 mmHg, and the mole fraction of water in the
solution is 0.947, what is the approximate vapor
pressure of the solution?
A. 27.1 mmHg
B. 28.4 mmHg
C. 30.1 mmHg
D. 31.2 mmHg
Rationale: By Raoult’s law, the vapor pressure of a solution
containing a nonvolatile solute is Psolution =
XsolventP°solvent. Thus, P = (0.947)(31.8 mmHg) ≈ 30.1
mmHg. The reduction occurs because fewer water molecules
are present at the liquid surface to escape into the vapor
phase.
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2. A reaction has a rate law of rate = k[A]²[B]. If the
concentration of A is doubled while B remains constant,
by what factor does the reaction rate change?
,A. 2
B. 4
C. 6
D. 8
Rationale: The rate depends on [A]². Doubling A therefore
changes the rate by 2² = 4. The concentration of B has no
effect on this particular change because it remains constant.
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3. Which of the following compounds contains a carbon
atom that is sp-hybridized?
A. CH₄
B. CH₂=CH₂
C. HC≡CH
D. CH₃OH
Rationale: In acetylene, HC≡CH, each carbon participates in a
triple bond and has two regions of electron density, producing
sp hybridization and a linear geometry. CH₄ and CH₃OH
contain tetrahedral sp³ carbons, whereas ethene contains sp²-
hybridized carbons.
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4. A weak acid HA has a pKa of 4.76. A buffer contains
equal concentrations of HA and A⁻. What is the
approximate pH of the buffer?
A. 2.38
B. 4.00
,C. 4.76
D. 9.52
Rationale: The Henderson–Hasselbalch equation is pH = pKa +
log([A⁻]/[HA]). Because the concentrations are equal, their
ratio is 1 and log(1) = 0. Therefore, pH = pKa = 4.76.
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5. Which mechanism most directly explains why enzymes
can dramatically increase reaction rates without
changing the overall ΔG of a reaction?
A. Enzymes increase the equilibrium constant
B. Enzymes increase the energy of reactants
C. Enzymes lower the activation energy
D. Enzymes make products thermodynamically unstable
Rationale: Enzymes provide an alternative reaction pathway
with a lower activation energy. They accelerate both forward
and reverse reactions and therefore do not change the
equilibrium constant or the overall free-energy change
between reactants and products.
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6. A heterozygous individual with genotype AaBb produces
gametes. Assuming independent assortment, what
fraction of gametes are expected to contain both
dominant alleles?
A. 1/16
B. 1/8
, C. 1/4
D. 1/2
Rationale: Independent assortment gives four equally likely
gamete combinations: AB, Ab, aB, and ab. Only AB contains
both dominant alleles, so its probability is 1/4.
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7. During which stage of meiosis do homologous
chromosomes separate while sister chromatids remain
together?
A. Metaphase I
B. Anaphase I
C. Anaphase II
D. Telophase II
Rationale: During anaphase I, homologous chromosome pairs
separate and move toward opposite poles. Sister chromatids
remain attached at their centromeres until anaphase II, when
they finally separate.
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8. A population of cells is exposed to a chemical that
prevents microtubules from attaching to kinetochores.
Which cellular process would be most directly
disrupted?
A. DNA replication
B. RNA transcription
C. Chromosome segregation during mitosis
D. Protein translation