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CEM 141_ Stoichiometry.pdfCEM
141_
141_
Stoichiometry.pdfCEM
Stoichiometry.pdf###########################################################
141_ Stoichiometry.pdf######################################
CEM 141: Stoichiometry
(actual amount produced/ theoretical amount) x 100 - ANS-Percent yield
1. Take initial amount of LR convert to amount of non-LR using molar ratio and get used
2. Subtract this number from the initial amount of the non-LR to get unused - ANS-Determining
un-used amount of non-LR
1. write out balanced equation
2. draw map of where you are starting and how you will get to the end
3. write out calculation w/ units
4. calculate - ANS-General procedure for converting
1) find the atomic mass of the element 2) times that by the coefficient 3) repeat with all other
elements 4) add all together - ANS-How to find molar mass
1) make all elements = on both sides except oxygen 2) count oxygen, if = then good 3) if not,
then double everything and recount oxygens - ANS-How to balance equation
6.022 x 10^23 things/mol - ANS-Avagrado's number
amount of one of the reagents which limits how much of a product can be formed - ANS-Limiting
reactant
compare and predict amount of reactants/products - ANS-Use mass/mol conversion to
do not compare masses directly; use moles instead, the amount of product from each reactant,
smallest = LR - ANS-To calculate LR
formula mass in grams - ANS-The mass of 1 mol of any substance =
is a counting term - ANS-A mole
mass in grams of 1 mole - ANS-Molar mass =
mass is conserved across the reaction - ANS-Balancing equations happens because
molar mass - ANS-Mass A--> Mole A
molar mass and molar ratio - ANS-Mass A --> mole B
molar mass, molar ratio, molar mass - ANS-Mass A --> mass B
######################################################################################!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Q
###########################CEM
CEM 141_ Stoichiometry.pdf##################################################################################
141_ Stoichiometry.pdfCEM 141_ Stoichiometry.pdf######################################
###########################CEM
CEM 141_ Stoichiometry.pdfCEM
141_
141_
Stoichiometry.pdfCEM
Stoichiometry.pdf###########################################################
141_ Stoichiometry.pdf######################################
CEM 141: Stoichiometry
(actual amount produced/ theoretical amount) x 100 - ANS-Percent yield
1. Take initial amount of LR convert to amount of non-LR using molar ratio and get used
2. Subtract this number from the initial amount of the non-LR to get unused - ANS-Determining
un-used amount of non-LR
1. write out balanced equation
2. draw map of where you are starting and how you will get to the end
3. write out calculation w/ units
4. calculate - ANS-General procedure for converting
1) find the atomic mass of the element 2) times that by the coefficient 3) repeat with all other
elements 4) add all together - ANS-How to find molar mass
1) make all elements = on both sides except oxygen 2) count oxygen, if = then good 3) if not,
then double everything and recount oxygens - ANS-How to balance equation
6.022 x 10^23 things/mol - ANS-Avagrado's number
amount of one of the reagents which limits how much of a product can be formed - ANS-Limiting
reactant
compare and predict amount of reactants/products - ANS-Use mass/mol conversion to
do not compare masses directly; use moles instead, the amount of product from each reactant,
smallest = LR - ANS-To calculate LR
formula mass in grams - ANS-The mass of 1 mol of any substance =
is a counting term - ANS-A mole
mass in grams of 1 mole - ANS-Molar mass =
mass is conserved across the reaction - ANS-Balancing equations happens because
molar mass - ANS-Mass A--> Mole A
molar mass and molar ratio - ANS-Mass A --> mole B
molar mass, molar ratio, molar mass - ANS-Mass A --> mass B
######################################################################################!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Q
###########################CEM
CEM 141_ Stoichiometry.pdf##################################################################################
141_ Stoichiometry.pdfCEM 141_ Stoichiometry.pdf######################################
